2.RÚT GỌN RỒI TÍNH.
\(\frac{24}{36}\)- \(\frac{6}{18}\)
\(\frac{18}{27}\)-\(\frac{2}{6}\)
\(\frac{2}{15}\)-\(\frac{5}{35}\)
\(\frac{15}{25}\)- \(\frac{3}{21}\)
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\(\frac{8}{5}-\frac{18}{27}\)
\(=\frac{8}{5}-\frac{2}{3}\)
\(=\frac{24}{15}-\frac{10}{15}\)
\(=\frac{14}{15}\)
\(\frac{12}{20}-\frac{6}{18}\)
\(=\frac{3}{5}-\frac{1}{3}\)
\(=\frac{9}{15}-\frac{5}{15}\)
\(=\frac{4}{15}\)
\(\frac{8}{24}-\frac{5}{25}\)
\(=\frac{1}{3}-\frac{1}{5}\)
\(=\frac{5}{15}-\frac{3}{15}\)
\(=\frac{2}{15}\)
\(\frac{18}{21}-\frac{12}{27}\)
\(=\frac{6}{7}-\frac{4}{9}\)
\(=\frac{54}{63}-\frac{28}{63}\)
\(=\frac{26}{63}\)
1)8/5-2/3=14/15
2)3/5-1/3=4/15
3)1/3-1/5=2/15
4)6/7-4/9=26/63
\(\frac{18}{24}=\frac{18:6}{24:6}=\frac{3}{4}\)
\(\frac{15}{25}=\frac{15:5}{25:5}=\frac{3}{5}\)
\(\frac{3}{4}>\frac{3}{5}\) vì cùng bằng tử số, mẫu số của phân số nào lớn thì nhỏ hơn
2) a) \(\frac{24}{32}=\frac{3}{4}\)
\(\frac{9}{21}=\frac{3}{7}\) \(\Rightarrow\frac{3}{4}>\frac{3}{7}\) ( giải thích tương tự như trên)
những câu sau tương tự
Bài 1
\(\frac{18}{24}=\frac{18:6}{24:6}=\frac{3}{4}\)
\(\frac{15}{25}=\frac{15:5}{25:5}=\frac{3}{5}\)
Vì 4 < 5 => \(\frac{3}{4}>\frac{3}{5}\)( Cùng tử, mẫu số nào nhỏ hơn thì p.s đó lớn hơn )
=> \(\frac{18}{24}>\frac{15}{25}\)
Bài 2.
a) \(\frac{24}{32}\)và \(\frac{9}{21}\)
\(\frac{24}{32}=\frac{24:8}{32:8}=\frac{3}{4}\); \(\frac{9}{21}=\frac{9:3}{21:3}=\frac{3}{7}\)
Vì 4 < 7 => \(\frac{3}{4}>\frac{3}{7}\)=> \(\frac{24}{32}>\frac{9}{21}\)
\(\frac{15}{25}\)và \(\frac{12}{15}\)
\(\frac{15}{25}=\frac{15:5}{25:5}=\frac{3}{5}\); \(\frac{12}{15}=\frac{12:3}{15:3}=\frac{4}{5}\)
Vì 3 < 4 => \(\frac{3}{5}< \frac{4}{5}\)=> \(\frac{15}{25}< \frac{12}{15}\)
b) \(\frac{5}{6}\)và \(\frac{6}{5}\)
Ta có : \(\frac{5}{6}< 1< \frac{6}{5}\)
=> \(\frac{5}{6}< \frac{6}{5}\)
\(\frac{7}{5}\)và \(\frac{5}{3}\)
Quy đồng mẫu số ta được : \(\frac{7}{5}=\frac{7\cdot3}{5\cdot3}=\frac{21}{15}\); \(\frac{5}{3}=\frac{5\cdot5}{3\cdot5}=\frac{25}{15}\)
Vì 21 < 25 => \(\frac{21}{15}< \frac{25}{15}\)=> \(\frac{7}{5}< \frac{5}{3}\)
\(a.=\frac{3}{15}+\frac{-10}{15}\)
\(=-\frac{7}{15}\)
\(b.=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)
\(=1+\left(-1\right)\)
\(=0\)
\(c.=\left(\frac{13}{25}-\frac{38}{25}\right)+\left(\frac{6}{41}+\frac{35}{41}\right)-\frac{1}{2}\)
\(=-1+1-\frac{1}{2}\)
\(=0-\frac{1}{2}\)
\(=-\frac{1}{2}\)
\(d.=\frac{5}{6}.\left(18\frac{2}{3}-6\frac{2}{3}\right)\)
\(=\frac{5}{6}.12\)
\(=10\)
#)Giải :
Câu 1 :
Đặt \(A=\frac{1}{20}+\frac{1}{21}+\frac{1}{22}+...+\frac{1}{27}\)
\(\Rightarrow A>\frac{1}{27}+\frac{1}{27}+...+\frac{1}{27}\)( 8 số hạng )
\(\Rightarrow A>\frac{8}{27}=\frac{8}{27}\)
\(\Rightarrow A>\frac{8}{27}\)
#~Will~be~Pens~#
Câu 1:(trội)
Ta có:\(\frac{1}{20}+\frac{1}{21}+...+\frac{1}{27}>\frac{1}{27}+\frac{1}{27}+...+\frac{1}{27}=\frac{8}{27}\left(đpcm\right)\)
Câu 2:\(D=\frac{2^{25}.3^{15}+3^{15}.5.2^{26}}{2^{25}.3^{17}+3^{15}.2^{25}}=\frac{2^{25}3^{15}\left(1+5.2\right)}{2^{25}3^{15}\left(3^2+1\right)}=\frac{11}{10}\)
b) \(\frac{36^7}{2^{15}.27^5}=\frac{\left(2^2.3^2\right)^7}{2^{15}.\left(3^3\right)^5}=\frac{2^{14}.3^{14}}{2^{15}.3^{15}}=\frac{1.1}{2.3}=\frac{1}{6}\)
h) \(\frac{2^{18}.9^4}{6^6.8^4}=\frac{2^{18}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^4}=\frac{2^{18}.3^8}{2^6.3^6.2^{12}}=\frac{2^{18}.3^8}{2^{18}.3^6}=\frac{1.3^2}{1.1}=9\)
o) \(\frac{3^3+3.6^2+6^3}{13}=\frac{3^3+6^2\left(3+6\right)}{13}=\frac{3^3+6^2.3^2}{13}\)
\(=\frac{3^2\left(3+6^2\right)}{13}=\frac{9.3.13}{13}=\frac{9.3.1}{1}=27\)
câu 1: 0
\(\frac{24}{36}\)