Tính nhanh
-5+5 mũ 2 - 5 mũ 3 + 5 mũ 4 -...-5 mũ 2017 +5 mũ 2018
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\(\left(x+1\right)^3=27\)
\(\left(x+1\right)^3=3^3\)
\(\Rightarrow x+1=3\)
\(x=2\)
\(\left(x+1\right)^3=27\)
\(< =>\left(x+1\right)^3=3.3.3=3^3\)
\(< =>x+1=3< =>x=3-1=2\)
\(\left(2x+3\right)^3=9.81\)
\(< =>\left(2x+3\right)^3=9.9.9\)
\(< =>\left(2x+3\right)^3=9^3\)
\(< =>2x+3=9< =>2x=6\)
\(< =>x=\frac{6}{2}=3\)
Giải:
a) Đặt:
\(A=1+2^2+2^3+2^4+...+2^{2018}\)
\(\Leftrightarrow2A=2+2^3+2^4+2^5+...+2^{2019}\)
\(\Leftrightarrow2A-A=\left(2+2^{2019}\right)-\left(1+2^2\right)\)
\(\Leftrightarrow A=2+2^{2019}-1-2^2\)
\(\Leftrightarrow A=2+2^{2019}-5\)
\(\Leftrightarrow A=2^{2019}-3\)
Vậy \(A=2^{2019}-3\).
b) Đặt:
\(B=1+5+5^2+5^3+...+5^{2017}\)
\(\Leftrightarrow5B=5+5^2+5^3+5^4+...+5^{2018}\)
\(\Leftrightarrow5B-B=5^{2018}-1\)
\(\Leftrightarrow4B=5^{2018}-1\)
\(\Leftrightarrow B=\dfrac{5^{2018}-1}{4}\)
Vậy \(B=\dfrac{5^{2018}-1}{4}\).
Chúc bạn học tốt!
a)A= 1 + 22+23 + 24 +....+22018
2A = 22 + 23 + 24 +......+22018 + 22019
_
A= 1 + 22+23 + 24 +....+22018
A= 22019 - 1
a)\(A=1+3+3^2+...+3^{2018}\)
\(\Rightarrow3A=3.\left(1+3+3^2+...+3^{2018}\right)\)
\(\Rightarrow3A=3+3^2+3^3+...+3^{2019}\)
\(\Rightarrow3A-A=3+3^2+3^3+...+3^{2019}-\left(1+3+3^2+...+3^{2018}\right)\)
\(\Rightarrow2A=3^{2019}-1\)
\(\Rightarrow A=\frac{3^{2019}-1}{2}\)
b) \(B=5+5^2+...+5^{2017}\)
\(\Rightarrow5B=5^2+5^3+...+5^{2018}\)
\(\Rightarrow5B-B=5^2+5^3+...+5^{2018}-5-5^2-...-5^{2017}\)
\(\Rightarrow4B=5^{2018}-5\)
\(\Rightarrow B=\frac{5^{2018}-5}{4}\)
a,A=1+3+32+...+32017
3A=3+32+33+...+32018
3A-A=32018-1
2A=32018-1
A=(32018-1):2
`A = 2 + 2^2+ ... + 2^2017`
`=> 2A = 2^2 + 2^3 + ... + 2^2018`
`=> 2A - A = (2^2 + 2^3 + ... + 2^2018) - (2 + 2^2 + ... +2^2017)`
`=> A = 2^2018 - 2`
`B = 1 + 3^2 + ... + 3^2018`
`=> 3^2B = 3^2 + 3^4 + ... + 3^2020`
`=> 9B-B =(3^2 + 3^4 + ... + 3^2020) - (1 + 3^2 + ... + 3^2018`
`=> 8B = 3^2020 - 1`
`=> B = (3^2020 - 1)/8`
`C = 5 + 5^2 - 5^3 + ... + 5^2018`
`=> 5C = 5^2 + 5^3 - 5^4 + ... +5^2019`
`=> 5C + C = ( 5^2 + 5^3 - 5^4 + ... 5^2019) + (5 + 5^2 - 5^3 + ... + 5^2018)`
`=> 6C = 55 + 5^2019`
`=> C = (5^2019 + 55)/6`
(59 x 75 - 510 x 75 : 5) : 20172018
= [59 x 75 - (510 : 5) x 75) : 20172018
= (59 x 75 - 59 x 75) : 20172018
= 0 : 20172018
= 0
(1981 x 1982 - 990) : (1980 x 1982 + 992)
=(1980 x 1982+1982 -990) : (1980 x 1982 +992)
=(1980 x 1982 + 992) : ( 1980 x 1982 + 992)
=1
B=[(45.79+45.21)]:90-5^2]:5+2^3 B=[(45.79+45.21):90-25]:5+8 B=[(45.(79+21):65]:13 B=[(45.100):65]:13 B=[4500:65]:13 B=4500:65:13
1. a) 4.415.8.25.125
= (4.25). (8.125).415
= 100.1000.415
= 100000.415
= 41500000
b) 2.31.12+4.42.6+8.27.3
= (2.31.12)+(4.42.6)+(8.27.3)
= (2.12).31+(4.6).42+(8.3).27
= 24.31+24.42+24.27
= 24 (31+42+27)
= 24.100
= 2400
Sai đề câu E sửa lại 95 hoặc 93 vì đây là dãy số mũ lẻ. Ta có :
\(E=3+3^3+3^5+3^7+...+3^{95}\)
\(\Rightarrow\) \(9E=3^3+3^5+3^7+3^9+...+3^{95}+3^{97}\)
\(\Rightarrow\) \(8E=3^{97}-3\)
\(\Rightarrow\) \(E=\frac{3^{97}-3}{8}\)
\(E=3+3^3+3^5+3^7+.......+3^{95}\)
\(\Rightarrow9E=3^3+3^5+3^7+3^9+...+3^{97}\)
\(\Rightarrow9E-E=\left(3^3+3^5+3^7+3^9+....+3^{97}\right)-\left(3+3^3+3^5+3^7+.....+3^{95}\right)\)
\(\Rightarrow8E=3^{97}-3\)
\(\Rightarrow E=\frac{3^{97}-3}{8}\)
\(F=1+2018+2018^2+......+2018^{2017}\)
\(=2018^0+2018^1+2018^2+....+2018^{2017}\)
\(\Rightarrow2018F=2018^1+2018^2+2018^3+....+2018^{2018}\)
\(\Rightarrow2018F-F=\left(2018^1+2018^2+2018^3+....+2018^{2018}\right)-\left(2018^0+2018^1+2018^2+....+2018^{2017}\right)\)
\(\Rightarrow2017F=2018^{2018}-1\)
\(\Rightarrow F=\frac{2018^{2018}-1}{2017}\)
Đặt A = -5+52-53+54-...-52017+52018
=>5A = -52+53-54+55-...-52018+52019
=> 5A+A=(-52+53-54+55-...+52019)+(-5+52-53+54-...+52018)
=> 6A = 52019-5
=> A = \(\dfrac{5^{2019}-5}{6}\)