3^5.3^x=9.3^5 giúp mình với
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`#3107`
b)
`2.3^x = 162`
`\Rightarrow 3^x = 162 \div 2`
`\Rightarrow 3^x = 81`
`\Rightarrow 3^x = 3^4`
`\Rightarrow x = 4`
Vậy, `x = 4`
c)
`(2x - 15)^5 = (2 - 15)^3`
\(\Rightarrow \)`(2x - 15)^5 - (2x - 15)^3 = 0`
\(\Rightarrow \)`(2x - 15)^3 . [ (2x - 15)^2 - 1] = 0`
\(\Rightarrow\left[{}\begin{matrix}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15\right)^2=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x=15\\\left(2x-15\right)^2=\left(\pm1\right)^2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\2x-15=1\\2x-15=-1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\2x=16\\2x=-14\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=8\\x=-7\end{matrix}\right.\)
Vậy, `x \in`\(\left\{-7;8;\dfrac{15}{2}\right\}.\)
`d)`
\(3^{x+2}-5.3^x=?\) Bạn ghi tiếp đề nhé!
`e)`
\(7\cdot4^{x-1}+4^{x-1}=23?\)
\(4^{x-1}\cdot\left(7+1\right)=23\\ \Rightarrow4^{x-1}\cdot8=23\\ \Rightarrow4^{x-1}=\dfrac{23}{8}\)
Bạn xem lại đề!
`f)`
\(2\cdot2^{2x}+4^3\cdot4^x=1056\)
\(\Rightarrow2\cdot2^{2x}+\left(2^2\right)^3\cdot\left(2^2\right)^x=1056\\ \Rightarrow2\cdot2^{2x}+2^6\cdot2^{2x}=1056\\ \Rightarrow2^{2x}\cdot\left(2+2^6\right)=1056\\ \Rightarrow2^{2x}\cdot66=1056\\ \Rightarrow2^{2x}=1056\div66\\ \Rightarrow2^{2x}=16\\ \Rightarrow2^{2x}=2^4\\ \Rightarrow2x=4\\ \Rightarrow x=2\)
Vậy, `x = 2`
_____
\(10 -{[(x \div 3+17) \div 10+3.2^4] \div 10}=5\)
\(\Rightarrow\left[\left(x\div3+17\right)\div10+48\right]\div10=10-5\)
\(\Rightarrow\left[\left(x\div3+17\right)\div10+48\right]\div10=5\)
\(\Rightarrow\left(x\div3+17\right)\div10+48=50\)
\(\Rightarrow\left(x\div3+17\right)\div10=2\)
\(\Rightarrow x\div3+17=20\)
\(\Rightarrow x\div3=3\\ \Rightarrow x=9\)
Vậy, `x = 9.`
\(A=\left(2^5\cdot2^7\right):2^{10}+5\cdot3^4-6^3:6\\ =2^{12}:2^{10}+5\cdot3^4-6^2\\ =2^2+5\cdot3^4-36\\ =4+405-36\\ =373\\ B=\left(5^2-3\right):11\\ =\left(25-3\right):11\\ =22:11\\ =2\\ C=\left(5^{2022}-5^{2021}\right):5^{2021}\\ =5^{2021}\cdot\left(5-1\right):5^{2021}\\ =4\\ D=\left(7^{20}-7^{19}\right):7^{19}\\ =7^{19}\cdot\left(7-1\right):7^{19}\\ =6\)
NH3 + HCl -> NH4Cl
NH4Cl -> NH4+ + Cl-
NH4+ <-> NH3 + H+
H+ + OH- <-> H2O
Vì \(Ka\times C>>Kw\) => Bỏ qua nước
NH4+ <-> NH3 + H+
0.1
x x x
0.1-x x x
\(Ka=\dfrac{x^2}{0.1-x}=10^{-9.3}\Leftrightarrow x=7.07\times10^{-6}\)\(\Rightarrow pH=5.2\)
Chọn D
5^4-3/100=1/20
3^3+2+1/3*13=3^5/13
5.3^7-5/5.3^5-3=1
2^15+14+13/2^13+12+11=2^6
\(3^{-1}.3^x+5.3^{x-1}=162\)
=> \(\frac{1}{3}.3^x+5.3^x:3=162\)
=> \(\left(\frac{1}{3}+\frac{5}{3}\right).3^x=162\)
=> 2 . 3x = 162
=> 3x = 162 : 2
=> 3x = 81
=> 3x = 34
=> x = 4
Vậy ...
\(3^{-1}.3^x+5.3^{x-1}=162\)
\(\Rightarrow3^{-1+x}+5.3^{x-1}=162\)
\(\Rightarrow3^{x-1}+5.3^{x-1}=162\)
\(\Rightarrow3^{x-1}.\left(1+5\right)=162\)
\(\Rightarrow3^{x-1}.6=162\)
\(\Rightarrow3^{x-1}=162:6=27=3^3\)
\(\Rightarrow x-1=3\)
\(\Rightarrow x=4\)
Vậy x = 4
A = \(\dfrac{5}{9}\cdot\left(\dfrac{1}{7}+\dfrac{1}{7}+\dfrac{3}{7}\right)\)
=\(\dfrac{5}{9}\cdot\dfrac{5}{7}=\dfrac{25}{63}\)
a. 37-7.(x+1)=40-8.3
37 - 7(x+1) = 16
7(x+1) = 21
x+1 = 3
x=2
b. (x+5).3=11=10+(3+4).4
(sao có 2 dấu bằng, dấu nào là dấu cộng do viết nhầm ???)
c. 25-5.3+4.10=100-5.x
50 = 100 - 5x
5x = 50
x=10
d. 36+2.(x-7)=12+8.(3+5)-36
36 + 2(x-7) = 40
2(x-7) = 4
x-7 =2
x=9
e. 3.(x+7)-9=11.5-5-8
3(x+7) - 9 = 42
3(x+7) = 51
x+7 = 17
x=10
\(\frac{2^5.3^7-2^5.3^6}{2^5.3^6}=\frac{2^5.3^6.\left(3-1\right)}{2^5.3^6}=2\)
35.3x=9.35
⇒ 35+x=32.35
⇒ 35+x=37
⇒ 5+x=7
⇒ x=7-5
⇒ x=2
35.3x=9.35
⇒ 35+x=32.35
⇒ 35+x=37
⇒ 5+x=7
⇒ x=7-5
⇒ x=2