13 x y = 3/7
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Mình ko ghi lai de
C=3.(1-1/20+1/13-1/2013)/7.(1-1/20+1/13-1/2013)
C=3.1/7.1
C=3/7
a) 0,5 x - \(\frac{2}{3}\)x = \(\frac{7}{12}\)
x . ( 0,5 - \(\frac{2}{3}\)) = \(\frac{7}{12}\)
x . \(\frac{-1}{6}\) = \(\frac{7}{12}\)
x = \(\frac{7}{12}\): \(\frac{-1}{6}\)
x = \(\frac{-7}{2}\)
b) x : \(\frac{25}{3}\) = -25
x = -25 . \(\frac{25}{3}\)
x = \(\frac{-625}{3}\)
c) 5,5 x = \(\frac{13}{15}\)
x = \(\frac{13}{15}\): 5,5
x = \(\frac{26}{165}\)
d) (\(\frac{3x}{7}\)+ 1 ) : ( -4) = \(\frac{-1}{28}\)
( \(\frac{3x}{7}\)+ 1 ) = \(\frac{-1}{28}\). ( -4)
\(\frac{3x}{7}\)+ 1 = \(\frac{1}{7}\)
\(\frac{3x}{7}\) = \(\frac{1}{7}\)- 1
\(\frac{3x}{7}\) = \(\frac{-6}{7}\)
=> x = -2
e) y + 30% y = -1,3
y + \(\frac{3}{10}\)y = -1,3
y . ( 1 + \(\frac{3}{10}\)) = -1,3
y . \(\frac{13}{10}\) = -1,3
y = -1,3 : \(\frac{13}{10}\)
y = -1
g) y - 25% y = \(\frac{1}{2}\)
y - \(\frac{1}{4}\)y = \(\frac{1}{2}\)
y . ( 1 - \(\frac{1}{4}\)) = \(\frac{1}{2}\)
y . \(\frac{3}{4}\) = \(\frac{1}{2}\)
y = \(\frac{1}{2}\): \(\frac{3}{4}\)
y = \(\frac{2}{3}\)
ai tốt bụng thì tk cho mk nha, mk đg âm điểm đây huhu
a: =y x15/5=3y
b: =(4/6+14/6)+(7/13+19/13)+(17/9-8/9)
=3+2+1
=6
\(\left(x-7\right)\left(y+3\right)=13\)
Do \(x,y\in N\) nên ta có bảng:
x-7 | 1 | 13 |
y+3 | 13 | 1 |
x | 8 | 20 |
y | 10 | -2(loại) |
Vậy \(\left(x;y\right)\in\left\{\left(8;20\right)\right\}\)
y \(\times\) \(\dfrac{13}{15}\) = \(\dfrac{2}{3}\) \(\times\) \(\dfrac{7}{6}\)
y \(\times\) \(\dfrac{13}{15}\) = \(\dfrac{14}{18}\)
y \(\times\) \(\dfrac{13}{15}\) = \(\dfrac{7}{9}\)
y = \(\dfrac{7}{9}\) : \(\dfrac{13}{15}\)
y = \(\dfrac{35}{39}\)
thử lại ta có:
\(\dfrac{35}{39}\) \(\times\) \(\dfrac{13}{15}\) = \(\dfrac{7}{9}\)
\(\dfrac{2}{3}\) \(\times\) \(\dfrac{7}{6}\) = \(\dfrac{7}{9}\)
Vậy y = \(\dfrac{35}{39}\) là đúng
Ta có \(\dfrac{7-x}{13+y}=\dfrac{7}{13}\Rightarrow\dfrac{7-x}{7}=\dfrac{13+y}{13}\)
Áp dụng tính chất dãy tỉ số bằng nhau:
\(\dfrac{7-x}{7}=\dfrac{13+y}{13}=\dfrac{13+y-7+x}{13-7}=\dfrac{6+x+y}{6}=\dfrac{2022+6}{6}=338\)
\(\Rightarrow\left\{{}\begin{matrix}7-x=338\times7=2366\\13+y=338\times13=4394\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-2359\\y=4381\end{matrix}\right.\)
y=3/7:13
y=3/7x1/13
y=7/91
y = \(\dfrac{3}{7}\) : 13
y = \(\dfrac{3}{7}\) x \(\dfrac{1}{13}\)
y = \(\dfrac{3}{91}\)