Tìm x, biết: ( 1 + 3 + 7 + 15 +...+ 255 ) : x = 2
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) \(x+x\times\frac{1}{4}\div\frac{2}{7}+x\div\frac{2}{9}=255\)
\(\Rightarrow x+x\times\frac{1}{4}\times\frac{7}{2}+x\times\frac{9}{2}=255\)
\(\Rightarrow x+x\times\frac{7}{8}+x\times\frac{9}{2}=255\)
\(\Rightarrow x\times\left(1+\frac{7}{8}+\frac{9}{2}\right)=255\)
\(\Rightarrow x\times\frac{51}{8}=255\)
\(\Rightarrow x=255\div\frac{51}{8}\)
\(\Rightarrow x=40\)
Vậy x = 40
b) \(1\frac{1}{21}\div\left(15,75-15\frac{1}{5}\right)+2\frac{1}{12}\div\left(7\frac{3}{4}-7,25\right)\)
\(=\frac{22}{21}\div\left(15,75-\frac{76}{5}\right)+\frac{25}{12}\div\left(\frac{31}{4}-7,25\right)\)
\(=\frac{22}{21}\div\frac{11}{20}+\frac{25}{12}\div\frac{1}{2}\)
\(=\frac{40}{21}+\frac{25}{6}\)
\(=\frac{85}{14}\)
_Chúc bạn học tốt_
X + X x 1/4 : 2/7 + x : 2/9 = 225
X + X x 1/4 x 7/2 + X x 9/2 = 225
X + X x 7/8 + X x 9/2 = 225
X x ( 1 + 7/8 + 9/2 ) = 225
X x 51/8 = 225
X = 225 : 51/8
X = 600/17
Bài 1:
a) \(=\dfrac{8}{15}\left(\dfrac{7}{13}+\dfrac{6}{13}\right)=\dfrac{8}{15}.1=\dfrac{8}{15}\)
b) \(=\dfrac{3.3-7-2.4}{12}=-\dfrac{6}{12}=-\dfrac{1}{2}\)
Bài 2:
\(\dfrac{x}{2,7}=-\dfrac{2}{3,6}\Rightarrow x=\dfrac{\left(-2\right).2,7}{3,6}\Rightarrow x=-\dfrac{3}{2}\)
Bài 3:
\(\dfrac{x}{2}=\dfrac{y}{5}=\dfrac{x+y}{2+5}=-\dfrac{21}{7}=-3\)
\(\Rightarrow\left\{{}\begin{matrix}x=\left(-3\right).2=-6\\y=\left(-3\right).5=-10\end{matrix}\right.\)
Bài 1:
a) \(\dfrac{9}{20}-\dfrac{8}{15}\times\dfrac{5}{12}\)
\(=\dfrac{9}{20}-\dfrac{2}{9}\)
\(=\dfrac{41}{180}\)
b) \(\dfrac{2}{3}\div\dfrac{4}{5}\div\dfrac{7}{12}\)
\(=\dfrac{2}{3}\times\dfrac{5}{4}\times\dfrac{12}{7}\)
\(=\dfrac{5}{6}\times\dfrac{12}{7}\)
\(=\dfrac{10}{7}\)
c) \(\dfrac{7}{9}\times\dfrac{1}{3}+\dfrac{7}{9}\times\dfrac{2}{3}\)
\(=\dfrac{7}{9}\times\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\)
\(=\dfrac{7}{9}\times1\)
\(=\dfrac{7}{9}\)
Bài 2:
a) \(2\times\left(x-1\right)=4026\)
\(\left(x-1\right)=4026\div2\)
\(x-1=2013\)
\(x=2014\)
Vậy: \(x=2014\)
b) \(x\times3,7+6,3\times x=320\)
\(x\times\left(3,7+6,3\right)=320\)
\(x\times10=320\)
\(x=320\div10\)
\(x=32\)
Vậy: \(x=32\)
c) \(0,25\times3< 3< 1,02\)
\(\Leftrightarrow0,75< 3< 1,02\) ( S )
=> \(0,75< 1,02< 3\)
k mk nha