x2 - 8x + 55 = 0
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\(a.x^2-7x-3x+21=0\Leftrightarrow\left(x^2-7x\right)-\left(3x-21\right)=0\)
\(\Leftrightarrow x\left(x-7\right)-3\left(x-7\right)=0\Leftrightarrow\left(x-3\right)\left(x-7\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x-7=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=7\end{matrix}\right.\)
\(b.x^2+6x+2x+12=0\Leftrightarrow\left(x^2+6x\right)+\left(2x+12\right)=0\)
\(\Leftrightarrow x\left(x+6\right)+2\left(x+6\right)=0\Leftrightarrow\left(x+2\right)\left(x+6\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=-6\end{matrix}\right.\)
\(c.x^2+4x+5x+20=0\Leftrightarrow\left(x^2+4x\right)+\left(5x+20\right)=0\)
\(\Leftrightarrow x\left(x+4\right)+5\left(x+4\right)=0\Leftrightarrow\left(x+5\right)\left(x+4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-5\\x=-4\end{matrix}\right.\)
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a) \(\text{Δ}=8^2-4.3.4=16\)
\(\left[{}\begin{matrix}x=\dfrac{-8+4}{2.3}=-\dfrac{2}{3}\\x=\dfrac{-8-4}{2.3}=-2\end{matrix}\right.\)
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\(x^2-8x-9=0\\ x^2+x-9x-9=0\\ x\left(x+1\right)-9\left(x+1\right)=0\\ \left\{{}\begin{matrix}x-3=0\\x+3=0\\x-1=0\end{matrix}\right.\left\{{}\begin{matrix}x=3\\x=-3\\x=1\end{matrix}\right.\)
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a) x = -1. b) x = 4 hoặc x = 5.
c) x = ± 2 . d) x = 1 hoặc x = 2.
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có 3 x 2 + 8x + 5 = 0
ó 3 x 2 + 3x + 5x + 5 = 0 ó 3x(x + 1) + 5(x + 1) = 0
ó (3x + 5)(x + 1) = 0
Vậy x = - 5 3 ; x = - 1
Đáp án cần chọn là: A
![](https://rs.olm.vn/images/avt/0.png?1311)
x3 - 9x2 + 19x - 11 = 0
<=> (x - 1)(x2 - 8x + 11) = 0
<=> x - 1 = 0
<=> x = 1
pt vô nghiệm
dị đò thôi :))