128-[68+8(37-35mũ 2 ]:4
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Lời giải:
$128-[68+8(37-35)^2]:4=128-(68+8.2^2):4$
$=128-100:4=128-25=103$
128 - [68 + 8(37 - 35)2 ] : 4
= 128 - [68 + 8.22 ] : 4
= 128 - [68 + 32] : 4
= 128 - 100 : 4
= 128 - 25
= 103
\(128.\left[68+8\left(37-35\right)^2\right]\)
\(=128\left[68+8.2^2\right]\)
\(=128\left[68+32\right]\)
\(=128.100\)
\(=12800\)
128[68+8(37-35)^2]
=128[68+8.2^2]
=128[68+8.4]
=128[68+32]
=128.100
=12800
\(a.3.52+15.22-26:2\\ 156+330-13\\ =486-13\\ =473\)
\(b.53.2-100:4+23.5\\ =106-25+115\\ =81+115\\ =196\)
A)3.52+15.22-26:2
= 3.25+15x4-26:2
= 75+60-13
=122
B)52.9+50.2-33.3
=125.2-25+8
=225+40.
=265
C)62:9+50.2-33.3
=36:9+100-27.3
=7+100-81
=7+19
= 26
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a , 2014+(-1999)+1986+175+(-2001) = (2014+1986)+(-1999+-2001)+175
= 4000 + -4000 +175
= 175
roi tu lam nhe minh ban roi phai day
nice to meet you
a: \(=47-\left[\left(45\cdot16-25\cdot12\right):14\right]\)
\(=47-30=17\)
b: \(=50-\left[6+34\right]\)
=50-40
=10
a, 68 + 42 x 5 - 625 : 25
= 68 + 210 - 25
= 278 - 25
= 253
b, 15 x { 37 + 8 + 20 } + 15 x { 13 + 22 }
= 15 x 65 + 15 x 35
= 15 x { 65 + 35 }
= 15 x 100
= 1500
c, 125 x 56 x 3
= 7000 x 3
= 21000
d, 249 - { 49 - 100 }
= 249 - 49 + 100
= 200 + 100
= 300
e, 1/2 + 1/4 + 1/ 8 + 1/32 + 1/64 + 1/128
= 1/1 - 1/2 + 1/2 - 1/4 + 1/4 - 1/8 + 1/8 - 1/32 + 1/32 - 1/64 + 1/64 - 1/128
= 1/1 - 1/128
= 127/128
A, \(68+42\times5-625:25\)
= 68 +210 - 25
= 278 - 25
= 253
B,\(15\times\left(37+8+20\right)+15\times\left(13+22\right)\)
= \(15\times\left(37+8+20+13+22\right)\)
=\(15\times100\)
= 1500
C,\(125\times56\times3\)
= \(125\times8\times7\times3\)
= \(1000\times21\)
= 21000
D, 249 - { 49 - 100 }
= 249 - 49 -100
= 200 - 100
= 100
E, \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}\)(mình sửa lại đề chút xíu nha, nó cứ bị sai sai sao ấy)
= \(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+\frac{1}{16}-\frac{1}{32}+\frac{1}{32}-\frac{1}{64}+\frac{1}{64}-\frac{1}{128}\)
= \(1-\frac{1}{128}\)
=\(\frac{128}{128}-\frac{1}{128}\)
= \(\frac{127}{128}\)
128-[68+8(37-35mũ 2 ]:4
=128-[68+8(37-1225]:4
=128-[68+8.(-1188)]:4
=128-[68+(-9504)]:4
=128-(-9436):4
=128-(-2359)
=2487
128-[68+8(37-35mũ 2 ]:4
=128-[68+8(37-1225]:4
=128-[68+8.(-1188)]:4
=128-[68+(-9504)]:4
=128-(-9436):4
=128-(-2359)
=2487