1235 × 6789 × ( 630 - 315 ×2 ) ÷ 1996
Cần giải gấp
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k) 4 x 113 x 25 - 5 x 112 x 20
= (4 x 25) x 113 - (5 x 20) x 112
= 100 x 113 - 100 x 112
= 100 x (113 - 112)
= 100
p) 1235 x 6789 x (630 - 315 x 2) : 1996
= 1235 x 6789 x (630 - 630) : 1996
= 1235 x 6789 x 0 : 1996
= 0
l) 54 x 113 + 45 x 113 + 113
= 113 (54 + 45 + 1)
= 113 x 100
= 11300
u) (500 x 9 - 250 x 18) x (1 + 2 + 3 + ... + 9)
= (2 x 250 x 9 - 250 x 2 x 9) x (1 +2 + 3 + ... + 9)
= 0 x (1 + 2 + 3 + ... + 9)
= 0
\(1235\text{×}6789\text{×}\left(630-315\text{×}2\right)\)
\(=1235\text{×}6789\text{×}\left(630-630\right)\)
\(=1235\text{×}6789\text{×}0=0\)
\(\left(100+67\right)\text{×}67+\left(200-38\right)\text{×}33\)
\(=167\text{×}67+167\text{×}33\)
\(=167\text{×}\left(67+33\right)\)
\(=167\text{×}100=16700\)
\(72+36\text{×}2+24\text{×}3+18\text{×}4+12\text{×}2+168\)
\(=72+72+72+72+24+168\)
\(=\left(72\text{×}4\right)+24+168=288+24+168=480\)
`@` `\text {Ans}`
`\downarrow`
`a,`
\(\text{326 x 728 + 327 x 272}\)
`= 326 \times 728 + 326 \times 272 + 272`
`= 326 \times (728 + 272) + 272`
`= 326 \times 1000 + 272`
`= 362000 + 272`
`= 362272`
`b,`
\(\text{2008 x 867 + 2009 x 133}\)
`= 2008 \times 867 + 2008 \times 133 + 133`
`= 2008 \times (867 + 133) + 133`
`= 2008 \times 1000 + 133`
`= 2008000 + 133`
`= 2008133`
`c,`
\(\text{1235 x 6789 x (630 - 315 x 2 )}\)
`= 1235 \times 6789 \times (630 - 630)`
`= 1235 \times 6789 \times 0`
`= 0`
`d,`
\((m \div 1 - m \times 1 ) \div ( m \times 2008 + m + 2008)\)
`= (m - m) \div (m \times 2008 + m + 2008)`
`= 0 \div (m \times 2008 + m + 2008)`
`= 0`
a: =326*728+326*272+272
=326000+272
=326272
c: \(=1235\cdot6789\cdot\left(630-630\right)=0\)
d: \(=\left(m-m\right):\left(20009m+2008\right)=0\)
a.326.728+327.272
=326.728+326.272+272
=326.(728+272) +272
=326.1000 +272
=326000+272
=326272
B, 1235.6789.(630-315.2)
=1235.6789.(630- 630)
=1235.6789.0
=0
C, 2008.867+2009.133
=2008.867+2008.133 +133
=2008.(867+133)+133
=2008.1000 +133
=2008000+133
=2008133
D, (m:1-m*1) : (m*2008+m+2008)
= (m-m) : (m*2008+m+2008)
= 0 : (m*2008+m+2008)
=0
(x-5) x ( 1995 x 196 + 1997 x 1996) = 0
x-5 = 0 : ( 1995 x 196 + 1997 x 1996)
x-5 = 0
x= 0+5
x= 5
(x-5)(1995.1996+1997.1996)=1234.5678.(630-315.2):1996
VP=1234.5678(630-315.2):196
=0
=> (x-5)(1995.1996+1997.1996)=0
=> x-5=0 vì (1995.1996+1997.1996 khác 0)
=> x=5
1235x6789x(630-630):1996
= 1235x6789x0:1996
=0
1235 x 6789 x (630 - 315 x 2) : 1996
=1235x6789x(630-630):1996
=1235x6789x0:1996
=0