Tính bằng cách hợp lý:
-1500 - {53. 23 - 11 . [72 - 5 . 23 + 8 .(112 - 121)]}. (-2)
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a=-1500-{1219-11[72-115+8.-9]}.(-2)
A=-1500-{1219-11[-43+-72].(-2)}
A=-1500-{1219-11.-115}.(-2)
A=1500-2484.(-2)
A=1500-(-4968)
A=6468
\(1500-\left\{5^3\cdot2^3-11\left[7^2-5\cdot2^3+8\left(11^2-121\right)\right]\right\}\\ =1500-\left[125\cdot8-11\left(49-5\cdot8+8\cdot0\right)\right]\\ =1500-\left[125\cdot8-11\left(49-40+0\right)\right]\\ =1500-\left(125\cdot8-11\cdot9\right)\\ =1500-\left(1000-99\right)\\ =1500-901\\ =599\)
a)54 : 33 + 6.52
= 54 : 27 + 6.25
= 2 + 150
= 152
b) 45.26 + 45.74 - 1500
= 45.(26 + 74) - 1500
= 45.100 - 1500
= 4500 - 1500
= 3000
c) 125 + 132 + (-125) + (-21)
= [125 + (-125)] + [132 + (-21)]
= 0 + 111
= 111
d) 11 - 13 + 15 - 17 + 19 - 21 + 23 - 25
= -2 + (-2) + (-2) + (-2)
= (-4) + (-2) + (-2)
= (-8)
Câu 5:
a: \(31\cdot\left(-18\right)+31\cdot\left(-81\right)-31\)
\(=31\left(-18-81-1\right)\)
\(=31\cdot\left(-100\right)=-3100\)
b: \(\left(-12\right)\cdot47+\left(-12\right)\cdot52+\left(-12\right)\)
\(=\left(-12\right)\left(47+52+1\right)\)
\(=-12\cdot100=-1200\)
c: \(13\cdot\left(23+22\right)-3\cdot\left(17+28\right)\)
\(=13\cdot45-3\cdot45\)
\(=45\cdot10=450\)
d: \(-48+48\left(-78\right)+48\left(-21\right)\)
\(=48\left(-1-78-21\right)\)
\(=48\left(-100\right)=-4800\)
Câu 4:
a: \(\left(-6-2\right)\left(-6+2\right)=\left(-8\right)\cdot\left(-4\right)=32\)
b: \(\dfrac{\left(7\cdot3-3\right)}{-6}=\dfrac{21-3}{-6}=\dfrac{18}{-6}=-3\)
c: \(\left(-5+9\right)\cdot\left(-4\right)=4\cdot\left(-4\right)=-16\)
d: \(\dfrac{72}{-6\cdot2+4}=\dfrac{72}{-12+4}=\dfrac{72}{-8}=-9\)
= -1500- {1219-11.[72-115+8.(-9)]}.(-2)
= -1500-{1208.[72--115-72]}.(-2)
= -1500-{1208.(-115)].(-2)
= -1500 - (-138920).(-2)
= -1500 - 277840
= - 279340
Lời giải:
$\frac{53}{17}=\frac{51+2}{17}=\frac{51}{17}+\frac{2}{17}=3+\frac{2}{17}$
$>3+\frac{2}{23}=\frac{3.23+2}{23}=\frac{71}{23}$
\(\frac{8}{11}.\frac{14}{23}+\frac{8}{11}.\frac{9}{23}-\frac{8}{11}\)
\(=\frac{8}{11}.\left(\frac{14}{23}+\frac{9}{23}\right)-\frac{8}{11}\)
\(=\frac{8}{11}.1-\frac{8}{11}\)
\(=0\)
`a, 4/9 + 2/5 + 5/9= (4/9 +5/9) + 2/5= 1 + 2/5= 5/5 + 2/5= 7/5`
`b, 6/13 + 5/8 + 7/13=(6/13 + 7/13) + 5/8=1+5/8= 8/8 + 5/8= 13/8`
`c, 5/11 + 6/25 + 66/121 = ( 5/11 + 66/121 ) + 6/25=1 + 6/25 = 25/25 + 6/25 = 31/25`
`d, 1/2 + 1/3 + 1/4 + 1/6 + 1/12 + 1/24= (1/2 + 1/4) +(1/3 + 1/6) + (1/12 + 1/24)= 3/4 + 1/2 + 1/8= 6/8 + 4/8 + 1/8= 11/8`
`@ yl`
1/ 2155-(174+2155)+(-68+174)
=2155-174-2155-68+174
=[2155+(-2155)]+[(-174)+174]+(-68)
=0+0+(-68)
=-68
2/ -25.72+25.21-49.25
=25.(-72)+25.21-49.25
=25.[(-72)+21+(-49)]
=25.(-100)
=-2500
3/ 35.(14-23)-23.(14-45)
=35.14-35.23-23.14-23.45
=(35.14-23.14)+(-35.23-23.45)
=(35.14-23.14)+(-35.23-45.23)
=14.(35-23)+23.(-35-45)
=14.12+23.(-80)
=168+(-1840)
=-1672
4/ 8154-(674+8154)+(-98+674)
=8154-674-8154-98+674
=[8154+(-8154)]+[(-674)+674]+(-98)
=0+0+(-98)
=-98
5/ -25.21+25.72+49.25
=-12.25+25.72+49.25
=25.(-12+72+49)
=25.109
=2725
Đúng thì chọn đúng cho mình nhé !
Mình sửa lại mũ nhé
-1500 - {53. 23 - 11 . [72 - 5 . 23 + 8 .(112 - 121)]}. (-2)
= -1500 - {53. 23 - 11 . [49 - 5 . 8 + 8 .(121 - 121)]}. (-2)
= -1500 - {53. 23 - 11 . [49 - 5 . 8 + 8 .0]}. (-2)
= -1500 - {125. 8- 11 . [49 - 5 . 8 ]}. (-2)
= -1500 - {1000 - 11 . 9}. (-2)
=-1500 - {1000 - 99}. (-2)
=-1500 - 901.(-2)
=-1500 -(-1802)
=302