Tính nhanh:
100 x 10 x 1 x (a x 1 - a : 1) = ?
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\(B=\frac{10}{18}\times\frac{22}{30}\times\frac{36}{44}\times...\times\frac{200}{209}=\frac{1\times10}{2\times9}\times\frac{2\times11}{3\times10}\times\frac{3\times12}{4\times11}\times...\times\frac{10\times20}{11\times19}\)
\(=\frac{1\times10\times2\times11\times3\times12\times...\times10\times20}{2\times9\times3\times10\times4\times11\times...\times11\times19}=\frac{\left(1\times2\times3\times...\times10\right)\times\left(10\times11\times12\times...\times20\right)}{\left(2\times3\times4\times...\times11\right)\times\left(9\times10\times11\times...\times19\right)}\)
\(=\frac{1\times20}{11\times9}=\frac{20}{99}\)
Sửa đề \(C=\left(1-\frac{1}{4}\right)\times\left(1-\frac{1}{9}\right)\times\left(1-\frac{1}{16}\right)\times...\times\left(1-\frac{1}{100}\right)\)
\(=\frac{3}{4}\times\frac{8}{9}\times\frac{15}{16}\times...\times\frac{99}{100}=\frac{3\times8\times15\times...\times99}{4\times9\times16\times...\times100}=\frac{1\times3\times2\times4\times3\times5\times...\times9\times11}{2\times2\times3\times3\times4\times4\times...\times10\times10}\)
\(=\frac{\left(1\times2\times3\times....\times9\right)\times\left(3\times4\times5\times...\times11\right)}{\left(2\times3\times4\times...\times10\right)\times\left(2\times3\times4\times...\times10\right)}=\frac{1\times11}{10\times2}=\frac{11}{20}\)
#)Giải :
\(\left(1-\frac{3}{4}\right)x\left(1-\frac{3}{7}\right)x\left(1-\frac{3}{10}\right)x\left(1-\frac{1}{13}\right)x...x\left(1-\frac{3}{100}\right)\)
\(=\frac{1}{4}x\frac{4}{7}x\frac{7}{10}x...x\frac{94}{97}x\frac{97}{100}\)
\(=\frac{1x4x7x...x94x100}{4x7x10x...x97x100}\)
\(=\frac{1}{100}\)
#~Will~be~Pens~#
\(\left(1-\frac{3}{4}\right)\left(1-\frac{3}{7}\right)\left(1-\frac{3}{10}\right)\left(1-\frac{1}{13}\right)...\left(1-\frac{1}{97}\right)\left(1-\frac{3}{100}\right)\)
\(=\frac{1}{4}.\frac{4}{7}.\frac{7}{10}.\frac{10}{13}...\frac{94}{97}.\frac{97}{100}\)
\(=\frac{1}{100}\)
Bài 10: \(1^2+2^2+3^2+...+n^2=\frac{n.\left(n+1\right).\left(2n+1\right)}{6}\)
\(A=1+4+9+16+...+100=1^2+2^2+3^2+4^2+...+10^2=385\)
Bài 11:
\(B=1^2+2^2+3^2+...+100^2=\frac{100.\left(100+1\right).\left(2.100+1\right)}{6}=338350\)
a: \(=68\cdot72\cdot49\cdot\left[324-324\right]=0\)
b: \(=\left(1250-1250\right)\cdot\left(1+...+100\right)=0\)
Bài 1 :
\(A=1+2+3+4+5+6+7+8+9\)
\(=\left(1+9\right)+\left(2+8\right)+\left(3+7\right)+\left(4+6\right)+5\)
\(=10+10+10+10+5\)
\(=45\)
Bài 2 bạn tự làm nha
Bài 2 : Tìm x :
a) ( x - 8 )5 = ( x - 8 )9
=> x - 8 thuộc { 0 ; 1 } vì :
Nếu x - 8 = 0 thì ( x - 8 )5 = 05 = 0
Nếu x - 8 = 0 thì ( x - 8 )9 = 09 = 0
Vậy x - 8 = 0 là thỏa mãn điều kiện.
Nếu x - 8 = 1 thì ( x - 8 )5 = 15 = 1
Nếu x - 8 = 1 thì ( x - 8 )9 = 19 = 1
Vậy x - 8 = 1 là thỏa mãn điều kiện.
=> x - 8 thuộc { 0 ; 1 }
=> x thuộc { 8 ; 9 }
a, =13x(27+2x35+4-1)=13x100=1300
b, =(99-99):(1x2x...x10)=0
tick nha!