52 + 35 =
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1 < 2
3 > 1
3 < 4
3 = 3
5 > 2
5 > 4
2 < 3
1 < 5
4 > 1
4 = 4
4 > 3
5 = 5
2 < 3
3 < 5
1 < 4
3 > 1
Ta có: 35=1(mod 17)
=>3535=135(mod 17)
=>3535=1 (mod 17)
Ta có: 52=1(mod 17)
=>5252 = 152(mod 17)
=>5252=1(mod 17)
=>3535+5252-2=1+1-2 (mod 17)
=>A=0 (mod 17)
=>A chia hết cho 17 (đpcm)
1. \(-\dfrac{52}{17}+\left(\dfrac{12}{19}+\dfrac{52}{17}\right)=\left[\left(-\dfrac{52}{17}\right)+\left(-\dfrac{52}{17}\right)\right]+\dfrac{12}{19}=\dfrac{12}{19}\)
2. \(\dfrac{21}{35}+\left(-1+\dfrac{14}{35}\right)=\dfrac{3}{5}+\left(-1+\dfrac{2}{5}\right)=\left(\dfrac{3}{5}+\dfrac{2}{5}\right)+\left(-1\right)=1-1=0\)
1. \(\frac{-52}{17}+\left(\frac{12}{19}+\frac{52}{17}\right)=\frac{-52}{17}+\frac{12}{19}+\frac{52}{17}\)\(=\left(\frac{-52}{17}+\frac{52}{17}\right)+\frac{12}{19}=\frac{0}{17}+\frac{12}{19}=\frac{12}{19}\)
2. \(\frac{21}{35}+\left(-1+\frac{14}{35}\right)=\frac{21}{35}-1+\frac{14}{35}=\left(\frac{21}{35}+\frac{14}{35}\right)-1=1-1=0\)
a) -( -35 + 7 - 13 ) + ( 2 - 35 ) - ( 13 - 7 )
= 35 - 7 + 13 + 2 - 35 - 13 + 7
= ( 35 - 35 ) + ( -7 + 7 ) + ( 13 - 13 ) + 2
= 0 + 0 + 0 + 2
= 2
b) ( 70 + 8 - 35 ) - ( 8 - 37 - 10 ) - 70
= 70 + 8 - 35 - 8 + 37 + 10 - 70
= ( 70 - 70 ) + ( 8 - 8 ) + ( -35 + 37 ) + 10
= 0 + 0 + 2 + 10
= 12
c) 5 - ( 14 + 4 - 52 ) - ( 52 - 14 ) + 4
= 5 - 14 - 4 + 52 - 52 + 14 + 4
= 5 - ( 14 + 14 ) + ( 52 - 52 ) + ( -14 + 14 )
= 5 - 14 - 14 + 0 + 0
= 5 - ( 14 - 14 )
= 5 - 0
= 5
52 = 37
7 = 5 + 2
3 = 5 - 2
41 = 4 + 1 = 5
4 - 1 = 3
35 = 28
5 + 3= 8
5 - 3 = 2
25 = x
2+ 5 = 7
5 - 2 = 3
x = 37
100:{2.[52-(35-8)]}
=100:{2.[52-27]}
=100:{2.25}
=100:50
=2
52 + 35 = 87
= 87
tk nha