TÌM x :(1,1.x-9).1/5=40%
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\(\left(1,1.x-9\right).\left|\frac{-1}{5}\right|=40\%\)
\(\left(\frac{11}{10}.x-9\right).\frac{1}{5}=\frac{2}{5}\)
\(\frac{11}{10}.x-9=\frac{2}{5}:\frac{1}{5}\)
\(\frac{11}{10}.x-9=2\)
\(\frac{11}{10}.x=2+9\)
\(\frac{11}{10}.x=11\)
\(x=11:\frac{11}{10}\)
\(x=10\)
\(\left(\frac{11}{10}x-9\right)\times\frac{1}{5}=\frac{2}{5}\)
\(\left(\frac{11}{10}x-9\right)=\frac{2}{5}:\frac{1}{5}\)
\(\left(\frac{11}{10}x-9\right)=2\)
\(\frac{11}{10}x=2+9\)
\(\frac{11}{10}x=11\)
\(x=11:\frac{11}{10}=10\)
a.x+30/100x=-1,1
13/10x=-1,1
x=-11/13
b. (x-1/2):1/3 +5/7=9/5/7
(x-1/2):1/3=9
x-1/2=3
x=7/2
c. -5/6-x=7/12-1/3
x=-5/6-7/12-1/3
x=-7/4
d. 3(x+3)=-15
x+3=-5
x=-8
e. (4,5-2x)(-11/7)=11/14
4,5-2x=11/14:-11/7
4,5-2x=-1/2
2x=4,5+1/2
2x=5
x=5/2
a) \(2\dfrac{4}{9}+6\dfrac{7}{11}+7\dfrac{5}{9}+13\dfrac{4}{11}\)
\(=2+\dfrac{4}{9}+6+\dfrac{7}{11}+7+\dfrac{5}{9}+13+\dfrac{4}{11}\)
\(=\left(2+6+7+13\right)+\left(\dfrac{4}{9}+\dfrac{5}{9}\right)+\left(\dfrac{7}{11}+\dfrac{4}{11}\right)\)
\(=28+1+1\)
\(=30\)
b) \(\dfrac{3}{4}+\dfrac{1}{2}\times\dfrac{12}{5}-1\dfrac{1}{2}\)
\(=\dfrac{3}{4}+\dfrac{1}{2}-1-\dfrac{1}{2}\)
\(=\dfrac{3}{4}-1\)
\(=\dfrac{3}{4}-\dfrac{4}{4}\)
\(=-\dfrac{1}{4}\)
a: =>4/9*a/b=5/27+3/27=8/27
=>a/bb=8/27:4/9=8/27*9/4=72/108=2/3
b: =>9/13*a/b=40/91+1/7=53/91
=>a/b=53/63
`a)4/9xxa/b-1/9=5/27`
`=>4/9xxa/b=5/27+1/9`
`=>4/9xxa/b=5/27+3/27`
`=>4/9xxa/b=8/27`
`=>a/b=8/27:4/9`
`=>a/b=8/27xx9/4`
`=>a/b=2/3`
Vậy `a=2` và `b=3`
__
`b)9/13xxa/b+1/7=40/91`
`=>9/13xxa/b=40/91-1/7`
`=>9/13xxa/b=40/91-13/91`
`=>9/13xxa/b=27/91`
`=>a/b=27/91:9/13`
`=>a/b=27/91xx13/9`
`=>a/b=39/91`
Vậy `a=39` và `b=91`
a) \(\text{}/3x-5/-\frac{1}{7}=\frac{1}{3}\) b)\(\left(\frac{3}{5}x-\frac{2}{3}x-x\right).\frac{1}{7}=\frac{-5}{21}\)
\(/3x-5/=\frac{10}{21}\) \([x.\left(\frac{3}{5}-\frac{2}{3}-1\right)]=\frac{-5}{21}.7\)
\(\Rightarrow3x-5=\frac{10}{21}hay3x-5=\frac{-10}{21}\) \(\left[x.\frac{-16}{15}\right]=\frac{-5}{3}\)
\(3x=\frac{115}{21}\) \(3x=\frac{95}{21}\) \(x=\frac{25}{16}\)
\(x=\frac{115}{63}\) \(x=\frac{95}{63}\) Vậy x = \(\frac{25}{16}\)
Vậy x \(\in\left\{\frac{115}{63};\frac{95}{63}\right\}\)
Bài 1:
a: \(\Leftrightarrow\dfrac{6}{7}\left(\dfrac{7}{12}x-\dfrac{14}{3}\right)=\dfrac{5}{9}-\dfrac{9}{8}=\dfrac{-41}{72}\)
\(\Leftrightarrow x\cdot\dfrac{7}{12}-\dfrac{14}{3}=-\dfrac{287}{432}\)
\(\Leftrightarrow x\cdot\dfrac{7}{12}=\dfrac{1729}{432}\)
hay \(x=\dfrac{247}{36}\)
b: \(\Leftrightarrow\dfrac{1}{5}:x=\dfrac{1}{5}+\dfrac{3}{14}-\dfrac{8}{7}=\dfrac{-51}{70}\)
hay \(x=-\dfrac{14}{51}\)
c: đề sai rồi bạn
\(x:\left(1,1x-9\right).\frac{1}{5}=40\%\)
\(x:\left(1,1x-9\right)=2\)
\(x=2.\left(1,1x-9\right)\)
\(x=2,2x-18\)
\(-1,2x=-18\)
\(x=15\)
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