1.15 x 42 x 3 / 7 x 9 x 5 =
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\(\frac{2}{3}:\frac{x}{5}+\frac{5}{7}=\frac{2}{7}:\frac{3}{5}+\frac{10}{9}\)
\(\Rightarrow\frac{2}{3}:\frac{x}{5}+\frac{5}{7}=\frac{2}{7}.\frac{5}{3}+\frac{10}{9}\)
\(\Rightarrow\frac{2}{3}:\frac{x}{5}+\frac{5}{7}=\frac{10}{21}+\frac{10}{9}\)
\(\Rightarrow\frac{2}{3}:\frac{x}{5}+\frac{5}{7}=\frac{100}{63}\)
\(\Rightarrow\frac{2}{3}:\frac{x}{5}=\frac{100}{63}-\frac{5}{7}\)
\(\Rightarrow\frac{2}{3}:\frac{x}{5}=\frac{55}{63}\)
\(\Rightarrow\frac{x}{5}=\frac{2}{3}:\frac{55}{63}\)
\(\Rightarrow\frac{x}{5}=\frac{2}{3}.\frac{63}{55}\)
\(\Rightarrow\frac{x}{5}=\frac{42}{55}\)
\(\Rightarrow x=\frac{42.5}{55}=\frac{42}{11}\)
Nên ta chọn đáp án D là đáp án đúng!
( trong bài có dấu . tức là dấu dấu nhân bn nhé )
2/3 : x/5 + 5/7 = 2/7 : 3/5 + 10/9
2/3 : x/5 + 5/7 = 10/21 + 10/9
2/3 : x/5 + 5/7 = 100/63
2/3 : x/5 = 100/63 - 5/7
2/3 : x/5 = 55/63
2/3 . 5/x= 55/63
=) 5/x = 55/63 : 2/3
=) 5/x = 55/42
ta có : a/b = c/d =) a.d=b.c
(=) 55.x = 5.42
55.x = 210
=) x = 210 : 55 = 42/11
vậy đáp án đúng là D
chúc bn học tốt
Học sinh nhẩm và ghi kết quả như sau:
6 x 9 = 54
28 : 7 = 4
7 x 7 = 49
56 : 7 = 8
7 x 8 = 56
36 : 6 = 6
6 x 3 = 18
48 : 6 = 8
6 x 5 = 30
42 : 7 = 6
7 x 5 = 35
40 : 5 = 8
e) x-[42+(-28)]=-8
=> x-14=-8
=> x=-8+14
=> x=-6
f) |x-3|=|5|+|-7|
=> |x-3|=5+7=12
=> x-3=12 hoặc x-3=-12
=> x=12+3 hoặc x=-12+3
=> =15 hoặc x=-9
h) 9x-1=9
=> 9x=9+1=10
=> x=10/9
g) 3x=9
=> x=9:3=3
a, X = 273
b, X = 156
c, X = 4
d, X = 505
e, X = \(\frac{37}{245}\)
a) x(x - 5) - 4x + 20 = 0
\(\Leftrightarrow\) x(x - 5) - (4x + 20)
\(\Leftrightarrow\) x(x - 5) - 4(x - 5) = 0
\(\Leftrightarrow\) (x - 5)(x - 4)
Khi x - 5 = 0 hoặc x - 4 = 0
\(\Leftrightarrow\) x = 5 \(\Leftrightarrow\) x = 4
Vậy S = \(\left\{5;4\right\}\)
b) x(x + 6) - 7x - 42 = 0
\(\Leftrightarrow\) x(x + 6) - (7x - 42) = 0
\(\Leftrightarrow\) x(x + 6) - 7(x + 6) = 0
\(\Leftrightarrow\) (x + 6)(x - 7) = 0
Khi x - 6 = 0 hoặc x - 7 = 0
\(\Leftrightarrow\) x = 6 \(\Leftrightarrow\) x = 7
Vậy S = \(\left\{6;7\right\}\)
c) x3 - 5x2 - x + 5 = 0
\(\Leftrightarrow\) (x3 - 5x2) - (x + 5) = 0
\(\Leftrightarrow\) x2 (x - 5) - (x - 5) = 0
\(\Leftrightarrow\) (x - 5)(x2 - 1) = 0
\(\Leftrightarrow\) (x - 5)(x - 1)(x + 1) = 0
Khi x - 5 = 0 hoặc x - 1 = 0 hoặc x + 1 = 0
\(\Leftrightarrow\) x = 5 \(\Leftrightarrow\) x = 1 \(\Leftrightarrow\) x = -1
Vậy S = \(\left\{5;1;-1\right\}\)
d) 4x2 - 25 - (2x - 5)(3x + 7) = 0
\(\Leftrightarrow\) (2x)2 - 52 - (2x - 5)(3x + 7) = 0
\(\Leftrightarrow\) (2x - 5)(2x + 5) - (2x - 5)(3x + 7) = 0
\(\Leftrightarrow\) (2x - 5) \([\left(2x+5\right)-\left(3x+7\right)]\) = 0
\(\Leftrightarrow\) (2x - 5) ( 2x + 5 - 3x + 7) = 0
\(\Leftrightarrow\) (2x - 5)( -x + 12) = 0
Khi 2x - 5 = 0 hoặc -x + 12 = 0
\(\Leftrightarrow\) 2x = 5 \(\Leftrightarrow\) -x = -12
\(\Leftrightarrow\) x = \(\dfrac{5}{2}\) \(\Leftrightarrow\) x = 12
Vậy S = \(\left\{\dfrac{5}{2};12\right\}\)
e) x3 + 27 + (x + 3)(x - 9) = 0
\(\Leftrightarrow\) x3 - 33 + (x + 3)(x - 9) = 0
\(\Leftrightarrow\) (x - 3)(x2 - 3x + 9) + (x + 3)(x - 9) = 0
\(\Leftrightarrow\) (x - 3) \(\left[\left(x^2-3x+9\right)+\left(x-9\right)\right]\) = 0
\(\Leftrightarrow\) (x - 3) ( x2 - 3x + 9 + x - 9) = 0
\(\Leftrightarrow\) (x - 3)(x2 - 2x) = 0
\(\Leftrightarrow\) (x - 3)x(x - 2)
Khi x - 3 = 0 hoặc x = 0 hoặc x - 2 = 0
\(\Leftrightarrow\) x = 3 \(\Leftrightarrow\) x = 2
Vậy S = \(\left\{3;0;2\right\}\)
Chúc bạn học tốt
a) Ta có: \(x\left(x-5\right)-4x+20=0\)
\(\Leftrightarrow\left(x-5\right)\left(x-4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=5\\x=4\end{matrix}\right.\)
b) Ta có: \(x\left(x+6\right)-7x-42=0\)
\(\Leftrightarrow x\left(x+6\right)-7\left(x+6\right)=0\)
\(\Leftrightarrow\left(x+6\right)\left(x-7\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-6\\x=7\end{matrix}\right.\)
a) 23,5 x 34 + 45 x 23,5 + 3 x 23,5 x 7
= 23,5 x (34 + 45 + 3 x 7)
= 23,5 x (34 + 45 + 21)
=23,5 x 100
= 235.
b) 126 x 56 + 252 x 0,5 x 35 + 42 x 3 x 9
= 42 x 3 x 56 + 126 x 35 + 42 x 3 x 9
= 42 x 168 + 42 x 3 x 35 + 42 x 3 x 9
= 42 x 168 + 42 x 105 + 42 x 27
= 42 x (168 + 105 + 27)
= 42 x 300
= 12600
`@` `\text {Ans}`
`\downarrow`
\(x\div\dfrac{1}{5}+x\div\dfrac{1}{7}+x\div\dfrac{1}{9}=42\)
\(\Rightarrow x\cdot5+x\cdot7+x\cdot9=42\)
\(\Rightarrow x\cdot\left(5+7+9\right)=42\)
\(\Rightarrow x\cdot21=42\)
\(\Rightarrow x=42\div21\)
\(\Rightarrow x=2\)
Vậy, `x = 2.`
x - 5 / 6 = 12 / 7
x = 12 / 7 + 5 / 6
x = 107 / 42
x + 4 / 5 = 8 / 3
x = 8 / 3 - 4 / 5
x = 28 / 15
x * 3 / 9 = 11 / 7 - 3 / 4
x * 3 / 9 = 23 / 28
x = 23 / 28 : 3 / 9
x = 69 / 28
5 / 9 : x = 1 / 3 + 2 / 5
5 / 9 : x = 11 / 15
x = 5 / 9 : 11 / 15
x = 25 / 33
\(1\frac{3}{4}-x=\frac{3}{8}\)
x = 11 / 8
15 , 21 - x = 5 , 6 + 1 , 2
15 , 21 - x = 6 , 8
x = 15 , 21 - 6 , 8
x = 8 , 41
C1 : ( 6 , 75 + 3 , 25 ) * 42
= 10 * 42
= 420
C 2 : ( 6 , 75 + 3 , 25 ) * 42
= 6,75 * 42 + 3,25 * 42
= 283 , 5 + 136 , 5
= 4200
C 1 : ( 9 , 6 - 4 , 2 ) * 3 , 6
= 5 , 4 * 3 , 6
= 19 , 44
C 2 : ( 9 , 6 - 4 , 2 ) * 3 , 6
= 9 , 6 * 3 , 6 - 4 , 2 * 3 , 6
= 34 , 56 - 15 , 12
= 19 , 44
1.15 x 42 x 3 / 7 x 9 x 5 = 931.5
\(\dfrac{1\cdot15\cdot42\cdot3}{7\cdot9\cdot5}=\dfrac{5\cdot3\cdot2\cdot3\cdot7\cdot3}{7\cdot3\cdot3\cdot5}=6\)