Tìm x biết:
\(\frac{x-25-124}{2015}+\frac{x-124-2015}{25}+\frac{x-2015-25}{124}=3\)
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NN
0
24 tháng 9 2016
a )
\(\Rightarrow\frac{x-100}{24}-1+\frac{x-98}{26}-1+\frac{x-96}{26}-1=0\)
\(\frac{x-124}{24}+\frac{x-124}{26}+\frac{x-124}{28}=0\)
\(\left(x-124\right)\left(\frac{1}{26}+\frac{1}{24}+\frac{1}{28}\right)=0\)
\(\Rightarrow x-124=0\Rightarrow x=124\)
25 tháng 6 2020
a) Ta có: \(3\frac{1}{2}+\frac{2014}{2015}-0,5+\frac{1}{2015}\)
\(=\frac{7}{2}-\frac{1}{2}+1\)
\(=3+1=4\)
b) Ta có: \(85\%\cdot x+25\%\cdot x=110\)
\(\Leftrightarrow x\left(85\%+25\%\right)=110\)
\(\Leftrightarrow x\cdot110\%=110\)
\(\Leftrightarrow x\cdot\frac{11}{10}=110\)
hay \(x=110:\frac{11}{10}=110\cdot\frac{10}{11}=100\)
Vậy: x=100
PG
1
14 tháng 6 2017
ta co (x-2163)(1/2011+1/28+1/124)=0
vi 1/2011+1/28+1/124khac0
x-2163=0
x=2163
2 tháng 12 2018
124 : x + 24 : x - 48: x = 25
( 124 + 24 - 48 ) : x = 25
100 : x = 25
x = 4
MN
2 tháng 12 2018
\(124\div x+24\div x-48\div x=25\)
\(\Leftrightarrow\left(124+24-48\right)\div x=25\)
\(\Leftrightarrow100\div x=25\)
\(\Leftrightarrow x=100\div25=4\)
TH
2
\(\dfrac{x-25-124}{2015}\) + \(\dfrac{x-124-2015}{25}\) + \(\dfrac{x-2015-25}{124}\) = 3
\(\dfrac{x-15-124}{2015}\) - 1 + \(\dfrac{x-124-2015}{25}\) - 1 + \(\dfrac{x-2015-25}{124}\) - 1 = 0
\(\dfrac{x-15-124-2015}{2015}\)+\(\dfrac{x-124-2015-25}{25}\)+\(\dfrac{x-2015-25-124}{124}\) = 0
\(\dfrac{x-\left(15+124+2015\right)}{2015}\)+\(\dfrac{x-\left(124+2015+25\right)}{25}\)+\(\dfrac{x-\left(2015+25+124\right)}{124}\) = 0
(\(x\) - 2164).(\(\dfrac{1}{2015}\)+\(\dfrac{1}{25}\)+\(\dfrac{1}{124}\)) = 0
\(x-2164\) = 0
\(x\) = 2164