tìm y
y chia 3 phần 8 bằng 12 phần 7
y trừ 7 phần 2 bằng 1
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11 tháng 8 2015
a) \(\frac{3}{2}-\frac{5}{6}:x=\frac{5}{15}-\frac{3}{15}\)
\(\Leftrightarrow\frac{3}{2}-\frac{5}{6}:x=\frac{2}{15}\)
\(\Leftrightarrow\frac{5}{6}:x=\frac{3}{2}-\frac{2}{15}\)
\(\Leftrightarrow\frac{5}{6}:x=\frac{41}{30}\)
\(\Leftrightarrow x=\frac{5}{6}:\frac{41}{30}\)
\(\Leftrightarrow x=\frac{25}{41}\)
b) \(x-\frac{6}{7}.\frac{14}{8}=\frac{1}{2}-\frac{2}{5}\)
\(\Leftrightarrow x-\frac{3}{2}=\frac{1}{10}\)
\(\Leftrightarrow x=\frac{1}{10}+\frac{3}{2}\)
\(\Leftrightarrow x=\frac{8}{5}\)
c) \(x:\frac{6}{5}+\frac{2}{3}=\frac{7}{3}\)
\(\Leftrightarrow x:\frac{6}{5}=\frac{7}{3}-\frac{2}{3}\)
\(\Leftrightarrow x:\frac{6}{5}=\frac{5}{3}\)
\(\Leftrightarrow x=\frac{5}{3}.\frac{6}{5}\)
\(\Leftrightarrow x=2\)
D
11 tháng 6 2018
1,
\(\frac{25}{12}+\left(\frac{-4}{12}\right)=\frac{7}{4}\)
\(\frac{-10}{8}+\frac{15}{4}=\frac{5}{2}\)
\(\frac{3}{8}+\frac{-14}{6}=\frac{-47}{24}\)
\(\frac{350}{150}+\left(\frac{-200}{360}\right)=\frac{16}{9}\)
\([\frac{5}{8}+\left(\frac{-3}{4}\right)]+\frac{15}{6}=\frac{-1}{8}+\frac{15}{6}=\frac{19}{8}\)
\(\frac{7}{3}+[\left(\frac{-5}{6}\right)+\left(\frac{-2}{3}\right)]=\frac{7}{3}+\left(\frac{-3}{2}\right)=\frac{5}{6}\)
3 tháng 10 2019
Ta có biểu thức :
\(M=\frac{11}{6}-\frac{5}{6}\div\left(m+\frac{3}{10}\right)\)
a ) Nếu \(m=\frac{1}{2}\) thì \(M=\frac{11}{6}-\frac{5}{6}\div\left(\frac{1}{2}+\frac{3}{10}\right)=\frac{5}{4}\)
b ) Nếu \(M=\frac{5}{3}\) thì
\(\frac{11}{6}-\frac{5}{6}\div\left(m+\frac{3}{10}\right)=\frac{5}{3}\)
\(1\div\left(m+\frac{3}{10}\right)=\frac{5}{3}\)
\(m+\frac{3}{10}=1\div\frac{5}{3}\)
\(m+\frac{3}{10}=\frac{3}{5}\)
\(m=\frac{3}{5}-\frac{3}{10}\)
\(m=\frac{3}{10}\)
TN
14 tháng 6 2021
\(\frac{3}{4}+\frac{5}{9}:\frac{4}{5}=\frac{3}{4}+\frac{5}{9}\times\frac{5}{4}\)
\(=\frac{3}{4}+\frac{25}{36}=\frac{27}{36}+\frac{25}{36}=\frac{27+25}{36}=\frac{52}{36}=\frac{13}{9}\)
\(\frac{7}{19}\times\frac{4}{7}-\frac{7}{19}\times\frac{3}{7}=\frac{7}{19}\times\left(\frac{4}{7}-\frac{3}{7}\right)\)
\(=\frac{7}{19}\times\frac{1}{7}=\frac{1}{19}\)
\(y:\frac{3}{8}=\frac{12}{7}\)
\(y=\frac{12}{7}\times\frac{3}{8}\)
\(y=\frac{9}{14}\)
\(y-\frac{7}{2}=1\)
\(y=1+\frac{7}{2}\)
\(y=\frac{9}{2}\)
y : \(\frac{3}{8}\)= \(\frac{12}{7}\) y - \(\frac{7}{2}\)= 1
y = \(\frac{12}{7}x\frac{3}{8}\) y = 1 + \(\frac{7}{2}\)
y = \(\frac{9}{14}\) y = \(\frac{9}{2}\)