(50 x 76 - 50 x 24 + 50 x 22) x 2 =
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25 tháng 4 2020
Bài làm
\(\frac{x+52}{21}+\frac{x+51}{22}=\frac{x+50}{23}+\frac{x+49}{24}\)
\(\Leftrightarrow\frac{x+52}{21}+\frac{x+51}{22}+2=\frac{x+50}{23}+\frac{x+49}{24}+2\)
\(\Leftrightarrow\left(\frac{x+52}{21}+1\right)+\left(\frac{x+51}{22}+1\right)=\left(\frac{x+50}{23}+1\right)+\left(\frac{x+49}{24}+1\right)\)
\(\Leftrightarrow\left(\frac{x+52}{21}+\frac{21}{21}\right)+\left(\frac{x+51}{22}+\frac{22}{22}\right)=\left(\frac{x+50}{23}+\frac{23}{23}\right)+\left(\frac{x+49}{24}+\frac{24}{24}\right)\)
\(\Leftrightarrow\frac{x+52+21}{21}+\frac{x+51+22}{22}=\frac{x+50+23}{23}+\frac{x+49+24}{24}\)
\(\Leftrightarrow\frac{x+73}{21}+\frac{x+73}{22}=\frac{x+73}{23}+\frac{x+73}{24}\)
\(\Leftrightarrow\frac{x+73}{21}+\frac{x+73}{22}-\frac{x+73}{23}-\frac{x+73}{24}=0\)
\(\Leftrightarrow\left(x+73\right)\left(\frac{1}{21}+\frac{1}{22}-\frac{1}{23}-\frac{1}{24}\right)=0\)
\(\Leftrightarrow x+73=0\)
\(\Leftrightarrow x=-73\)
Vậy x = -73
# Học tốt #
25 tháng 4 2020
\(\frac{x+52}{21}+\frac{x+51}{22}=\frac{x+50}{23}+\frac{x+49}{24}\)
\(\Leftrightarrow\frac{x+52}{21}+\frac{x+51}{22}-\frac{x+50}{23}-\frac{x+49}{24}=0\)
\(\Leftrightarrow\left(\frac{x+52}{21}+1\right)+\left(\frac{x+51}{22}+1\right)-\left(\frac{x+50}{23}+1\right)-\left(\frac{x+49}{24}+1\right)=0\)
\(\Leftrightarrow\frac{x+73}{21}+\frac{x+73}{22}-\frac{x+73}{23}-\frac{x+73}{24}=0\)
\(\Leftrightarrow\left(x+73\right)\left(\frac{1}{21}+\frac{1}{22}-\frac{1}{23}-\frac{1}{24}\right)=0\)
=> \(x+73=0\left(\frac{1}{21}+\frac{1}{22}-\frac{1}{23}-\frac{1}{24}\ne0\right)\)
<=> x=-73
8 tháng 7 2017
b) 35 x 24 + 35 x 76 +55 x 19 +55 x 91
= 35 x ( 24 + 76 ) + 55 x ( 19 + 91 )
= 35 x100 +55 x 100
= 100 x ( 55 + 35 )
= 90 x 100 =9 000
c) \(6\cdot25\cdot4+4\cdot19\cdot6-2\cdot14\cdot12\)
\(=24\cdot25+24\cdot19-24\cdot14\)
\(=24\left(25+19-14\right)\)
\(=24\cdot30=720\)
d) \(19\cdot64+76\cdot34\)
\(=76\cdot19+76\cdot34\)
\(=76\left(19+34\right)=76\cdot53=4028\)
8 tháng 7 2017
a) 2 x 16 x 50 x 25
= ( 2 x 50 ) x ( 16 x 25 )
= 100 x 400
= 40 000
9 tháng 12 2021
\(n_{H_2}=\dfrac{0,336}{22,4}=0,015(mol)\\ PTHH:Mg+2HCl\to MgCl_2+H_2\\ MgO+2HCl\to MgCl_2+H_2O\\ \Rightarrow n_{Mg}=0,015(mol)\\ \Rightarrow \%_{Mg}=\dfrac{0,015.24}{1,5}.100\%=24\%\\ \Rightarrow \%_{MgO}=100\%-24\%=76\%\)
Chọn A
H9
HT.Phong (9A5)
CTVHS
8 tháng 7 2023
Bài 1:
\(101\cdot125+101\cdot25-101\cdot50\)
\(=101\cdot\left(125+25-50\right)\)
\(=101\cdot100\)
\(=10100\)
Bài 2:
\(76\cdot115+56\cdot24+59\cdot24\)
\(=76\cdot115+24\cdot\left(56+59\right)\)
\(=76\cdot115+24\cdot115\)
\(=115\cdot\left(76+24\right)\)
\(=115\cdot100\)
\(=11500\)
9 tháng 1 2023
b: =2376-376+3425-42
=2000+3383
=5383
c: =3145-145+246+4246+2347-347
=3000+2000+4492
=9492
e: =(72-72):A=0
= [ 50 x ( 76 - 24 + 22)] x 2
= 50 x 74 x 2
= (50 x 2) x 74
= 100 x 74
= 7400.
7400