9/14 × 35/12 - 3/2
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Mấu chốt làm bài này là đưa về thừa số nguyên tố
\(\frac{12^7.3^{35}.14^{21}}{9^{21}.7^{21}.2^{35}}=\frac{3^7.4^7.3^{35}.2^{21}.7^{21}}{3^{2.21}.7^{21}.2^{35}}=\frac{3^7.2^{2.7}.3^{35}.2^{21}.7^{21}}{3^{2.21}.7^{21}.2^{35}}=\frac{3^7.2^{14}.3^{35}.2^{21}.7^{21}}{3^{42}.7^{21}.2^{35}}=\frac{3^{42}.2^{35}.7^{21}}{3^{42}.7^{21}.2^{35}}=1\)
2/ Tìm y:
y + \(\dfrac{1}{3}\) x 4 = 12 \(\dfrac{2}{5}\) + y = \(\dfrac{12}{35}\) x \(\dfrac{14}{9}\)
\(y=12-\left(\dfrac{1}{3}\times4\right)=12-\dfrac{4}{3}=\dfrac{32}{3}\)
\(y=\left(\dfrac{12}{35}\times\dfrac{14}{9}\right)-\dfrac{2}{5}=\dfrac{8}{15}-\dfrac{2}{5}=\dfrac{2}{15}\)
a: \(=\dfrac{-36}{35}\cdot\dfrac{14}{9}\cdot\dfrac{-1}{8}=\dfrac{36}{9}\cdot\dfrac{14}{35}\cdot\dfrac{1}{8}=4\cdot\dfrac{1}{8}\cdot\dfrac{2}{5}=\dfrac{1}{5}\)
b: \(=\left(6+\dfrac{1}{8}-\dfrac{1}{2}\right)\cdot4\)
\(=\dfrac{48+1-4}{8}\cdot4=\dfrac{45}{2}\)
Giải:
a) \(-\dfrac{36}{35}:\dfrac{9}{14}.\left(-\dfrac{1}{2}\right)^3\)
\(=-\dfrac{36}{35}.\dfrac{14}{9}.\left(-\dfrac{1}{8}\right)\)
\(=-\dfrac{36.14.\left(-1\right)}{35.9.8}\)
\(=-\dfrac{9.4.2.7.\left(-1\right)}{5.7.9.2.4}\)
\(=-\dfrac{-1}{5}\)
Vậy ...
b) \(\left[6+\left(\dfrac{1}{2}\right)^3-\dfrac{1}{2}\right]:\dfrac{3}{12}\)
\(=\left[6+\dfrac{1}{8}-\dfrac{1}{2}\right].\dfrac{12}{3}\)
\(=\left[\dfrac{48}{8}+\dfrac{1}{8}-\dfrac{4}{8}\right].4\)
\(=\dfrac{48+1-4}{8}.4\)
\(=\dfrac{45}{8}.4\)
\(=\dfrac{45}{2}\)
Vậy ...
\(-\frac{12}{35}\div\frac{7}{11}-\frac{23}{35}\div\frac{7}{11}-\frac{5}{11}\)
\(=\left(-\frac{12}{35}-\frac{23}{35}\right)\div\frac{7}{11}-\frac{5}{11}\)
\(=-1\div\frac{7}{11}-\frac{5}{11}\)
\(=-\frac{11}{7}-\frac{5}{11}\)
\(=-\frac{156}{77}\)
3/8
= 12/7 - 3/2
= 3/14