-5/8 +14/8-3/8+2/9-1/2022
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(9x - 2³) : 5=2
3x . [ 8² -2 .( 2⁵-1)]=2022
[ 3⁴ - ( 8² +14) :13] . x=5²+10²
2²: ( 6x - 3²) - 3 = 33
(9\(x\) - 23) : 5 = 2
9\(x\) - 8 = 2 x 5
9\(x\) - 8 = 10
9\(x\) = 18
\(x\) = 2
3\(x\) .(82 - 2.(25 - 1)] = 2022
3\(x\) .(64 - 2.31) = 2022
3\(x\).(64 - 62) = 2022
3\(x\).2 = 2022
\(x\) = 2022 : 2
\(x\) = 1011
A=1−2−3+4−5−6+7−8−9+....+2020−2021−2022D=1-2-3+4-5-6+7-8-9+....+2020-2021-2022
A =(1−2−3)+(4−5−6)+(7−8−9)+....+(2020−2021−2022)D=(1-2-3)+(4-5-6)+(7-8-9)+....+(2020-2021-2022)
A=(−4)+(−7)+(−10)+.....+(−2023)D=(-4)+(-7)+(-10)+.....+(-2023)
A=[(2023−4):3+1].[(−2023−4):2]D=[(2023-4):3+1].[(-2023-4):2]
A=674.(−1013,5)D=674.(-1013,5)
A=−683099
A=1−2−3+4−5−6+7−8−9+....+2020−2021−2022D=1-2-3+4-5-6+7-8-9+....+2020-2021-2022
A =(1−2−3)+(4−5−6)+(7−8−9)+....+(2020−2021−2022)D=(1-2-3)+(4-5-6)+(7-8-9)+....+(2020-2021-2022)
A=(−4)+(−7)+(−10)+.....+(−2023)D=(-4)+(-7)+(-10)+.....+(-2023)
A=[(2023−4):3+1].[(−2023−4):2]D=[(2023-4):3+1].[(-2023-4):2]
A=674.(−1013,5)D=674.(-1013,5)
A=−683099
a:
Sửa đề: \(S=1-3+5-7+...+2021-2023+2025\)
Từ 1 đến 2025 sẽ có:
\(\dfrac{2025-1}{2}+1=\dfrac{2024}{2}+1=1013\left(số\right)\)
Ta có: 1-3=5-7=...=2021-2023=-2
=>Sẽ có \(\dfrac{1013-1}{2}=\dfrac{1012}{2}=506\) cặp có tổng là -2 trong dãy số này
=>\(S=506\cdot\left(-2\right)+2025=2025-1012=1013\)
b: \(S=1+2-3-4+5+6-7-8+...+2021+2022-2023-2024\)
Từ 1 đến 2024 là: \(\dfrac{\left(2024-1\right)}{1}+1=2024\left(số\right)\)
Ta có: 1+2-3-4=5+6-7-8=...=2021+2022-2023-2024=-4
=>Sẽ có \(\dfrac{2024}{4}=506\) cặp có tổng là -4 trong dãy số này
=>\(S=506\cdot\left(-4\right)=-2024\)
S = (1 + 2 - 3 - 4) + (5 + 6 - 7 - 8) + ... + (2017 + 2018 - 2019 - 2020) + (2021 - 2022 + 2023) (nhóm các số hạng vào 505 nhóm, mỗi nhóm có 4 số hạng, thừa ra 3 số hạng nhóm vào 1 nhóm là 506 nhóm)
S = -4 + (-4) + ... + (-4) + 2022
S = -4 x 505 + 2022
S = -2022 + 2022
S = 0
S = (1 + 2 - 3 - 4) + (5 + 6 - 7 - 8) + ... + (2017 + 2018 - 2019 - 2020) + (2021 - 2022 + 2023) (nhóm các số hạng vào 505 nhóm, mỗi nhóm có 4 số hạng, thừa ra 3 số hạng nhóm vào 1 nhóm là 506 nhóm)
S = -4 + (-4) + ... + (-4) + 2022
S = -4 x 505 + 2022
S = -2022 + 2022
S = 0
a, \(\frac{-3}{7}+\frac{5}{13}-\frac{4}{7}+\frac{8}{13}\)
\(=\frac{-3}{7}-\frac{4}{7}+\frac{5}{13}+\frac{8}{13}\)
\(=-\frac{7}{7}+\frac{13}{13}=-1+1=0\)
b, \(\frac{-5}{14}-\frac{2}{-14}+\frac{1}{8}+\frac{1}{8}\)
\(=\frac{-5}{14}+\frac{2}{14}+\frac{1}{8}+\frac{1}{8}\)
\(=-\frac{3}{14}+\frac{1}{4}=\frac{1}{28}\)
c,\(-\frac{5}{13}-\left(\frac{3}{5}+\frac{3}{13}-\frac{4}{10}\right)\)
\(=-\frac{5}{13}-\frac{3}{13}-\frac{3}{5}+\frac{4}{10}\)
\(=-\frac{8}{13}-\frac{3}{5}+\frac{4}{10}=-\frac{79}{65}+\frac{4}{10}=-\frac{53}{65}\)
d, \(\left[\left(\frac{1}{8}-\frac{9}{7}+\frac{4}{6}-\frac{12}{7}-\frac{1}{2}\right)+\frac{5}{9}\right]\)
\(=\left[\left(\frac{1}{8}-\frac{9}{7}+\frac{2}{3}-\frac{12}{7}-\frac{1}{2}\right)+\frac{5}{9}\right]\)
\(=\left[\left(\frac{1}{8}-\frac{1}{2}-\frac{9}{7}-\frac{12}{7}+\frac{2}{3}\right)+\frac{5}{9}\right]\)
\(=-\frac{65}{24}+\frac{5}{9}=-2\frac{11}{72}\)
\(A=8\left(1+8\right)+8^3\left(1+8\right)+...+8^{2021}\left(1+8\right)\)
\(=8.9+8^3.9+...+8^{2021}.9=9\left(8+8^3+...+8^{2021}\right)⋮9\)
a) Ta có: \(\dfrac{-5}{7}\left(\dfrac{14}{5}-\dfrac{7}{10}\right):\left|-\dfrac{2}{3}\right|-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)+\dfrac{10}{3}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)\)
\(=\dfrac{-5}{7}\cdot\dfrac{3}{2}\cdot\dfrac{21}{10}-\dfrac{3}{4}\cdot\dfrac{56}{3}+\dfrac{10}{3}\cdot\dfrac{8}{15}\)
\(=\dfrac{-9}{4}-14+\dfrac{16}{9}\)
\(=\dfrac{-1621}{126}\)
b) Ta có: \(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)
\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{-3}{2}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)
\(=\dfrac{3}{4}-1-\dfrac{11}{5}\)
\(=-\dfrac{49}{20}\)
1: =1-1+5-5+7-7+8-8=0
2: =14-23+5+14-5+23+17
=28+17=45
3: =12-12+9-9+14-44-3=-33
4: =22-8-8-12+4
=22-16-8
=-2
Bài \(1\)
\(1)\) \(1-5+7-8+4-1+5-7+8\)
\(=(1-1)+(5-5)+(7-7)+(8-8)\)
\(=0+0+0+0\)
\(=0\)
\(2)\) \(14-23+(5+14)-(5-23)+17\)
\(=14-23+5+14-5+23+17\)
\(=(14+14)+(23-23)+(5-5)+17\)
\(=28+17\)
\(=45\)
\(3)\) \(12-44+9-3+14-19-9-12\)
\(=(12-12)+(9-9)+(14-44)+3\)
\(=-30+3\)
\(=-33\)
\(4)\) \(22-(4-8+12)+(-8-12+4)\)
\(=22-4+8-12-8-12+4\)
\(=22+(4+4)+(8-8)+(-12-12)\)
\(=22-24\)
\(=-2\)
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`-5/8 + 14/8 - 3/8 + 2/9 - 1/2022`
`=-5/8 + 7/4 - 3/8 + 2/9 - 1/2022`
`=(-5/8 -3/8) + 7/4 + 2/9 - 1/2022`
`=-8/8 + 7/4 + 2/9 - 1/2022`
`=-1 + 7/4 + 2/9 - 1/2022`
`=-4/4 + 7/4 + 2/9 - 1/2022`
`=3/4 + 2/9 - 1/2022`
`=35/36 - 1/2022`
`=0.97172766238`
\(\approx0,98\)