1/3+5/6+1/12+1/24+1/4
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14 tháng 2 2022
a: \(=\dfrac{-5}{8}+\dfrac{7}{12}=\dfrac{-15}{24}+\dfrac{14}{24}=\dfrac{-1}{24}\)
b: \(=\dfrac{3}{4}-\dfrac{5}{6}+\dfrac{11}{12}=\dfrac{9}{12}-\dfrac{10}{12}+\dfrac{11}{12}=\dfrac{10}{12}=\dfrac{5}{6}\)
c: \(=\dfrac{6}{36}-\dfrac{1}{36}=\dfrac{5}{36}\)
d: \(=\dfrac{5}{12}+\dfrac{5}{12}=\dfrac{10}{12}=\dfrac{5}{6}\)
e: \(=\dfrac{-8}{56}-\dfrac{7}{56}=\dfrac{-15}{56}\)
f: \(=\dfrac{-5}{15}+\dfrac{3}{25}=\dfrac{-25}{75}+\dfrac{9}{75}=\dfrac{-16}{75}\)
DT
0
VK
0
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
17 tháng 8 2023
a, \(\dfrac{1}{2}\) - ( - \(\dfrac{1}{3}\) ) + \(\dfrac{1}{23}\) + \(\dfrac{1}{6}\)
= \(\dfrac{5}{6}\) + \(\dfrac{1}{23}\) + \(\dfrac{1}{6}\)
= 1 + \(\dfrac{1}{23}\)
= \(\dfrac{24}{23}\)
b, \(\dfrac{11}{24}\) - \(\dfrac{5}{41}\) + \(\dfrac{13}{24}\) + 0,5 - \(\dfrac{36}{41}\)
= (\(\dfrac{11}{24}\) + \(\dfrac{13}{24}\)) - ( \(\dfrac{5}{41}\) + \(\dfrac{36}{41}\)) + 0,5
= 1 - 1 + 0,5
= 0,5
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
17 tháng 8 2023
c,\(-\dfrac{1}{12}-\left(\dfrac{1}{6}-\dfrac{1}{4}\right)\)
=\(-\dfrac{1}{12}-\left(-\dfrac{1}{12}\right)\)
=0
d, \(\dfrac{1}{6}-\left[\dfrac{1}{6}-\left(\dfrac{1}{4}+\dfrac{9}{12}\right)\right]\)
= \(\dfrac{1}{6}-\left[\dfrac{1}{6}-1\right]\)
= \(\dfrac{1}{6}-\left(-\dfrac{5}{6}\right)\)
= 1
24 tháng 1 2022
a) \(\dfrac{2}{5}+\dfrac{2}{3}+\dfrac{3}{4}=\dfrac{24}{60}+\dfrac{40}{60}+\dfrac{45}{60}=\dfrac{24+40+45}{60}=\dfrac{109}{60}\)
b) \(\dfrac{1}{3}+\dfrac{5}{12}+\dfrac{5}{6}=\dfrac{4}{12}+\dfrac{5}{12}+\dfrac{10}{12}=\dfrac{4+5+10}{12}=\dfrac{19}{12}\)
c) \(\dfrac{1}{6}+\dfrac{5}{24}+\dfrac{2}{3}=\dfrac{4}{24}+\dfrac{5}{24}+\dfrac{16}{24}=\dfrac{4+5+16}{24}=\dfrac{25}{24}\)
GN
GV Nguyễn Trần Thành Đạt
Giáo viên
23 tháng 6 2023
\(a,\dfrac{3}{4}+\dfrac{-5}{24}=\dfrac{3\times6}{24}+\dfrac{-5}{24}=\dfrac{18}{24}-\dfrac{5}{24}=\dfrac{13}{24}\\ b,\dfrac{-3}{5}+\dfrac{1}{15}=\dfrac{-3\times3}{15}+\dfrac{1}{15}=\dfrac{-9}{15}+\dfrac{1}{15}=-\dfrac{8}{15}\\ c,\dfrac{-5}{6}+\dfrac{1}{12}=\dfrac{-5\times2}{12}+\dfrac{1}{12}=\dfrac{-10}{12}+\dfrac{1}{12}=-\dfrac{9}{12}=-\dfrac{3}{4}\)
VN
Võ Ngọc Phương
VIP
23 tháng 6 2023
a, \(\dfrac{3}{4}+\dfrac{-5}{24}=\dfrac{18}{24}+\dfrac{-5}{24}=\dfrac{13}{24}\)
b, \(\dfrac{-3}{5}+\dfrac{1}{15}=\dfrac{-9}{15}+\dfrac{1}{15}=\dfrac{-8}{15}\)
c, \(\dfrac{-5}{6}+\dfrac{1}{12}=\dfrac{-10}{12}+\dfrac{1}{12}=\dfrac{-9}{12}=\dfrac{-3}{4}\)
\(\dfrac{1}{3}+\dfrac{5}{6}+\dfrac{1}{12}+\dfrac{1}{24}+\dfrac{1}{4}\\ =\dfrac{8}{24}+\dfrac{20}{24}+\dfrac{2}{24}+\dfrac{1}{24}+\dfrac{6}{24}\\ =\dfrac{8+20+2+1+6}{24}\\ =\dfrac{37}{24}\)
\(\dfrac{1}{3}+\dfrac{5}{6}+\dfrac{1}{12}+\dfrac{1}{24}+\dfrac{1}{4}\)
\(=\dfrac{8+5\times4+2+1+6}{24}\)
\(=\dfrac{37}{24}\)