Tính
8/5+7/6+5/9-2
3-5/6-4/9+32/24
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a)\(\dfrac{8}{5}+\dfrac{7}{6}+\dfrac{5}{9}-2\)
\(=\dfrac{144}{90}+\dfrac{105}{6}+\dfrac{50}{90}-\dfrac{180}{90}=\dfrac{119}{90}\)
b) \(3-\dfrac{5}{6}-\dfrac{4}{9}+\dfrac{32}{24}\)
\(=3-\dfrac{5}{6}-\dfrac{4}{9}+\dfrac{4}{3}\)
\(=\dfrac{54}{18}-\dfrac{15}{18}-\dfrac{8}{18}+\dfrac{24}{18}=\dfrac{55}{18}\)
Tính các tổng sau:
1, S=1-2+3_4+..+25-26
S =-1+3-5+7-...-53+55 ( có 28 số hạng )
= (-1+3)+(-5+7)+...+(-53+55) ( có 28:2=14 nhóm )
= 2+2+...+2
= 2 . 14
= 28
\(a)\dfrac{8}{5}+\dfrac{7}{6}+\dfrac{5}{9}+2\)
\(\text{=}\dfrac{144}{90}+\dfrac{105}{90}+\dfrac{50}{90}+\dfrac{180}{90}\)
\(\text{=}\dfrac{144+105+50+180}{90}\)
\(\text{=}\dfrac{497}{90}\)
\(b)3-\dfrac{5}{6}-\dfrac{4}{9}+\dfrac{32}{24}\)
\(\text{=}3-\dfrac{5}{6}-\dfrac{4}{9}+\dfrac{4}{3}\)
\(\text{=}\dfrac{54-15-8+24}{48}\text{=}\dfrac{55}{48}\)
\(\dfrac{8}{5}+\dfrac{7}{6}+\dfrac{5}{9}-2=\dfrac{144}{90}+\dfrac{105}{90}+\dfrac{50}{90}-\dfrac{180}{90}=\dfrac{119}{90}\)
\(3-\dfrac{5}{6}-\dfrac{4}{9}+\dfrac{32}{24}=3-\dfrac{5}{6}-\dfrac{4}{9}+\dfrac{4}{3}=\dfrac{54}{18}-\dfrac{15}{18}-\dfrac{8}{18}+\dfrac{24}{18}=\dfrac{55}{18}\)
8/5+7/6+5/9-2=83/30+5/9-2
=299/90-2
=119/90
3-5/6-4/9+32/24=13/6-4/9+32/24
=13/18+32/24
=55/18
) 2 x 6 = 12 3 x 7 = 21
12 : 2 = 6 21 : 3 = 7
12 : 6 = 2 21 : 7 = 3
4 x 8 = 32 5 x 9 = 45
32 : 4 = 8 45 : 5 = 9
32 : 8 = 4 45 : 9 = 5
b) 600 : 3 = 200 800 : 4 = 200 400 : 2 = 200
600 : 2 = 300 800 : 2 = 400 500 : 5 = 100
a) 2x6=12 3x7=21
12:2=6 21:3=7
12:6=2 21:7=3
4x8=32 5x9=45
32:4=8 45:5=9
32:8=4 45:9=5
b) 600:3=200 800:4=200 400:2=200
600:2=300 800:2=400 500:5=100
A Legend Never Dies
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