tính nhanh :
`2/3:5/7xx5/7:2/3+1934`
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2/3 : 5/7 x 5/7 :2/3 +1934 = (2/3 : 2/3)x(5/7 : 5/7) +1934 = 1 x 1 +1934 = 1 +1934 = 1935
a.\(\frac{3}{5}\)\(.\)\(\frac{1195}{1999}\)+ \(\frac{4}{1999}\)\(.\)\(\frac{3}{5}\)= \(\frac{3}{5}.\left(\frac{1195}{1999}+\frac{4}{1999}\right)\)= \(\frac{3}{5}.1\)= \(\frac{3}{5}\)
b. \(\frac{2}{3}\)\(:\)\(\frac{5}{7}\)\(.\)\(\frac{5}{7}\)\(:\)\(\frac{2}{3}\)\(+1934\)= \(\frac{2}{3}\).\(.\)\(\frac{7}{5}\)\(.\)\(\frac{5}{7}\)\(.\)\(\frac{3}{2}\)\(+\)\(1934\)= \(1\)\(+\)\(1934\)= \(1935\)
b) \(\frac{1}{5}:\frac{1}{3}\cdot\frac{\frac{1}{3}}{\frac{1}{5}}+1996\)
\(=\frac{3}{5}\cdot\left(\frac{1}{3}:\frac{1}{5}\right)+1996\)
\(=\frac{3}{5}\cdot\frac{5}{3}+1996\)
\(=1+1996=1997\)
a) \(\frac{2}{3}:\frac{5}{7}\cdot\frac{5}{7}\cdot\frac{2}{3}+1934\)
\(=\frac{2\cdot7}{5\cdot3}\cdot\frac{5\cdot2}{7\cdot3}+1934\)
\(=\frac{2\cdot7\cdot5\cdot2}{5\cdot3\cdot7\cdot3}+1996=\frac{4}{9}+1996\)
Lời giải:
$\frac{1}{5}: \frac{1}{3}\times \frac{1:5}{1:3}+1934$
$=\frac{1}{5}\times 3\times \frac{3}{5}+1934$
$=\frac{3}{5}\times \frac{3}{5}+1934$
$=\frac{9}{25}+1934=1934\frac{9}{25}$
b) \(\frac{1}{1000}+\frac{13}{1000}+\frac{25}{1000}+...+\frac{87}{1000}+\frac{99}{1000}\)
\(=\frac{1+13+25+...+85+97}{1000}=\frac{\left(97+1\right).\left[\left(97-1\right):12+1\right]:2}{1000}\)
\(=\frac{49.9}{1000}=\frac{441}{1000}.\) ( Đề bài sai nhé bạn tử số : 1; 13; 25; 37; 49 ; 61; 73; 85 ; 97. )
#)Trả lời :
\(a,\frac{2}{3}:\frac{5}{7}.\frac{5}{7}:\frac{2}{3}+1934\)
\(=\left(\frac{2}{3}:\frac{2}{3}\right).\left(\frac{5}{7}:\frac{5}{7}\right)+1934\)
\(=1.1+1934\)
\(=1935\)
#~Will~be~Pens~#
`2/3:5/7xx5/5:2/3+1934`
`=2/3xx7/5xx5/7xx3/2+1934`
`=[2xx7xx5xx3]/[3xx5xx7xx2]+1934`
`=1+1934=1935`
2/3 : 5/7 x 5/7 :2/3 +1934
= (2/3 : 2/3)x(5/7 : 5/7) +1934
= 1x1+1934
= 1 +1934
= 1935