1.Tìm x:
18 - 2 . (x - 11) = -40
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a) \(12+x+\left(-5\right)=-18-2x\)
\(\Rightarrow12+x-5=-18-2x\)
\(\Rightarrow x+7+18+2x=0\)
\(\Rightarrow3x=-25\)
\(\Rightarrow x=-\dfrac{25}{3}\)
b) \(\left(-14\right)-x+\left(-15\right)=-10+\left(4-2x\right)\)
\(\Rightarrow-14-x-15=-10+4-2x\)
\(\Rightarrow-x-29=-2x-6\)
\(\Rightarrow-x+2x=-6+29\)
\(\Rightarrow x=23\)
c) \(x-\left(-19\right)-\left(-11\right)=-\left(3x+40\right)\)
\(\Rightarrow x+19+11=-3x-40\)
\(\Rightarrow x+30=-3x-40\)
\(\Rightarrow x+3x=-40-30\)
\(\Rightarrow4x=-70\)
\(\Rightarrow x=-\dfrac{35}{2}\)
\(\left(x-5\right)^2=\left(18\dfrac{1}{3}:5\right).\dfrac{11}{3}\)
\(\Leftrightarrow\left(x-5\right)^2=\dfrac{55}{3}.\dfrac{1}{5}.\dfrac{11}{3}\)
\(\Leftrightarrow\left(x-5\right)^2=\dfrac{121}{9}\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=\dfrac{11}{3}\\x-5=-\dfrac{11}{3}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{26}{3}\\x=\dfrac{4}{3}\end{matrix}\right.\)
Câu 1 : \(\frac{x+2}{18}+\frac{x+2}{19}+\frac{x+2}{20}=\frac{x+2}{21}+\frac{x+2}{22}\)
=> \(\frac{x+2}{18}+\frac{x+2}{19}+\frac{x+2}{20}-\frac{x+2}{21}-\frac{x+2}{22}=0\)
=> x+2 . ( \(\frac{1}{18}+\frac{1}{19}+\frac{1}{20}-\frac{1}{21}-\frac{1}{22}\)) = 0
Vì \(\frac{1}{18}+\frac{1}{19}_{ }+\frac{1}{20}-\frac{1}{21}-\frac{1}{22}\ne0\)nên x+2=0
=> x= 0 - 2 = -2
Vậy x = -2
\(\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+....+\frac{2}{x\left(x+1\right)}=\frac{11}{40}\)
\(\Leftrightarrow\frac{2}{30}+\frac{2}{42}+\frac{2}{56}+....+\frac{2}{x\left(x+1\right)}=\frac{11}{40}\)
\(\Leftrightarrow\frac{2}{5.6}+\frac{2}{6.7}+\frac{2}{7.8}+....+\frac{2}{x\left(x+1\right)}=\frac{11}{40}\)
\(\Leftrightarrow2\left(\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+....+\frac{1}{x}-\frac{1}{x+1}\right)=\frac{11}{40}\)
\(\Leftrightarrow\frac{1}{5}-\frac{1}{x+1}=\frac{11}{40}\div2\)
\(\Leftrightarrow\frac{1}{x+1}=\frac{1}{5}-\frac{11}{80}\)
\(\Leftrightarrow\frac{1}{x+1}=\frac{1}{16}\Rightarrow x=16-1=15\)
1: x=3/4-1/2=3/4-2/4=1/4
2: x-1/5=2/11
=>x=2/11+1/5=21/55
3: x-5/6=16/42-8/56
=>x-5/6=8/21-4/28=5/21
=>x=5/21+5/6=15/14
4: x/5=5/6-19/30
=>x/5=25/30-19/30=6/30=1/5
=>x=1
5: =>|x|=1/3+1/4=7/12
=>x=7/12 hoặc x=-7/12
6: x=-1/2+3/4
=>x=3/4-1/2=1/4
11: x-(-6/12)=9/48
=>x+1/2=3/16
=>x=3/16-1/2=-5/16
1)x= 1/4
2)x= 2/11+ 1/5
x= 21/55
3)x - 5/6 = 5/21
x = 5/21+5/6
x = 15/14
4)x/5 = 5/6 + -19/30
x:5 = 1/5
x = 1/5.5
x = 1
5) |x| - 1/4 = 6/18
|x| = 6/18 - 1/4
|x| =7/12
⇒x= 7/12 hoặc -7/12
6)x = -1/2 +3/4
x= 1/4
7) x/15 = 3/5 + -2/3
x:15 = -1/15
x = -1/15. 15
x = -1
8)11/8 + 13/6 = 85/x
85/24 = 85/x
⇒ x = 24
9) x - 7/8 = 13/12
x = 13/12 + 7/8
x = 47/24
10)x - -6/15 = 4/27
x = 4/27 + (-6/15)
x = -34/135
11) -(-6/12)+x = 9/48
x= 9/48 - 6/12
x = -5/16
12) x - 4/6 = 5/25 + -7/15
x -4/6 = -4/15
x = -4/15 + 4/6
x = 2/5
a)x-160:40=45
x-4=45
x=45+4
x=49
b)(x+45):15=80
x+45=80.15
x+45=1200
x=1155
c)x-50:25=8
x-5=8
x=13
d)5.x-38:19=13
5x-2=13
5x=15
x=3
d)(5x-38):19=13
5x-38=247
5x=285
x=57
e)(3x-18)(2x-20)=0
\(\Rightarrow\left[\begin{array}{nghiempt}3x-18=0\\2x-20=0\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}3x=18\\2x=20\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=6\\x=10\end{array}\right.\)
Vậy x=6;10
g)Gọi số tự nhiên thứ nhất là a
số tự nhiên thứ hai là b
Vì lấy số lớn chia số nhỏ đc thương là 9 và dư là 11
Mà a+b=361
a=361-b
Suy ra:(11+a):b=9
Ta có:(11+a):b=9
(11+361-b):b=9
(372-b):b=9
372:b-1=9
372:b=10
b=372:10
b ko TM
Xem lại đề
x - 160 : 40 = 45
x - 4 = 45
x = 45 + 4
x = 49
Vậy x = 49
(x + 45 ):15 = 80
x + 45 = 80.15
x + 45 = 1000
x = 1000 - 45
x = 955
Vậy x = 995
x - 50:25 = 8
x - 2 = 8
x = 8 + 2
x = 10
Vậy x = 10
5.x - 38:19 = 13
5.x - 2 = 13
5.x = 13 + 2
x = 15:5
x = 3
Vậy x = 3
( 5.x - 38 ):19 = 13
5.x - 38 = 13.19
5.x - 38 = 247
5.x = 247 + 38
5.x = 285
x = 285:5
x = 57
Vậy x = 57
( 3x - 18 ).( 2x - 20 ) = 0
3x - 18 = 0 hoặc 2x - 20 = 0
+) 3x - 18 = 0
3x = 18
x = 6
+) 2x - 20 =0
2x = 20
x = 10
Vậy x = 6 hoăc x = 10
18 - 2.(x-11)= -40
2x-22=18-(-40)
2x - 22 = 18+40
2x = 58 + 22
x = 80 :2
x=40
k mình nhé mình làm xong đầu tiên, kết quả đúng 100%