X+524=2256-145
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(478-739)+739
= 478 - 739 + 793
= 793 - 793 + 478
= 00 + 478
= 478
524-(524-213)
= 524 - 524 + 213
= 0 + 213
= 213
(145-342)+(342-45)
= 145 - 342 + 342 - 45
= 342 - 342 +145 - 45
= 00 + 145 - 45
= 100
(-75+94)-(25+94)
= -75 + 94 - 25 - 94
= 94 - 94 - 75 - 25
= 00 - 75 - 25
= -100
a ) 159 − 524 − 59 − 424 ; = 159 − 524 − 59 + 424 = 159 − 59 − 524 − 424 = 100 − 100 = 0 b ) 36 + 79 + 145 − 79 − 36 ; = 36 + 79 + 145 − 79 − 36 = 36 − 36 + 79 − 79 + 145 = 145 c ) 334 − 117 + 234 + 42 + 117 ; = 334 − 117 − 234 + 42 + 117 = 334 − 234 − 117 − 117 + 42 = 100 + 42 = 142 d ) 271 − − 43 + 271 − − 17 . = 271 − − 43 + 271 + 17 = 271 + 43 − 271 − 17 = 271 − 271 + 43 − 17 = 26
a: \(\left(24-234\right)+\left(234-24-77\right)\)
\(=24-234+234-24-77\)
\(=\left(24-24\right)+\left(234-234\right)-77\)
=0+0-77
=-77
b: \(\left(13-135+49\right)-\left(13+49\right)\)
\(=13-135+49-13-49\)
\(=\left(13-13\right)+\left(49-49\right)-135\)
=0+0-135
=-135
c: \(159-524-\left(59-424\right)\)
\(=159-524-59+424\)
\(=\left(159-59\right)-\left(524-424\right)\)
=100-100
=0
d: \(\left(36+79\right)+\left(145-79-36\right)\)
\(=36+79+145-79-36\)
\(=\left(36-36\right)+\left(79-79\right)+145\)
=0+0+145
=145
e: \(334-\left(117+234\right)+\left(42+117\right)\)
\(=334-117-234+42+117\)
\(=\left(334-234\right)+\left(117-117\right)+42\)
=100+0+42
=142
f: \(271-\left[\left(-43\right)+271-\left(-17\right)\right]\)
\(=271+43-271+\left(-17\right)\)
\(=\left(271-271\right)+\left(43-17\right)\)
=0+26
=26
a)=234(1257-257)
=234.1000
=234000
b)=524(1327-327)
=524.1000
=524000
c)=325(1574-325-24)
=325.1225
=398125
d)=175(1274-273-1)
=175.1000
=175000
234x (1257-257)= 234 x 1000 = 234000
1327 x 524 - 524 x 327 = 524 x (1327 - 327 ) = 524 x 1000 = 524000
325x1574 - 325 x 325 -325 x24 =325 x(1574 - 325 - 24 )= 325 x 1225 =398125
175 x 1274 - 175 x273 -175 = 175 x (1274 - 273 -1) = 175 x 1000= 175000
kkk mk nha bạn !!!!!!!!
\(E=\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+...+\dfrac{2}{2256}\)
\(=\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{47.48}\)
\(=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+...+\dfrac{1}{47}-\dfrac{1}{48}\)
\(=\dfrac{1}{2}-\dfrac{1}{48}\)
\(=\dfrac{23}{48}\)
x+524=2256-145`
`x+524=2111`
`x=2111-524`
`x=1587`
Vậy `x=1587`
2256 - 145
= 2111
x = 2111 - 524
x = 1587