Bài 2 tìm X biết:
a) 2448 : ( 119 - ( X - 6 ) = 24
b) ( X + 1) + ( X+ 3 ) + (X + 5 ) + ...+( X+99) = 2550
Giải hộ mik với
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\(a,2448:\left[119-\left(x-6\right)\right]=24\)
\(119-\left(x-6\right)=2448:24\)
\(119-\left(x-6\right)=102\)
\(x-6=119-102\)
\(x-6=17\)
\(x=17+6\)
\(\Rightarrow x=23\)
\(b,2016-100\times\left(x+11\right)=128:8\)
\(2016-100\times\left(x+11\right)=16\)
\(100\times\left(x+11\right)=2016-16\)
\(100\times\left(x+11\right)=2000\)
\(x+11=2000:100\)
\(x+11=20\)
\(x=20-11\)
\(\Rightarrow x=9\)
\(a,2448:\left[119-\left(x-6\right)\right]=24\\ 119-\left(x-6\right)=2448:24\\ 119-\left(x-6\right)=102\\ x-6=119-102\\ x-6=17\\ x=17+6\\ x=23\\ b,2016-100\times\left(x+11\right)=128:8\\ 2016-100\times\left(x+11\right)=16\\ 100\times\left(x+11\right)=2016-16\\ 100\times\left(x+11\right)=2000\\ x+11=2000:100\\ x+11=20\\ x=20-11\\ x=9\)
bài 2
a) 2448:[119-(x-6)]=24
119-(x-6)=2448:24
119-(x-6)=102
x-6=119-102
x-6=17
x=17+6
x=23
a: x/3-1/6=1/5
=>x/3=11/30
hay x=11/90
b: =>1/2x=2
hay x=4
c: =>2/3:x=-7-1/3=-22/3
=>x=-1/11
Trả lời
a)(136,5-x).1,2=5,4
136,5-x =5,4:1,2
136,5-x =4,5
x =136,5+4,5
x =141
b)18:(372:3.x-1)=6
372:3x-1 =18:6
372:3x-1 =3
372:3x =3+1
372:3x =4
3x =372:4
3x =93
x =93:3
x =31
c)[(6.x-39):7].4=12
(6x-39):7 =12:4
(6x-39):7 =3
6x-39 =3.7
6x-39 =21
6x =21+39
6x =60
x =60:6
x =10
d)2448:[119-(x-6)]=24
119-(x-6)=2448:24
119-(x-6)=102
x-6 =119-102
x-6 =17
x =17+6
x =23
Chúc bạn học tốt !
a, ( 136,5 - X ) x 1,2 = 5,4
=> 136,5 - X = 5,4 : 1,2
=> 136,5 - X = 4,5
=> X = 136,5 - 4,5
=> X = 132
b, hình như sai đề bạn ơi
c, [ ( 6 x X - 39 ) : 7 ] x 4 = 12
=> ( 6 x X - 39 ) : 7 = 12 : 4
=> ( 6 x X - 39 ) :7 = 3
=> 6 x X - 39 = 3 x 7
=> 6 x X - 39 = 21
=> 6 x X = 60
=> X = 60 : 6
=> X = 10
d, 2448 : [ 119 - ( x - 6 ) ] = 24
=> 119 - ( x - 6 ) = 2448 : 24
=> 119 - ( x - 6 ) = 102
=> x - 6 = 119 - 102
=> x - 6 = 17
=> x = 17 + 6
=> x = 23
\(2448:\left[119-\left(x-6\right)\right]=24\)
\(119-\left(x-6\right)=2448:24\)
\(119-\left(x-6\right)=102\)
\(x-6=119-102\)
\(x-6=17\)
\(x=17+6\)
\(x=23\)( thỏa mãn \(x\in N\) )
vậy x = 23
\(2016-100\cdot\left(x+11\right)=2^7:2^3\)
\(2016-100\cdot\left(x+11\right)=128:8\)
\(2016-100\cdot\left(x+11\right)=16\)
\(100\cdot\left(x+11\right)=2016-16\)
\(100\cdot\left(x+11\right)=2000\)
\(x+11=2000:100\)
\(x+11=20\)
\(x=20-11\)
\(x=9\)( thỏa mãn \(x\in N\))
vậy x = 9
Câu b,
= 50x + (1 + 3 + 5 + ..... + 99) = 2550
= 50x + 2500 = 2550
= 50x = 2550 - 2500
= 50x = 50
= x = 50 : 50
= x = 1
refer
A) 2448:[119-[x-6]]=24
<=> 199 - ( x-6 ) = 2448 : 24 = 102
<=> x - 6 = 199 - 102 = 97
<=> x = 97 +6 = 103
B) (x+1)+(x+3)+(x+5)+......+(x+99) = 2550
(x+x+x+....+x)+(1+3+5+....+99) = 2550
50x + 2500 = 2550
50x = 2550 - 2500
50x = 50
x = 50 : 50
x = 1