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3x +20 =65
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a, 1230 : 3(x – 20) = 10
3(x – 20) = 123
x – 20 = 41
x = 61
b, 250 – 10.(24 – 3x):15 = 244
10.(24 – 3x):15 = 6
10.(24 – 3x) = 90
24 – 3x = 9
3x = 15
x = 5
c, 4 x 3 + 15 = 47
4 x 3 = 32
x 3 = 8 = 2 3
x = 2
d, 65 - 4 x + 2 = 2014 0
65 - 4 x + 2 = 1
4 x + 2 = 64 = 4 3
x + 2 = 3
x = 1
e, 4 . 2 x - 3 = 125
4 . 2 x = 128
2 x = 32 = 2 5
x = 5
a)
5.(12-x)-20=30
⇒60-5x-20=30
⇒-5x=30+20-60
⇒-5x=-10
⇒x=2
b)(17x - 25 ) : 8 + 65 = 92
(17x - 25 ) : 8 + 65 = 81
17x - 25 = 16 x 8 = 128
17x = 128+25=153
x= 153:17 =9
c)
x=23
Giải thích các bước giải:
3x – 10 = 2x + 13
3x-2x=13+10
x=23
d)4(2x+7)-3(3x-2)=24
4.2x+4.7-3.3x+3.2=24
8x+28-9x+6=24
8x-9x=24-28-6=-10
=>(-1)x=-10
x=-10:(-1)
x=10
a. \(5\cdot\left(12-x\right)-20=30\Leftrightarrow5\left(12-x\right)=50\)
\(\Leftrightarrow12-x=50:5=10\)
\(\Leftrightarrow x=12-10=2\)
b. \(\left(17x-25\right):8+65=9^2\)
\(\Leftrightarrow\left(17x-25\right):8=81-65=16\)
\(\Leftrightarrow17x-25=16:8=2\)
\(\Leftrightarrow17x=2+25=27\Leftrightarrow x=\frac{27}{17}\)
c. \(3x-10=2x+13\)
\(\Leftrightarrow3x-2x=10+13\)
\(\Leftrightarrow x=23\)
d. \(4\cdot\left(2x+7\right)-3\cdot\left(3x-2\right)=24\)
\(\Leftrightarrow8x+28-9x+6=24\)
\(\Leftrightarrow34-x=24\Leftrightarrow x=10\)
1:
a: \(35\cdot16+35\cdot28-44\cdot15\)
\(=35\left(16+28\right)-44\cdot15\)
\(=44\left(35-15\right)\)
\(=44\cdot20=880\)
b: \(240-2\left(3\cdot5^2-20:2^2\right)\)
\(=240-2\left(3\cdot25-20:4\right)\)
\(=240-150+10=10+90=100\)
2:
b: \(\left(8-3x\right)^4-1=15\)
=>\(\left(3x-8\right)^4=16\)
=>\(\left[{}\begin{matrix}3x-8=2\\3x-8=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=10\\3x=6\end{matrix}\right.\)
=>x=10/3 hoặc x=2
c: \(218-5\left(x-8\right)=2^5:2^2\)
=>\(218-5\left(x-8\right)=2^3=8\)
=>5(x-8)=210
=>x-8=42
=>x=50
d: \(\left(5-3x\right)^4-1=15\)
=>\(\left(3x-5\right)^4-1=15\)
=>\(\left(3x-5\right)^4=16\)
=>\(\left[{}\begin{matrix}3x-5=-4\\3x-5=4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=1\\3x=9\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=3\end{matrix}\right.\)
65 - 5 = 60 65 - 60 = 5 65 - 65 = 0
70 - 30 = 40 94 - 3 = 91 33 - 30 = 3
21 - 1 = 20 21 - 20 = 1 32 - 10 = 22
65 - 5 = 60 65 - 60 = 5 65 - 65 = 0
70 - 30 = 40 94 - 3 = 91 33 - 30 = 3
21 - 1 = 20 21 - 20 = 1 32 - 10 = 22
Toán lớp 1 không có cái này đâu !!!
a) \(5x-65=5.3^2 \\ 5x-65=45\\5x=45+65\\5x=110\\x=22\)
b) \(200-(2x+6)=4^3\\2x+6=200-4^3\\2x+6=136\\2x=130\\x=65\)
c) \(2(x-51)=2.2^3+20\\2(x-51)=16+20\\2(x-51)=36\\x-51=18\\x=51+18=69\)
d) \(135-5(x+4)=35\\5(x+4)=135-45\\5(x-4)=90\\x-4=18\\x=18+4=22\)
e) \((2x-4)(15-3x)=0\\2(x-2).3(5-x)=0\\(x-2)(5-x)=0\\ \left[ \begin{array}{l}x-2=0\\5-x=0\end{array} \right. \\ \left[ \begin{array}{l}x=2\\x=5\end{array} \right.\)
f) \(2^{x+1} . 2^{2014}=2^{2016} \\ (2^{x+1} . 2^{2014}):2^{2014}=2^{2016} :2^{2014} \\ 2^{x=1}=2^{2016-2014} \\2^{x+1}=2^2\\x+1=2\\x=1\)
g) \(15+(x-1)^3=43\\(x-1)^3=15-42\\(x-1)^3=-27\\(x-1)^3=(-3)^3\\x-1=-3\\x=-2\)
h) \(15-x=17+(-9)\\15-x=17-9\\15-x=8\\x=15-8\\x=7\)
i) \(|x-5|=|-7|+|-4|\\|x-5|=7+4\\|x-5|=11\\ \left[ \begin{array}{l}x-5=11\\x-5=-11\end{array} \right. \\ \left[ \begin{array}{l}x=16\\x=-6\end{array} \right.\)
k) \(|x-3|-12=-9+|-7|\\|x-3|-12=-9+7\\|x-3|-12=-2\\|x-3|=10 \\ \left[ \begin{array}{l}x-3=10\\x-3=-10\end{array} \right. \\ \left[ \begin{array}{l}x=13\\x=-7\end{array} \right.\)
Tìm x
a, 5x - 10 . (-7) = 15 . (-3)
5x + 70 = -45
5x = -45 - 70
5x = -115
x = -115 : 5
x = -23
Vậy x = -23.
b, 2x + 12 = -8
2x = -8 - 12
2x = -20
x = -20 : 2
x = -10
Vậy x = -10.
c, 3x - 5 = -20
3x = -20 + 5
3x = -15
x = -15 : 3
x = -5
Vậy x = -5.
d, 2x - (-12) = -8 . 23
2x + 12 = -184
2x = -184 - 12
2x = -196
x = -196 : 2
x = -98
Vậy x = -98.
e, x2 = 49
x2 = 72 = (-7)2
=> x = 7 hoặc x = -7.
Vậy x thuộc {-7 ; 7}
i, (x - 2)2 + 1 = 65
(x - 2)2 = 65 - 1
(x - 2)2 = 64
(x - 2)2 = 82 = (-8)2
=> x - 2 = 8 hoặc x - 2 = -8
=> x = 10 hoăc x = -6
Vậy x thuộc {-6 ; 10}.
g, 2 (x - 3)2 - 5 = 5 . (-3)2
2 (x - 3)2 - 5 = 5 . 9
2 (x - 3)2 - 5 = 45
2 (x - 3)2 = 45 + 5
2 (x - 3)2 = 50
(x - 3)2 = 50 : 2
(x - 3)2 = 25
(x - 3)2 = 52 = (-5)2
=> x - 3 = 5 hoặc x - 3 = -5
=> x = 8 hoặc x = -2
Vậy x thuộc {-2 ; 8}.
a) 5x - 10.(-7)=15.(-3) b) 2x+12=-8 c) 3x-5=-20 d)2x-(-12)=-8.23 e)\(^{x^2}\)=49 i)\(\left(x-2\right)^2+1\)=65
5x+70=-45 2x=-8-12 3x=-20+5 2x+12=-184 x=7 \(\left(x-2\right)^2\) =64
5x=-45-70 2x=-20 3x=-15 2x=-184-12 X-2 =8
5x=-115 x=-20:2 x=-15:3 2x=-186 x =10
x=-23 x=-10 x=-5 x=-93
g)\(2.\left(x-3\right)^2-5=5.\left(-3\right)^2\)
\(2\left(x-3\right)^2-5=30\)
\(2.\left(x-3\right)^2=35\)
\(2.\left(x^2-2x.3+3^2\right)=35\)
\(2x^2-24x+18=35\)
\(2x^2-24x=17\)
\(2x\left(x-12\right)=17\)
\(\orbr{\begin{cases}2x=17\\x-12=17\end{cases}}\orbr{\begin{cases}x=\frac{17}{2}\\x=29\end{cases}}\)
X\(3x-15=65-2x\)
Áp dụng quy tắc chuyển vế, ta có:
\(3x+2x=65+15\)
\(5x=80\)
\(x=16\)
3x - 15 = 65 - 2x
=> 3x + 2x = 65 + 15
=> 5x = 80
=> x = 80 : 5
=> x = 16
3x+20=65
=> 3x=45
=> x = 15
3x = 65-20
3x= 45
x= 45: 3
x= 15