thực hiện phép tính
a, 4x52-18:32
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\(a.\sqrt{\left(\sqrt{2}-\sqrt{3}\right)^2}+\sqrt{18}=\left|\sqrt{2}-\sqrt{3}\right|+3\sqrt{2}=\sqrt{3}-\sqrt{2}+3\sqrt{2}\left(\sqrt{3}>\sqrt{2}\right)=\sqrt{3}+2\sqrt{2}\)\(b.3\sqrt{2}-4\sqrt{18}+2\sqrt{32}-\sqrt{50}=3\sqrt{2}-12\sqrt{2}+8\sqrt{2}-5\sqrt{2}=-6\sqrt{2}\)
a: \(=\sqrt{3}-\sqrt{2}+3\sqrt{2}=2\sqrt{2}+\sqrt{3}\)
\(98.42-50\left[\left(18-2^3\right):2+3^2\right]\\ =4116-50\left[\left(18-8\right):2+9\right]\\ =4116-50\left[10:2+9\right]\\ =4116-50\left[5+9\right]\\ =4116-50.14\\ =4116-700\\ =3416\)
98.42-50.[(18-23):2 +32]
=98.42-50.[(18-8):2+32]
=98.42-50.[10:2+3]
=98.42-50.[5+3]
=98.42-50.8
= 4116-400
=3716
a, 5 . 2 2 - 18 : 3 2
= 5.4 – 18:9
= 20 – 2 = 18
b, 17.85+15.17 – 120
= 1445+255 – 120
= 1580
c, 2 3 . 17 - 2 3 . 14
= 2 3 . ( 17 - 14 ) = 8.3 = 24
d, 20 – [30 – 5 - 1 2 ]
= 20 – (30 – 16) = 6
a)\(\left(-3\right).8.\left(-2\right).5=\left(-3\right).\left(-2\right).8.5\)
\(=6.40=240\)
b)\(127-18.\left(5+6\right)=127-18.11\)
\(=127-198=-71\)
c)\(125-\left(-75\right)+32-\left(48+32\right)=125+75+32-48-32\)
\(\left(125+75\right)+\left(32-32\right)-48=200-48=152\)
d)\(3.\left(-4\right).2+2.\left(-5\right)-20=-12.2+2.\left(-5\right)-20\)
\(=\left(-12-5\right).2-20=-17.2-20=-140-20=-160\)
Chúc bạn học tốt
\(\frac{9}{18}-\frac{-7}{12}+\frac{13}{32}\)
\(=\frac{1}{2}+\frac{7}{12}+\frac{13}{32}\)
\(=\frac{6}{12}+\frac{7}{12}+\frac{13}{32}\)
\(=\)\(\frac{13}{12}+\frac{13}{32}\)
\(=\frac{143}{96}\)
5.42 – 18 : 32
= 5.16 – 18 : 9 = 80 – 2 = 78
Phân tích ra thừa số nguyên tố: 78 = 2.39 = 2.3.13
a) 9/18 - (-7/12) + 13/32
= 13/12 + 13/32
= 143/96
b) (5/-8) + 14/25 - 6/10
= (-13/200) - 6/10
= -133/200
Chúc bạn học tốt!! ^^
a: \(\dfrac{9}{18}-\dfrac{-7}{12}+\dfrac{13}{32}\)
\(=\dfrac{1}{2}+\dfrac{7}{12}+\dfrac{13}{32}\)
\(=\dfrac{48}{96}+\dfrac{56}{96}+\dfrac{39}{96}\)
\(=\dfrac{143}{96}\)
b: \(\dfrac{-5}{8}+\dfrac{14}{25}-\dfrac{6}{10}\)
\(=\dfrac{-125}{200}+\dfrac{112}{200}-\dfrac{120}{200}\)
\(=\dfrac{-133}{200}\)
4 x 52 - 18 : 32
= 208 - 9/16
= 3319/16
Lời giải:
$4\times 52-18:21=208-\frac{6}{7}=\frac{1450}{7}$