Tính nhanh :
2022/2×4/3÷2022/9÷18/
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A=1−2−3+4−5−6+7−8−9+....+2020−2021−2022D=1-2-3+4-5-6+7-8-9+....+2020-2021-2022
A =(1−2−3)+(4−5−6)+(7−8−9)+....+(2020−2021−2022)D=(1-2-3)+(4-5-6)+(7-8-9)+....+(2020-2021-2022)
A=(−4)+(−7)+(−10)+.....+(−2023)D=(-4)+(-7)+(-10)+.....+(-2023)
A=[(2023−4):3+1].[(−2023−4):2]D=[(2023-4):3+1].[(-2023-4):2]
A=674.(−1013,5)D=674.(-1013,5)
A=−683099
A=1−2−3+4−5−6+7−8−9+....+2020−2021−2022D=1-2-3+4-5-6+7-8-9+....+2020-2021-2022
A =(1−2−3)+(4−5−6)+(7−8−9)+....+(2020−2021−2022)D=(1-2-3)+(4-5-6)+(7-8-9)+....+(2020-2021-2022)
A=(−4)+(−7)+(−10)+.....+(−2023)D=(-4)+(-7)+(-10)+.....+(-2023)
A=[(2023−4):3+1].[(−2023−4):2]D=[(2023-4):3+1].[(-2023-4):2]
A=674.(−1013,5)D=674.(-1013,5)
A=−683099
`2022+2022:1/3+2022+2022:1/5`
`=2022+2022xx3+2022+2022xx5`
`=2022xx(1+3+1+5)`
`=2022xx10=20220`
a: \(\dfrac{4}{9}=\dfrac{4\cdot2}{9\cdot2}=\dfrac{8}{18}< \dfrac{13}{18}\)
b: 34/-4=-8,5
Ta có: 8,5<8,6
=>-8,5>-8,6
=>\(\dfrac{34}{-4}>-8,6\)
c: \(\dfrac{2021}{2022}=1-\dfrac{1}{2022}\)
\(\dfrac{2022}{2023}=1-\dfrac{1}{2023}\)
Ta có: 2022<2023
=>\(\dfrac{1}{2022}>\dfrac{1}{2023}\)
=>\(-\dfrac{1}{2022}< -\dfrac{1}{2023}\)
=>\(-\dfrac{1}{2022}+1< -\dfrac{1}{2023}+1\)
=>\(\dfrac{2021}{2022}< \dfrac{2022}{2023}\)
\(=\dfrac{1}{2}+\dfrac{5}{6}-\dfrac{1}{2}-\dfrac{5}{6}+2022=2022\)
A = ( 2022 x 0,75 + 2022 : 4) - ( 2021 : 0,1 : 10)
= (2022 x 0,75 + 2022 x 0,25) - ( 2021 : 1/10 : 10)
= 2022 x(0,75+0,25) - 2021x 10 : 10
= 2022x 1 - 2021
= 2022 - 2021
=1
a) 17.13+17.42-17.35
=17.(13+42-35)
=17.20=340
b) [25.(18-42)-10]:4+6
=(25.2-10):4+6
=40:4+6=16
c) 36:32+23.22-32.3
=34+25-33
=81+32-27=86
d) B=3.42-22.3
=3.(16-4)
=3.12=36
e)20220+3.[52.10-(23-13)2]
=1+3.(250-100)
=1+450=451
g) 27.77+24.27-27
=27.(77+24-1)
=27.100=2700
h) 5.23+79:77-12020
=40+72-1
=89-1=88
i) 120:{54[50:2+(32-2.4)]}
=120:[54(25+1)]
=120:1404=10/117
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