X : 6 x 7.2 + 1.3 x X + X : 2 + 1.5 = 19.95
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\(x\div6\times7,2+1,3\times x+x\div2+15=19,95\)
\(\Leftrightarrow x\times\frac{1}{6}\times7,2+1,3\times x+x\times\frac{1}{2}=19,95-15\)
\(\Leftrightarrow x\times1,2+x\times1,3+x\times\frac{1}{2}=4,95\)
\(\Leftrightarrow x\times\left(1,2+1,3+\frac{1}{2}\right)=4,95\)
\(\Leftrightarrow x\times3=4,95\)
\(\Leftrightarrow x=4,95\div3\)
\(\Leftrightarrow x=1,65\)
Vậy x = 1,65
\(\dfrac{2^2}{1\times3}\times\dfrac{3^2}{2.4}\times\dfrac{4^2}{3.5}\times\dfrac{5^2}{4.6}=\dfrac{2^2.3^2.4^2.5^2}{1.3.2.4.3.5.4.6}=\dfrac{2^2.3^2.4^2.5^2}{1.2.3.3.4.4.5.2.3}=\dfrac{2^2.3^2.4^2.5^2}{3^3.2^2.4^2.5.1}=\dfrac{5}{3.1}=\dfrac{5}{3}\)
\(\dfrac{2^2}{1\cdot3}\cdot\dfrac{3^2}{2\cdot4}\cdot\dfrac{4^2}{3\cdot5}\cdot\dfrac{5^2}{4.6}\\ =\dfrac{2^2\cdot3^2\cdot4^2\cdot5^2}{1\cdot3\cdot2\cdot4\cdot3\cdot5\cdot4\cdot6}\\ =\dfrac{2^2\cdot3^2\cdot4^2\cdot5^2}{1\cdot2\cdot4^2\cdot4^2\cdot5\cdot6}\\ =\dfrac{2\cdot5}{6}=\dfrac{5}{3}\)
5.7 x (179 -130) + (3.4 + 2.3) x (32 + 18) + (7.2 - 1.5)=570
k mk nha mn
( 1.1 x 1.2 x 1.3 x 1.4 x 1.5 x 1.6 ) x ( 1.25 - 0.25 x 5 )
=( 1,1 x 1,2 x1,3 x1,4 x1,5 x1,6 ) x ( 1,25 - 1,25 )
=( 1.1x1,2 x1,3 x1,4 x1,5 x1,6 ) x 0
=0
#Toán lớp 5
\(x:6\cdot7,2+1,3\cdot x+x:2+1.5=19.95\)
==> \(x\cdot7,2:6+1,3\cdot x+x\cdot\dfrac{1}{2}=19,95-1,5\)
==> \(x\cdot1,2+1,3\cdot x+x\cdot\dfrac{1}{2}=18,45\)
==> \(x\cdot\left(1,2+1,3+\dfrac{1}{2}\right)=18,45\)
==> \(x\cdot\left(2,5+0,5\right)=18,45\)
==> \(x\cdot3=18,45\)
==> \(x=18,45:3\)
==> \(x=6,15.\)
Vậy x là 6,15.
X : 6 x 7.2 + 1.3 x X + X : 2 + 1.5 = 19.95
1,2 X+ 1,3 X+ 0,5 X = 19.95-1,5 =18,45
3X=18,45
X= 18,45/3 = 6,15