4-12/17:6/7
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A =\(\frac{2}{5}\times\frac{4}{7}+\frac{3}{5}\times\frac{4}{7}\) B = \(\frac{17}{13}\times\frac{12}{17}-\frac{4}{13}\times\frac{12}{17}\) C = \(\frac{9}{14}:\frac{6}{7}+\frac{5}{14}:\frac{6}{7}\) D =\(\frac{9}{12}:\frac{7}{9}\times\frac{12}{19}\)
= \(\frac{4}{7}\times\left(\frac{2}{5}+\frac{3}{5}\right)\) =\(\left(\frac{17}{13}-\frac{4}{13}\right)\times\frac{12}{17}\) = \((\frac{9}{14}+\frac{5}{14}):\frac{6}{7}\) = \(\frac{9}{12}\times\frac{9}{7}\times\frac{12}{19}\)
=\(\frac{4}{7}\times1\) = \(1\times\frac{12}{17}\) = \(1:\frac{6}{7}\) = \(\frac{9\times9\times12}{12\times7\times19}\)
=\(\frac{4}{7}\) = \(\frac{12}{17}\) =\(\frac{7}{6}\) = \(\frac{9\times9}{7\times19}=\frac{81}{133}\)
\(-2,4\cdot\dfrac{17}{4}+\dfrac{12}{7}\cdot\left(-\dfrac{85}{6}\right)-2,4\cdot\left(-5\dfrac{5}{4}\right)-\dfrac{12}{7}\cdot\left(-\dfrac{71}{6}\right)\)
\(=-2,4\cdot\dfrac{17}{4}-2,4\cdot\left(-\dfrac{25}{4}\right)+\dfrac{12}{7}\cdot\left(-\dfrac{85}{6}\right)+\dfrac{12}{7}\cdot\dfrac{71}{6}\)
\(=-2,4\cdot\left(\dfrac{17}{4}-\dfrac{25}{4}\right)+\dfrac{12}{7}\cdot\left(-\dfrac{85}{6}+\dfrac{71}{6}\right)\)
\(=-2,4\cdot\left(-2\right)+\dfrac{12}{7}\cdot\left(-\dfrac{7}{3}\right)\)
\(=4,8-4\)
\(=0,8\)
#\(Toru\)
2 - 5/6 = 2/1 - 5/6 = 12/6 - 5/6 = 12-5/ 6= 7/6
7/8 + 3/4 = 7/8 + 6 / 8 = 7+8/8 = 15/8
2/5 + 3/4 = 8/20 + 15/20 = 8+15/20 = 23/20
2 - 5/6 = 2/1 - 5/6 = 12/6 - 5/6 = 12-5/6 = 7/6
7/8 + 3/4 = 7/8 + 6/8 = 7 + 8/8 =15/8
2/5 + 3/4 = 8/20 + 15/20 = 8 + 15/20 = 23/20
13 – 6 + 8 = 7 + 8 = 15
7 + 5 – 9 = 12 – 9 = 3
17 – 8 + 6 = 9 + 6 = 15
7 + 9 – 12 = 16 – 12 = 4
14 + 6 – 17 = 20 – 17 = 3
51 + 18 – 40 = 69 – 40 = 29
43 + 7 – 21 = 50 – 21 = 29
6 + 4 – 8 = 10 – 8 = 2
12 – 3 + 8 = 9 + 8 = 17
a: =-5/11-6/11+1=-11/11+1=0
b: =-13/17-13/21-4/17=-1-13/21=-34/21
b: \(=-\dfrac{5}{12}\cdot\dfrac{9}{20}\cdot\dfrac{7}{17}=\dfrac{-21}{272}\)
d: \(=\dfrac{13}{17}\left(-\dfrac{4}{5}-\dfrac{3}{4}\right)=\dfrac{13}{17}\cdot\dfrac{-31}{20}=\dfrac{-403}{340}\)
2 - 5/6= 7/6
7/8+3/4=`13/8
2/5+3/4=23/20
7/12 - 2/7 + 1/12=8/21
12/17 - 5/17 - 4/17=3/17
a: =(5/7+2/7)+(4/3+5/3)=3+1=4
b: =(17/12+7/12)+(29/7-8/7)
=2+3=5
c: =(2/5+3/5)+(6/9+1/3)+(7/4+1/4)
=1+2+1
=4
d: =(1/3+2/3)+(13/17+4/17)+(29/11+4/11)
=1+1+3=5
2/3+4/5=10/15+12/15=22/15
4/6+8/12=8/12+8/12=16/12=4/3
99/17+100/17=199/17
67/12-7/6=67/12-14/12=53/12
65/18-8/6=65/18-24/18=41/18
\(\frac{2}{3}+\frac{4}{5}=\frac{22}{15}\)
\(\frac{4}{6}+\frac{8}{12}=\frac{4}{3}\)
\(\frac{99}{17}+\frac{100}{17}=\frac{199}{17}\)
\(\frac{67}{12}-\frac{7}{6}=\frac{53}{12}\)
Bài 1:
a: \(x=\dfrac{2}{3}:\dfrac{3}{5}=\dfrac{2}{3}\cdot\dfrac{5}{3}=\dfrac{10}{9}\)
b: \(x=\dfrac{17}{8}:\dfrac{7}{17}=\dfrac{17}{8}\cdot\dfrac{17}{7}=\dfrac{289}{56}\)
c: \(x=-\dfrac{3}{4}:\dfrac{7}{12}=\dfrac{-3}{4}\cdot\dfrac{12}{7}=\dfrac{-63}{28}=-\dfrac{9}{4}\)
d: \(\Leftrightarrow x\cdot\dfrac{1}{6}=\dfrac{3}{8}-\dfrac{1}{4}=\dfrac{1}{4}\)
hay \(x=\dfrac{1}{4}:\dfrac{1}{6}=\dfrac{3}{2}\)
e: \(\Leftrightarrow\dfrac{1}{2}:x=-4-\dfrac{1}{3}=-\dfrac{17}{3}\)
hay \(x=-\dfrac{1}{2}:\dfrac{17}{3}=\dfrac{-3}{34}\)
\(4-\dfrac{12}{17}:\dfrac{6}{7}=4-\dfrac{12}{17}\times\dfrac{7}{6}=4-\dfrac{14}{17}=\dfrac{68-14}{17}=\dfrac{54}{17}\)
\(4-\dfrac{12}{7}:\dfrac{6}{7}=4-\dfrac{12}{7}\times\dfrac{7}{6}=4-\dfrac{12}{6}=4-2=2\)