100*3+100*25-100*9
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3 : 7 = 3 7 ; 4∶9 = 4 9 ; 23∶6 = 23 6
25 : 100 = 25 100 ; 100∶33 = 100 33 ; 10∶31 = 10 31
a.
(5/11 + 6/11 ) + ( 1/4 +3/4) + ( 6/25 + 9/25)
= 11/11 + 4/4 + 15/25
= 1 +1 + 3/5
= 2+3/5 = 13/5
b.
( 37/100 + 163/100) + (1/8 + 3/8 ) + 19/4 + 1/2
= 200/100 + 4/8 + ( 19/4 + 2/4)
= 2 + 1/2 + 21/4
= 31/4
\(=\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{13}{4}+\dfrac{3}{4}-\dfrac{1}{20}=4+\left(\dfrac{1}{4}-\dfrac{1}{5}-\dfrac{1}{20}\right)=4+0=4\)
ok
\(\frac{9}{100}=>\frac{13}{100}=>\frac{14}{100}=>\frac{15}{100}=>\frac{16}{100}=>\frac{17}{100}=>\frac{20}{100}\)
\(=>\frac{20}{100}=>\frac{24}{100}=>\frac{25}{100}=>\frac{29}{100}=>\frac{31}{100}=>\frac{36}{100}=>\frac{37}{100}=>\frac{67}{100}\)
\(\frac{93}{100}=>\frac{100}{99}=>\frac{100}{94}=>\frac{100}{92}=>\frac{100}{91}=>\frac{100}{89}\)
9/100 13/100 14/100 15/100 16/100 17/100 20/100 24/100 25/100 29/100 31/100 36/100 37/100 67/100 93/100 100/99 100/94 100/92 100/91 100/89.
\(\dfrac{2}{9}+\dfrac{3}{9}=\dfrac{5}{9}\)
\(\dfrac{3}{15}+\dfrac{5}{5}=\dfrac{1}{5}+\dfrac{5}{5}=\dfrac{6}{5}\)
\(\dfrac{4}{25}+\dfrac{3}{100}=\dfrac{16}{100}+\dfrac{3}{100}=\dfrac{19}{100}\)
\(\dfrac{4}{9}+\dfrac{3}{2}=\dfrac{8}{18}+\dfrac{27}{18}=\dfrac{35}{18}\)
cau1 :120-(100+x)=25
100+x=120-25
100+x=95
x=-5
cau2: 5(x+23)+6=96
5(x+23)+6=96
5(x+23)=90
x+23=18
x=-5
cau3: 100-(25+x)=40
25+x=100-40
25+x=60
x=35
cau4: 35-9(x+2)=45
9(x+2)=-10
x+2=-10/9
x=-28/9
\(\dfrac{75^{50}.2^{100}}{100^{50}.9^{25}}=\dfrac{\left(25.3\right)^{50}.2^{100}}{\left(25.4\right)^{50}.\left(3^2\right)^{25}}=\dfrac{25^{50}.3^{50}.2^{100}}{25^{50}.4^{50}.3^{50}}=\dfrac{25^{50}.3^{50}.2^{100}}{25^{50}.\left(2^{2^{ }}\right)^{50}.3^{50}}=\dfrac{25^{50}.3^{50}.2^{100}}{25^{50}.2^{100}.3^{50}}=1\)
tích tớ đi
100*3+100*25-100*9=1900
CHÚC BẠN HỌC GIỎI
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