1125798x2-11245+546832:2+254=?
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\(\frac{254^5+254^6}{254^3.254^2}=\frac{254^3.254^2+254^6}{254^3.254^2}=254^6\)
\(\frac{254^5+254^6}{254^3\cdot254^2}=\frac{254^5\left(1+254\right)}{254^5}=1+254=255\)
C=\(\frac{1}{2}.\frac{2}{3}.......\frac{2016}{2017}\)
C= CÂU HỎI TƯƠNG TỰ
=> đcpm
\(A=\frac{254\cdot399-145}{254+399\cdot253}\)
\(A=\frac{\left(253+1\right)\cdot399-145}{254+399\cdot253}\)
\(A=\frac{253\cdot399+\left(399-145\right)}{254+399\cdot253}\)
\(A=\frac{253\cdot399+254}{254+399\cdot253}\)
\(A=1\)
\(B=\frac{5932+6001\cdot5931}{5932\cdot6001-69}\)
\(B=\frac{5932+6001\cdot5931}{\left(5931+1\right)\cdot6001-69}\)
\(B=\frac{5932+6001\cdot5931}{5931\cdot6001+\left(6001-69\right)}\)
\(B=\frac{5932+6001\cdot5931}{5931\cdot6001+5932}\)
\(B=1\)
\(C=\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot...\cdot\left(1-\frac{1}{2017}\right)\)
\(C=\frac{1}{2}\cdot\frac{2}{3}\cdot...\cdot\frac{2016}{2017}\)
\(C=\frac{1\cdot2\cdot3\cdot...\cdot2016}{2\cdot3\cdot4\cdot...\cdot2017}\)
\(C=\frac{1}{2017}\)
\(a,856:214+1284:214\\ =\left(856+1284\right):214\\ =2140:214=10\\ b,1778:254+3302:254\\ =\left(1778+3302\right):254\\ =5080:254\\ =20\)
Bài 2:
a) \(856
:
214+1284
:
214=\left(856+1284\right)
:
214=2140
:
214=10\)
b) \(1778
:
254+3302
:
254=\left(1778+3302\right)
:
254=5080
:
254=20\)
2251596-11245+273416+254=2240351+273670=2514021
2514021