(16.17-5) : (16.16+11) + (45.16-17) : (18+45.15) tính nhanh và hợp lý
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tính nhanh
A =19902 -1992.1998
B=20012 -2000.2002
C =20092-2007.2011
D= (37.13-13):(24+37.12)
E = (16.17-5) :(16.16+11)
F= (45.16-17):(28+45.15)
a)\(\frac{16.17-5}{16.16+11}=\frac{16.17-16+11}{16.16+11}\)\(=\frac{16.\left(17-1\right)+11}{16.16+11}=\frac{16.16+11}{16.16+11}=1\)
b) \(\frac{45.16-17}{28+45.15}=\frac{45.\left(15+1\right)-17}{28+45.15}\)\(=\frac{45.15+45-17}{28+45.15}=\frac{45.15+28}{28+45.15}=1\)
c) \(\frac{7256.4375-725}{3650+4375.7255}=\frac{\left(7255+1\right).4375-725}{3650+4375.7255}\)\(=\frac{7255.4375+4375-725}{3650+4375.7255}\)\(=\frac{7255.4375+3650}{3650+4375.7255}=1\)
Câu C nhớ sửa 725 thành 7255 nha !
Bài giải
\(a,\text{ }\frac{16\cdot17-5}{16\cdot16+11}=\frac{16\cdot16+16-5}{16\cdot16+11}=\frac{16\cdot16+11}{16\cdot16+11}=1\)
\(b,\text{ }\frac{45\cdot16-17}{28+45\cdot15}=\frac{45\cdot15+45-17}{45\cdot15+28}=\frac{45\cdot15+28}{45\cdot15+28}=1\)
\(c,\text{ }\frac{7256\cdot4375-725}{3650+4375\cdot7255}=\frac{4375\cdot7255+4375-725}{4375\cdot7255+3650}=\frac{4375\cdot7255+3650}{4375\cdot7255+3650}=1\)
\(=\frac{45.15+45-17}{45.15+58}=\frac{45.15+28}{45.15+58}=???\)
ủa đề sai à ta?
Ta có:
45 . 16 - 17 = 45. (15 +1) - 17
= 45 . 15 + 1.45 - 17
= 45 . 15 + (45 - 17)
= 45 . 15 + 28
vậy \(\dfrac{45.16-17}{45.15+28}=\dfrac{45.15+28}{45.15+28}=1\)
a) \(100:17+53:17=\left(100+53\right):17=153:17=9\)
b) \(1895:5-1745:5=\left(1895-1745\right):5=150:5=30\)
c) \(\left(864.48-432.96\right):\left(864.48.432\right)\)
\(=\left(864.48-432.2.48\right):\left(864.48.432\right)\)
\(=\left(864.48-864.48\right):\left(864.48.432\right)\)
\(=0:\left(864.48.432\right)\)
\(=0\)
d) \(\left(16.17-5\right):\left(16.16+11\right)\)
\(=\left[16.\left(16+1\right)-5\right]:\left(16.16+11\right)\)
\(=\left[16.16+16-5\right]:\left(16.16+11\right)\)
\(=\left[16.16+11\right]:\left(16.16+11\right)\)
\(=1\)
_Chúc bạn học tốt_
Ta có: \(\dfrac{16.17-5}{16.16+11}\)= \(\dfrac{16.\left(16+1\right)-5}{16.16+11}\)
= \(\dfrac{16.16+16-5}{16.16+11}\)= \(\dfrac{16.16+11}{16.16+11}\)= 1
\(\dfrac{16.17-5}{16.16+11}\) = \(\dfrac{16.\left(16+1\right)-5}{16.16+11}\) = \(\dfrac{16.16+16-5}{16.16+11}\) =\(\dfrac{16.16+11}{16.16+11}=1\)
a) \(\left(56.27+56.35\right):62\)
\(=56.\left(27+35\right):62\)
\(=56.62:62\)
\(=56\)
b) \(3\frac{2}{7}.12\frac{1}{2}-3\frac{2}{7}.5\frac{1}{2}+1\frac{1}{2}:\frac{3}{4}\)
\(=3\frac{2}{7}.\left(12\frac{1}{2}-5\frac{1}{2}\right)+\frac{3}{2}.\frac{4}{3}\)
\(=\frac{23}{7}.7+2\)
\(=23+2\)
\(=25\)
c) \(\frac{16.17-5}{16.16+11}\)
\(=\frac{16.\left(16+1\right)-5}{16.16+11}\)
\(=\frac{16.16+16-5}{16.16+11}\)
\(=\frac{16.16+11}{16.16+11}\)
\(=1\)
\(\frac{16.17-5}{16.16+11}=\frac{16.16+16-5}{16.16+11}=\frac{16.16+11}{16.16+11}=1\)