x x 4/15 = 6/7
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1) 3x - 6= 5x + 2
5x - 3x = -6 - 2
2x = -8
x = -4
2) 15 - x = 4x - 5
4x + x = 15 + 5
5x = 20
x = 4
Tương tự như trên
a: \(\dfrac{5}{3}\cdot\dfrac{7}{10}=\dfrac{5}{10}\cdot\dfrac{7}{3}=\dfrac{14}{3}>2\)
\(\dfrac{5}{7}:\dfrac{7}{10}=\dfrac{5}{7}\cdot\dfrac{10}{7}=\dfrac{50}{49}< 2\)
=>\(\dfrac{5}{3}\cdot\dfrac{7}{10}>\dfrac{5}{7}:\dfrac{7}{10}\)
b: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{4}{6}=\dfrac{2}{3}\)
\(\dfrac{8}{9}:\dfrac{4}{3}=\dfrac{8}{9}\cdot\dfrac{3}{4}=\dfrac{8}{4}\cdot\dfrac{3}{9}=\dfrac{2}{3}\)
Do đó: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{8}{9}:\dfrac{4}{3}\)
c: \(\dfrac{5}{11}\cdot\dfrac{33}{15}=\dfrac{5}{15}\cdot\dfrac{33}{11}=\dfrac{3}{3}=1\)
\(\dfrac{6}{17}\cdot\dfrac{34}{25}=\dfrac{34}{17}\cdot\dfrac{6}{25}=2\cdot\dfrac{6}{25}=\dfrac{12}{25}< 1\)
=>\(\dfrac{5}{11}\cdot\dfrac{33}{15}>\dfrac{6}{17}\cdot\dfrac{34}{25}\)
d: \(\dfrac{15}{19}\cdot\dfrac{38}{5}=\dfrac{15}{5}\cdot\dfrac{38}{19}=3\cdot2=6\)
\(\dfrac{15}{16}:\dfrac{3}{8}=\dfrac{15}{16}\cdot\dfrac{8}{3}=\dfrac{15}{3}\cdot\dfrac{8}{16}=\dfrac{5}{2}\)<6
=>\(\dfrac{15}{19}\cdot\dfrac{38}{5}>\dfrac{15}{16}:\dfrac{3}{8}\)
\(\dfrac{x+1}{15}+\dfrac{x+2}{7}+\dfrac{x+4}{4}+6=-6\)
\(\Leftrightarrow\dfrac{28\left(x+1\right)}{420}+\dfrac{60\left(x+2\right)}{420}+\dfrac{105\left(x+4\right)}{420}+\dfrac{6.420}{420}=\dfrac{-6.420}{420}\)
`<=> 28(x+1) +60(x+2)+105(x+4)+6.420=-6.420`
`<=> 28x+28 +60x+120 +105x+420 +2520=-2520`
`<=> 28x+28 +60x+120 +105x+420 +2520+2520=0`
`<=> 193x+5608=0`
`<=> x=-5608:193`
`<=>x= -5608/13`
Vậy pt có nghiệm `x= -5608/13`
1/ Suy ra: -35 + 7x - 2x + 20 = 15
5x - 15 = 15
5x = 30
x = 6
2/ Suy ra: 4x - 20 - 3x - 21 = -19
x - 41 = -19
x = 22
3/ Suy ra: 8 - 4x + 3x - 15 = 14
-7 -x = 14
x = -7 -14
x = -21
4/ Suy ra: 7x - 63 - 30 + 5x = -6 + 11x
7x + 5x - 11x = -6 +63 + 30
x = 87
5/ Suy ra: -21x +35 + 14x - 28 = 28
-21x + 14x = 28 +28 - 35
-7x = 21
x= -3
6/ Suy ra: 20 - 5x + 7x - 14 = -2
2x = -8
x = -4
7/ Suy ra: 4x +15 -5x = 7
-x = -8
x = 8
8/ Suy ra: 5x - 35 +30 -10x = 20
-5x - 5 = 20
-5x = 25
x = -5
9/ Suy ra: 35 - 7x + 5x - 10 = 15
-7x + 5x = 15 +10 - 35
-2x = -10
x = 5
\(8x-48+4x-12-14=-x+4\)
\(\Leftrightarrow12x-75=-x+4\Leftrightarrow13x=79\Leftrightarrow x=\dfrac{79}{13}\)
\(-7\left(8-x\right)-6\left(x+9\right)=20-x\Leftrightarrow-56+7x-6x-54=20-x\)
\(\Leftrightarrow2x=130\Leftrightarrow x=65\)
\(9x-63-80+60x=-7x+15\Leftrightarrow76x=158\Leftrightarrow x=\dfrac{79}{38}\)
\(-96-16x-60+30x=-40x-16\Leftrightarrow54x=140\Leftrightarrow x=\dfrac{70}{27}\)
\(17x-102-14x-28=4x-24-2x+4\Leftrightarrow x=110\)
#) Giải :
a) \(\frac{5}{6}\)x \(\frac{6}{7}\)x \(\frac{7}{8}\): \(\frac{15}{16}\)= \(\frac{5}{8}\): \(\frac{15}{16}\)= \(\frac{5}{8}\)x \(\frac{16}{15}\)= \(\frac{80}{120}\)= \(\frac{4}{5}\)
b) \(\frac{4}{7}\)x \(\frac{7}{10}\)x \(\frac{3}{4}\) : \(\frac{9}{20}\)= \(\frac{2}{5}\)x \(\frac{3}{4}\): \(\frac{9}{20}\)= \(\frac{3}{10}\): \(\frac{9}{20}\)= \(\frac{60}{90}\)= \(\frac{2}{3}\)
#) Chúc bn học tốt :D
\(=\frac{5x6x7}{6x7x8}x\frac{16}{15}\\ =\frac{5}{8}x\frac{16}{15}\\ =\frac{2}{3}\)
b)\(=\frac{4x7x3}{7x10x4}x\frac{20}{9}\\ =\frac{3}{10}x\frac{20}{9}\\ =\frac{2}{3}\)
b)\(=\frac{4x7x3}{7x10x4}x\frac{20}{9}\\ =\frac{3}{10}x\frac{20}{9}\\ =\frac{2}{3}\)
cậu giải thích giùm mình đoạn này với P(x)=x^7-(x+1)x^6+(x+1)x^5-(x+1)x^4+(x+1)x^3-(x+1)x^2+(x+1)x+15
P(x)=x^7-x^7-x^6+x^6+x^5-x^5-x^4+x^4+x^3-x^3-x^2+x^2+x+15
P(x)=x+15=79+15=94
hay giai giup mk may phan nay nhe
cmr cac bieu thuc sau ko phu thuoc vao x:
c)C=x(x^3+x^2-3x-2)-(x^2-2)(x^2+x-1)
e)E=(x+1)(x^2-x+1)-(x-1)(x^2+x+1)
tinh gia tri cua da thuc
b)Q(x)=x^14-10x^13=10x^12-10x^11+...+10x^2-10x+10 voi x=9
c)R(x)=x^4-17x^3+17x^2_17x+20 või=16
d)S(x)=x^10-13x^9+13x^8-13X^7+...+13x^2-13x+10 voi 12
x x 4/15 = 6/7
X = 6/7 : 4/15
x = 45/14
x = 6/7 : 4/15
x = 6/7 x 15/4
x = 24/105 = 8/35