Question

[cục cứt pít chạy óhh]

giúp em với aaaa

Answer 1

[hnamyuh]

Bài 1 : 

CTHH	Phân loại	Tên
$Na_2CO_3$	muối	Sodium carbonate
$Fe_2O_3$	oxit bazo	Ferric oxide
$H_2SO_4$	axit	Sulfuric Acid
$Zn(NO_3)_2$	muối	Zinc Nitrate
$P_2O_5$	oxit axit	Phosphorus Oxide
$Fe(OH)_3$	bazo	Iron (III) hydroxyde

Bài 2 : 

$a) N_2 + O_2 \xrightarrow{t^o} 2NO$
$b) 2Cu + O_2 \xrightarrow{t^o} 2CuO$
$c) Fe + 2HCl \to FeCl_2 + H_2$
$d) 2H_2 + O_2 \xrightarrow{t^o} 2H_2O$
$e)2K + 2H_2O \to 2KOH + H_2$
$f) P_2O_5 + 3H_2O \to 2H_3PO_4$
$g) FeO + H_2 \xrightarrow{t^o} Fe + H_2O$

Bài 3 : 

a) $Fe + 2HCl \to FeCl_2 + H_2$

$n_{Fe} = \dfrac{2,8}{56} = 0,05(mol)$
$n_{HCl} =2 n_{Fe} = 0,1(mol) \Rightarrow V_{dd\ HCl} = \dfrac{0,1}{2} = 0,05(lít)$

b) $n_{H_2} = n_{Fe} = 0,05(mol) \Rightarrow V_{H_2} = 0,05.22,4 = 1,12(lít)$

c) $C_{M_{FeCl_2}} = \dfrac{0,05}{0,05} = 1M$

Answer 2

[Nguyễn Lê Phước Thịnh]

Câu 3: 

a: \(Fe+2HCl\rightarrow FeCl_2+H_2\)

0,05           0,1         0,05  

\(V_{HCl}=\dfrac{0.1}{2}=0.05\left(lít\right)\)

b: \(n_{H_2}=0.05\left(mol\right)\)

=>\(V_{H_2}=0.05\cdot22.4=1.12\left(lít\right)\)

Câu 2: 

\(N_2+O_2\rightarrow2NO\)

\(2Cu+O_2\rightarrow2CuO\)

\(Fe+2HCl\rightarrow FeCl_2+H_2\)

\(2H_2+O_2\rightarrow2H_2O\)

\(P_2O_5+3H_2O\rightarrow2H_3PO_4\)