Tìm x biết
a. (3.x + 2 ) . ( x + 1 ) = 140
b. ( 2.x + 3 ) . ( x+5 ) = 165
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`a)4/5:3/x xx2/11=24/165`
`(4/5xx2/11)xx 3/x=8/55`
`8/55xx3/x=8/55`
`3/x=8/55:8/55`
`3/x=1`
`3:x=1`
`x=3:1`
`x=3`
____________________________________________
`b)4/3:x/5=5/13xx4/9`
`4/3:x/5=20/117`
`x/5=4/3:20/117`
`x/5=39/5`
`x=39`
A) 4/5:3/x X 2/11=24/165
\(\dfrac{4}{5}:\dfrac{3}{x}X\dfrac{2}{11}=\dfrac{24}{165}\)
\(\dfrac{3}{x}=\dfrac{24}{165}:\dfrac{4}{5}:\dfrac{2}{11}\)
\(\dfrac{3}{x}=1\)
\(\dfrac{3}{x}=\dfrac{3}{3}\)
=> x=3
B) \(\dfrac{4}{3}:\dfrac{x}{5}=\dfrac{5}{13}x\dfrac{4}{9}\)
\(\dfrac{4}{3}:\dfrac{x}{5}=\dfrac{20}{117}\)
\(\dfrac{x}{5}=\dfrac{4}{3}:\dfrac{20}{117}\)
\(\dfrac{x}{5}=\dfrac{39}{5}\)
=> x = 39
\(\frac{4}{5}\cdot\frac{3}{x}\cdot\frac{2}{11}=\frac{24}{165}\)
\(\frac{3}{x}\) \(=\frac{24}{165}:\frac{2}{11}:\frac{4}{5}\)
\(\frac{3}{x}\) \(=1\)
\(x\) \(=3\)
\(\frac{4}{3}:\frac{x}{5}=\frac{5}{13}\cdot\frac{4}{9}\)
\(\frac{4}{3}:\frac{x}{5}=\frac{20}{117}\)
\(\frac{x}{5}=\frac{4}{3}:\frac{20}{117}\)
\(\frac{x}{5}=\frac{39}{5}\)
\(x=39\)
a,\(\Rightarrow x:3=1,56+7,2\)
\(\Rightarrow x:3=8,76\)
\(\Rightarrow x=8,76\cdot3\)
\(\Rightarrow x=26,28\)
b,\(\Rightarrow x:6=1,248:4\)
\(\Rightarrow x:6=0,312\)
\(\Rightarrow x=0,312\cdot6\)
\(\Rightarrow x=1,872\)
c,(x+x+x+x+...+x)+(2+5+8+....+29)=165
10 số hạng 10 số hạng
\(\Rightarrow\)10x+(29+2)*10:2=165
\(\Rightarrow\)10x+155=165
\(\Rightarrow10x=165-155\)
\(\Rightarrow10x=10\)
\(\Rightarrow x=10:10\)
\(\Rightarrow x=1\)
a) 2y - 12y = 0
\(\Rightarrow\) y ( 2-12) = 0
\(\Rightarrow\) y . (-10) =0
\(\Rightarrow\) y = 0 : (-10) = 0
b) (y-7)(y-8) = 0
\(\Rightarrow\orbr{\begin{cases}y-7=0\\y-8=0\end{cases}\Rightarrow\orbr{\begin{cases}y=0+7\\y=0+8\end{cases}\Rightarrow}\orbr{\begin{cases}y=7\\y=8\end{cases}}}\)
c) x + x.2+x.3+x.4+...+x.10 = 165
\(\Rightarrow\) x ( 1+2+3+.....+8+9+10) = 165
\(\Rightarrow\)x . \(\frac{\left(1+10\right).10}{2}\)=165
\(\Rightarrow\) x . 55 = 165
\(\Rightarrow x=\frac{165}{55}=3\)
Can you k for me ,Lê Thị Kim Chi!
a) \(2y-12y=0\)
\(\Leftrightarrow-10y=0\)
\(\Leftrightarrow y=0:\left(-10\right)\)
\(\Leftrightarrow y=0\)
b) \(\left(y-7\right)\left(y-8\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}y-7=0\\y-8=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}y=0+7\\y=0+8\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}y=7\\y=8\end{cases}}\)
c) \(x+x.2+x.3+......+x.10=165\)
\(\Leftrightarrow x.\left(1+2+3+.....+10\right)=165\)
\(\Leftrightarrow x.55=165\)
\(\Leftrightarrow x=165:55\)
\(\Leftrightarrow x=3\)
a: -x+5/9=-1/3
nên x=5/9+1/3=5/9+3/9=8/9
b: \(\Leftrightarrow\dfrac{1}{5}+\dfrac{1}{10}+\dfrac{11}{15}< x< \dfrac{1}{2}+\dfrac{13}{12}+\dfrac{1}{3}\)
=>31/30<x<23/12
mà x là số nguyên
nên \(x\in\varnothing\)
c: x+5/3=1/81
nên x=1/81-135/81=-134/81