a) (x + 1)2 =9
b) (7x - 4)3 = 25 . 52 + 200
help my
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1)
a) 2x + 5 = 3⁴ : 3²
2x + 5 = 3²
2x + 5 = 9
2x = 9 - 5
2x = 4
x = 4 : 2
x = 2
b) (3x - 24).73 = 2.74
(3x - 24).73 = 148
3x - 24 = 148/73
3x = 148/73 + 24
3x = 1900/73
x = 1900/73 : 3
x = 1900/219
c) [3.(42 - x)] + 15 = 23.3
126 - 3x + 15 = 69
141 - 3x = 69
3x = 141 - 69
3x = 72
x = 72 : 3
x = 24
d) 126 + (132 - x) = 300
132 - x = 300 - 126
132 - x = 174
x = 132 - 174
x = -42
2)
a) 120 - (x + 55) = 60
x + 55 = 120 - 60
x + 155 = 60
x = 60 - 55
x = 5
b) (7x - 11).3 = 25.52 + 200
(7x - 11).3 = 1500
7x - 11 = 1500 : 3
7x - 11 = 500
7x = 500 + 11
7x = 511
x = 511 : 7
x = 73
c) 2x + 2x + 4 = 544
4x = 544 - 4
4x = 540
x = 540 : 4
x = 135
X=0
Vì 2 mũ 5 = 32
2 mũ 2 = 4
Suy ra 2 mũ 5 + 2 mũ 2 +200 = 32+4+200=236
* ước của 236 = (1;2;4;59;118;236)
* Mà chỉ có 59+11=70 có chữ số đầu tiên là 7
ĐÚNG THÌ TICK CHO MÌNH NHA
\(\left(7x-11\right)^3=2^5\cdot5^2+200\cdot2023^0\\ \left(7x-11\right)^3=32\cdot25+200\cdot1\\ \left(7x-11\right)^3=1000\\ \left(7x-11\right)^3=10^3\\ 7x-11=10\\ 7x=21\\ x=\dfrac{21}{7}=3\)
Lời giải:
$(7x-11)^3=2^5.5^2+200.2023^0=32.25+200=1000=10^3$
$\Rightarrow 7x-11=10$
$\Rightarrow 7x=21$
$\Rightarrow x=3$
a, 7*(x-3) + 4 = 18
<=> 7*(x+3) = 14
<=> x+3=2
<=> x= -1
b, ( 7x - 11)3 =825
<=> 7x - 11=\(\sqrt[3]{825}\)
<=> x=\(\frac{\sqrt[3]{825}+11}{7}\) (loại)
a) 150 : [17 - (2x - 3)] = 350
=> 17 - (2x - 3) = \(\frac{150}{350}=\frac{3}{7}\)
=> 2x - 3 = \(17-\frac{3}{7}=\frac{116}{7}\)
=> 2x = \(\frac{116}{7}+3\)
=> 2x = \(\frac{137}{7}\)
=> x = \(\frac{137}{7}:2=\frac{137}{14}\)
b) 4 . [105 - (x - 9)] - 486 = 0
=> 4. [105 - (x - 9)] = 486
=> 105 - (x - 9) = 243/2
=> x - 9 = \(105-\frac{243}{2}=-\frac{33}{2}\)
=> x = \(-\frac{33}{2}+9=-\frac{15}{2}\)
c) 1000 - 2{600 - 4.[198 - 7.(21 - 7)]}.x = 200
=> 1000 - 2{600 - 4.[198 - 7.14]}.x = 200
=> 1000 - 2{600 - 4.[198 - 98].x = 200
=> 1000 - 2{600 - 4.100}.x = 200
=> 1000 - 2{600 -400}.x = 200
=> 1000 - 2.200.x = 200
=> 2.200.x = 800
=> 400.x = 800
=> x = 2
Câu 2 :
a) 350 : [19 - (7x - 3)] = 350
=> 19 - (7x - 3) = 1
=> 7x - 3 = 18
=> 7x = 21
=> x = 3
b) 7.[109 - (x - 9)] - 420 = 0
=> 7.[109 - (x - 9)] = 420
=> 109 - (x - 9) = 60
=> x - 9 = 49
=> x = 49 + 9 = 58
c) 254 - 2{200 - 4.[90 - 7.(19 - 9)]}.x = 54
=> 254 - 2{200 - 4.[90 - 7.10]}.x = 54
=> 254 - 2{200 - 4[90 - 70]} . x= 54
=> 254 - 2{200 - 4.20} . x = 54
=> 254 - 2{200 - 80}.x = 54
=> 254 - 2.120 . x= 54
=> 2.120.x = 200
=> 240.x = 200
=> \(x=\frac{5}{6}\)
a) = (x+3).(x-3)^2-(x-3)(x+3)^2
=(x^2-9)(x-3)-(x^2-9)(x+3)
=(x^2-9)(x-3-x-3)
=-6(x^2-9)
các câu còn lại tương tự
\(a,\left(x+3\right)\left(x^2-3x+9\right)-\left(x-3\right)\left(x^2+3x+9\right)\)
\(=x^3+3-\left(x^3-3\right)\)
\(=x^3+3-x^3+3\)
\(=6\)
\(b,\left(x-5\right)\left(x^2+5x+25\right)-\left(x+5\right)\left(x^2-5x+25\right)\)
\(=x^3-5^3-x^3-5^3\)
\(=-125-125\)
\(=-250\)
\(\text{a)}350:\left[19-\left(7x-3\right)\right]=350\)
\(\Rightarrow19-\left(7x-3\right)=1\)
\(\Rightarrow19-7x+3=1\)
\(\Rightarrow-7x=-21\)
\(\Rightarrow x=3\)
\(\text{b)}7.\left[109-\left(x-9\right)\right]-420=0\)
\(\Rightarrow7\left(109-x+9\right)=420\)
\(\Rightarrow118-x=60\)
\(\Rightarrow x=58\)
\(\text{c)}252-2\left\{200-4\left[90-7.\left(19-9\right)\right]\right\}.x=4\)
\(\Rightarrow2\left\{200-4\left[90-7.10\right]\right\}.x=250\)
\(\Rightarrow\left[200-4\left(90-70\right)\right].x=125\)
\(\Rightarrow\left[200-4.20\right].x=125\)
\(\Rightarrow120x=125\)
\(\Rightarrow x=\frac{125}{120}=\frac{25}{24}\)
\(\text{Xin điểm ạ}\)
350:[19-(7x-3)]=350
[19-(7x-3)]=350:350
[19-(7x-3)]=1
(7x-3)=19-1
(7x-3)=18
7x=18+3
7x=21
x=21:7
x=3
vậy x=3
7.[109-(x-19)]-420=0
7.[109-(x-19)]=0+420
7.[109-(x-19)]=420
[109-(x-19)]=420:7
[109-(x-19)]=60
(x-19)=109-60
(x-19)=49
x=49+19
x=58
vậy x=58
254-2{200-4.[90-7.(19-9)]}.x=4
254-2{200-4.[90-7.10]}.x=4
254-2{200-4.[90-70]}.x=4
254-2{200-4.20}.x=4
254-2{200-80}.x=4
254-2.120.x=4
254-240.x=4
240.x=254-4
240.x=250
x=250:240
x=25/24
vậy x=25/24
a.
\(\left(x+1\right)^2=9\\ \Leftrightarrow\left(x+1\right)^2=3^2\)
\(\Rightarrow\left[{}\begin{matrix}x+1=3\\x+1=-3\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)
b.
\(\left(7x-4\right)^3=2^5.5^2+200\\ \Leftrightarrow\left(7x-4\right)^3=800+200=1000\\ \Leftrightarrow\left(7x-4\right)^3=10^3\)
\(\Rightarrow\left[{}\begin{matrix}7x-4=10\\7x-4=-10\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{-6}{7}\end{matrix}\right.\)
Đs...