3/2+9/4+25/8+...+897/128
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\(=1+\dfrac{1}{2}+2+\dfrac{1}{4}+3+\dfrac{1}{8}+...+7+\dfrac{1}{128}\)
\(=\left(1+2+...+7\right)+\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+...+\dfrac{1}{128}\right)\)
\(=28+\left(1-\dfrac{1}{1}-+\dfrac{1}{2}-\dfrac{1}{4}+...+\dfrac{1}{64}-\dfrac{1}{128}\right)\)
\(=28+\left(1-\dfrac{1}{128}\right)\)
\(=28+\dfrac{127}{128}\)
\(=\dfrac{3711}{128}\)
1) 125.(-24) + 24.225.
\(=24\left(-125+225\right)=24.100=2400.\)
2) 512.(2 – 128) – 128. (-512).
\(=512\left(2-128+128\right)=512.2=1024.\)
1) (-12).46-12.54
=12.(-46)-12.54
=12.(-46-54)
=12.(-100)=(-1200)
10) 17.(-25)+25.21
= (-17).25+25.21
=25.(-17+21)
=25.4=100
( Mik đọc lướt qua thì thấy hai bài này dễ nên làm, chứ mấy bài kia chưa suy nghĩ gì, bạn tự làm nốt nhé!)
1/\(\left(-12\right)\cdot46-12\cdot54=\left(-12\right)\cdot46+\left(-12\right)\cdot54\)
\(=\left(-12\right)\cdot\left(46+54\right)=\left(-12\right)\cdot100=-1200\)
2/\(3784+23-3785-15=3785+22-3785-15\)
\(=22-15=7\)
3/\(\left(-8\right)\cdot25\cdot\left(-2\right)\cdot4\cdot\left(-5\right)\cdot125\)
\(=\left[\left(-8\right)\cdot125\right]\cdot\left[25\cdot4\right]\cdot\left[\left(-5\right)\cdot\left(-2\right)\right]\)
\(=\left(-1000\right)\cdot100\cdot10=-1000000\)
4/\(19\cdot25+9\cdot95+19\cdot30=19\cdot\left(25+30\right)+9\cdot95\)
\(=19\cdot55+9\cdot95=95\cdot11+9\cdot95=95\cdot\left(11+9\right)=20\cdot95=1900\)
5/\(\left(-50+19+143\right)-\left(-79+25+48\right)\)
\(=\left(-50\right)+19+143+79-25-48\)
\(=118\)
6/\(\left(-25\right)\cdot\left(75-45\right)-75\cdot\left(45-25\right)\)
\(=\left(-25\right)\cdot30+\left(-25\right)\cdot3\cdot20\)
\(=\left(-25\right)\cdot\left(30+60\right)=\left(-25\right)\cdot90=-2250\)
7/\(\left(-37-17\right)\cdot\left(-9\right)+35\left(-9-11\right)\)
\(=\left(-54\right)\cdot\left(-9\right)+35\cdot\left(-20\right)\)
\(=486+\left(-700\right)=-214\)
8/\(\left(187-23\right)-\left(20-180\right)\)
\(=187-23-20+180=324\)
9/\(512\cdot2-128\cdot\left(-512\right)\)
\(=512\cdot2+128\cdot512=512\cdot\left(2+128\right)\)
\(=512\cdot130=66560\)
10/\(17\cdot\left(-25\right)+25\cdot21\)
\(=17\cdot\left(-25\right)-\left(-25\right)\cdot21=\left(-25\right)\cdot\left(17-21\right)\)
\(=\left(-25\right)\cdot\left(-4\right)=100\)
Chúc bạn học tốt.
P=1+5+9+..+25
so so hang=(25-1)/4+1=7
P=(1+25)*7/2=13.7
Q=2^0+2^1+2^2+...+2^7
2Q=2^1+2^2+..+2^8
2Q-Q=Q=(2^8-2^0)/2
a) \(\left(-25\right).8.\left(-4\right).\left(-125\right).3\)
\(=\text{ }\left[\left(-25\right).\left(-4\right)\right].\text{ }\left[8.\left(-125\right)\right].3\)
\(=100.\left(-1000\right).3\)
\(=-100000.3\)
\(=-300000\)
b) \(27.\left(-17\right)+17.\left(-73\right)\)
\(=\left(-27\right).17+17.\left(-73\right)\)
\(=17\left[\left(-27\right).\left(-73\right)\right]\)
\(=17.\left(-100\right)\)
\(=-1700\)
c) \(512\left(2-128\right)-128\left(-512\right)\)
\(=512.2-512.128-128\left(-512\right)\)
\(=512.2-128\left[512+\left(-512\right)\right]\)
\(=1024-128.0\)
\(=1024-0\)
\(=1024\)
a, (-25).8.(-4).(-125).3
= (-25).(-8).(-4).(-125).(-3)
= {(-25).(-4)}.{(-8).(-125)}.(-3)
= 100.1000.(-3)
= 100000.(-3)
= -300000
b, 27.(-17)+17.(-73)
= 27.17+17.73
= 27.(17+73)
=27.90
=2430
c, 512.(2-128)-128.(-512)
= 512.(-2) - 512.128 - (-128).512
= { 512.{(-2)-128-(-128)}
= 512.{(-2).256}
=512.(-512)
= -262144
\(\dfrac{3}{2}+\dfrac{9}{4}+\dfrac{25}{8}+...+\dfrac{897}{128}\)
\(=\dfrac{3+9+25+...+897}{2+4+8+...+128}\)
\(=\dfrac{\left(897-3\right)\div6+1}{\left(128-2\right)\div2+1}\)
\(=\dfrac{150}{64}\)
\(=\dfrac{75}{32}\)