Thực hiện phép tính bằng cách hợp lí :
1 - 3 + 5 - 7 + 9 - 11 + ... + 17 - 19
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b)
\(=\frac{3}{7}\left(\frac{9}{11}+\frac{2}{11}\right)\)
\(=\frac{3}{7}.1=\frac{3}{7}\)
A) 11/125+(-17/18+4/9)-(5/7-17/14)
=11/125+(-17/18+8/18)-(10/14-17/14)
=11/125+(-1/2)-(-1/2)
=11/125
`a)3/5+(-4/9)`
`=3/5-4/9`
`=27/45-20/45`
`=7/45`
`b)3/5+2/5 . 15/8`
`=3/5 + 30/40`
`=3/5+3/4`
`=12/20+15/20`
`=27/20`
`c)7/2 . 8/13 + 8/13 . (-5/2)`
`=8/13 . (7/2 +(-5)/2)`
`=8/13 . 1`
`=8/13`
`d)-5/17 . (-9/23)+9/23 . (-22/17) + 11 9/23`
`=-5/17 . (-9/23) + 9/23 . (-1) . 22/17 + 11 + 9/23`
`=-5/17 . (-9/23) + (-9/23) . 22/17+11+9/23`
`= -9/23 ( -5/17 + 22/17)+11+9/23`
`= - 9/23 . 1+11+9/23`
`=-9/23+11+9/23`
`=(-9/23+9/23)+11`
`=0+11`
`=11`
a: =27/45-20/45=7/45
b: =3/5+30/40
=3/5+3/4
=12/20+15/20
=27/20
c: =8/13(7/2-5/2+1)=8/13*2=16/13
d: =9/23*5/17-9/23*22/17+11+9/23
=-9/23+11+9/23
=11
\(-\frac{3}{5}.\frac{11}{7}+\frac{3}{-5}.\frac{4}{7}+\frac{23}{7}\)
\(=\frac{-3}{5}\left(\frac{11}{7}+\frac{4}{7}\right)+\frac{23}{7}\)
\(=\frac{-3}{5}.\frac{15}{7}+\frac{23}{7}\)
\(=\frac{-9}{7}+\frac{23}{7}=2\)
(\(\dfrac{9}{25}\) - 2.18) : (\(\dfrac{19}{5}\) + 0,2)
=(\(\dfrac{9}{25}\) - 2.18) : (\(\dfrac{19}{5}\) +\(\dfrac{1}{5}\) )
=(\(\dfrac{9}{25}\)- 36) : 4
=\(\dfrac{-117}{5}\) : 4
= \(\dfrac{-117}{20}\)
(\(\dfrac{9}{25}\)-2.18) : (\(\dfrac{19}{5}\) +0,2)
= (\(\dfrac{9}{25}\)- 2.18) : (\(\dfrac{19}{5}\)+\(\dfrac{1}{5}\))
= (\(\dfrac{9}{25}\)-36): 4
= \(\dfrac{-891}{25}\):4
=\(\dfrac{-891}{100}\)
13 - 12 + 11 + 10 - 9 + 8 - 7 - 6 + 5 - 4 + 3 + 2 - 1
= 1 + 11 - 1 + 1 + 11 - 7 + 1
= 12 - 1 + 1 + 11 - 7 + 1
= 11 + 1 + 11 - 7 + 1
= 12 + 11 - 7 + 1
= 23 - 7 + 1
= 16 + 1
=17
(1-3)+(5-7)+(9-11)+....+(17-19)
=(-2)+(-2)+(-2)+...+(-2)
=(-2)x5
=-10