(x - 1/3). 1và 2/3 = 14/27 - 3/9
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MB
1
28 tháng 10 2021
\(1,2\sqrt{3}+\sqrt{27}=2\sqrt{3}+3\sqrt{3}=5\sqrt{3}=\sqrt{75}>\sqrt{74}\\ 2,\left(3+\sqrt{5}\right)^2=14+6\sqrt{5}\\ \left(2\sqrt{2}+\sqrt{6}\right)^2=14+4\sqrt{3}\\ 6\sqrt{5}=\sqrt{180}>\sqrt{48}=4\sqrt{3}\\ \Rightarrow3+\sqrt{5}>2\sqrt{2}+\sqrt{6}\\ 3,3\sqrt{3}+\sqrt{26}+1>3\sqrt{3}+\sqrt{3}\left(\sqrt{26}>\sqrt{3}\right)\\ \Rightarrow\sqrt{27}+\sqrt{26}+1>4\sqrt{3}=\sqrt{48}\\ 4,\dfrac{1}{\sqrt{15}+\sqrt{14}}< \dfrac{1}{\sqrt{14}+\sqrt{13}}\left(\sqrt{15}+\sqrt{14}>\sqrt{14}+\sqrt{13}\right)\\ \Rightarrow\sqrt{15}-\sqrt{14}< \sqrt{14}-\sqrt{13}\)
GD
0
NT
2
24 tháng 10 2020
A) x/y-3/8=1 x/y-3/8=1/2 B)4/9:x/y=1 4/9:x/y=2/3
x/y=1+3/8 x/y=1/2+3/8 x/y=4/9:1 x/y=4/9:2/3
x/y=8/8+3/8 x/y=4/8+3/8 x/y=4/9 x/y=2/3
x/y=11/8 x/y=7/8
NT
1
PT
1
2 tháng 3 2019
\(1\frac{1}{2}\times1\frac{1}{3}\times1\frac{1}{4}\times1\frac{1}{5}\times...1\frac{1}{9}+2005.\)
\(=\frac{3}{2}\times\frac{4}{3}\times\frac{5}{4}\times\frac{6}{5}\times...\times\frac{10}{9}+2005\)
\(=\frac{10}{2}+2005=5+2005=2010\)
.
25 tháng 7 2021
a) Ta có: \(\left(x-2\right)^3-\left(3+x^2\right)\left(3-x\right)\)
\(=x^3-6x^2+12x-8+\left(x-3\right)\left(x^2+3\right)\)
\(=x^3-6x^2+12x-8+x^3+3x-3x^2-9\)
\(=2x^3-9x^2+15x-17\)
b) Ta có: \(x\left(x-14\right)-10\left(x-1\right)^2\)
\(=x^2-14x-10\left(x^2-2x+1\right)\)
\(=x^2-14x-10x^2+20x-10\)
\(=-9x^2+6x-10\)
c) Ta có: \(2x\left(x+2\right)-\left(x+2\right)\left(x-2\right)\)
\(=2x^2+4x-\left(x^2-4\right)\)
\(=2x^2+4x-x^2+4\)
\(=x^2+4x+4\)
d) Ta có: \(\left(x-3\right)\left(x^2+3x+9\right)-\left(x^3-27\right)\)
\(=x^3-27-x^3+27\)
=0
C
12 tháng 2 2023
`#` `\text{dkhanhqlv}`
`4)`
`a)3.(-5/11)`
`=-15/11`
`b)3/5+4/7 . 14/6`
`=3/5 + 4/3`
`=9/15+20/15`
`=29/15`
`c) 10/21-3/8 . 4/15`
`=10/21-1/10`
`=100/210-21/210`
`=79/100`
`d)(2/3+3/4)(5/7+5/14)`
`=(8/12+9/12)(10/14+5/14)`
`=17/12 . 15/14`
`=85/56`
`5)`
`a)x-1/2=3/10 . 5/6`
`=>x-1/2=1/4`
`=>x=1/4+1/2`
`=>x=1/4+2/4`
`=>x=3/4`
`b)x/5 = -3/14`
`=>x : 5 = -3/14`
`=>x=-3/14 . 5`
`=>x=-15/14`
`c)x+2/3=9/15 . 5/27`
`=>x+2/3=1/9`
`=>x=1/9-2/3`
`=>x=1/9-6/9`
`=>x=-5/9`
`(x-1/3) . 1 2/3 = 14/27 - 3/9`
`(x-1/3). 1 2/3 = 14/27 - 9/27`
`(x-1/3). 1 2/3 = 5/27`
`(x-1/3) . 5/3 = 5/27`
`x-1/3 = 5/27 : 5/3`
`x-1/3 = 5/27 . 3/5`
`x-1/3 = 1/9`
`x=1/9+1/3`
`x=1/9+3/9`
`x=4/9`
Vậy `x=4/9`