\(4:\frac{205}{811}=\)
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a) 12/17 + 21/25 = 657/425
b) 4 - 205/811 = 3039/811
c) 12 . 21/25 = 252/25
d) 4 : 205/811 = 205/3244
a) 12/17 + 21/25 = 657/425
b) 4 - 205/811 = 3039/811
c) 12 . 21/25 = 252/25
d) 4 : 205/811 = 205/3244
mk biết làm nhưng ko thể ấn được phân số giống bn bn hay chỉ cách giúp mk rồi mk giải cho
Ta có
\(\frac{743}{811}<1\)
\(\frac{3}{2}>1\)
=>\(\frac{743}{811}<\frac{3}{2}\)
\(\)Đặt \(A=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}...+\frac{1}{205}}{\frac{204}{1}+\frac{203}{2}+\frac{202}{3}+...+\frac{1}{204}}=\frac{B}{C}\)
Biến đổi C:
\(C=\left(\frac{204}{1}+1\right)+\left(\frac{203}{2}+1\right)+\left(\frac{202}{3}+1\right)+...+\left(\frac{1}{204}+1\right)-204\)
\(=205+\frac{205}{2}+\frac{205}{3}+..+\frac{205}{204}+\frac{205}{205}-205\)
\(=205.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{205}\right)\)
\(\Rightarrow A=\frac{\frac{1}{2}+\frac{1}{3}+...+\frac{1}{205}}{205.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{205}\right)}=\frac{1}{205}\)
a) \(\frac{x+1}{2004}+\frac{x+2}{2003}=\frac{x+3}{2002}+\frac{x+4}{2001}\)
\(\Leftrightarrow\frac{x+2005}{2004}+\frac{x+2005}{2003}=\frac{x+2005}{2002}+\frac{x+2005}{2001}\)
\(\Leftrightarrow\left(x+2005\right)\left(\frac{1}{2004}+\frac{1}{2003}-\frac{1}{2002}-\frac{1}{2001}\right)=0\)
\(\Leftrightarrow x+2005=0\)
\(\Leftrightarrow x=-2005\)
b) Sửa đề :
\(\frac{201-x}{99}+\frac{203-x}{97}+\frac{205-x}{95}+3=0\)
\(\Leftrightarrow\frac{300-x}{99}+\frac{300-x}{97}+\frac{300-x}{95}=0\)
\(\Leftrightarrow\left(300-x\right)\left(\frac{1}{99}+\frac{1}{97}+\frac{1}{95}\right)=0\)
\(\Leftrightarrow x=300\)
c) \(\frac{2-x}{2002}-1=\frac{1-x}{2003}-\frac{x}{2004}\)
\(\Leftrightarrow\frac{2-x}{2002}+1=\frac{1-x}{2003}+1-\frac{x}{2004}+1\)
\(\Leftrightarrow\frac{2004-x}{2002}=\frac{2004-x}{2003}-\frac{2004-x}{2004}\)
\(\Leftrightarrow\left(2004-x\right)\left(\frac{1}{2002}-\frac{1}{2003}+\frac{1}{2004}\right)=0\)
\(\Leftrightarrow x=2004\)
Vậy....
\(\dfrac{4}{5}-\dfrac{2}{5}\times\dfrac{1}{4}=\dfrac{4}{5}-\dfrac{1}{10}=\dfrac{8}{10}-\dfrac{1}{10}=\dfrac{7}{10}\)
\(\dfrac{1}{4}+\dfrac{3}{4}:\dfrac{1}{8}=\dfrac{1}{4}+\dfrac{3}{4}\times8=\dfrac{1}{4}+6=\dfrac{1}{4}+\dfrac{24}{4}=\dfrac{25}{4}\)
\(\)\(\dfrac{11}{10}-\dfrac{2}{5}:\dfrac{1}{3}=\dfrac{11}{10}-\dfrac{2}{5}\times3=\dfrac{11}{10}-\dfrac{6}{5}=\dfrac{11}{10}-\dfrac{12}{10}=-\dfrac{1}{10}\)
4/5-2/5.1/4
=4/5-1/10
=8/10-1/10
=7/10
1/4+3/4:1/8
=1/4+3/4.8
=1/4+6
=1/4+24/4
=25/4
11/10-2/5:1/3
=11/10-2/5.3
=11/10-6/5
=11/10-12/10
=-1/10
4: \(\frac{205}{811}\)= \(\frac{3244}{205}\)
tk nhé
Ta có
kết quả là:
\(4:\frac{205}{811}=\frac{3244}{205}\)
nha bn
~~~~~