Thuận tiện: . 87/10 x 94/73 + 87/10 x 46/73 - 87/10 x 40/73
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a) Ta có:
\(\frac{19}{15}\)= 1+ \(\frac{4}{15}\).
\(\frac{15}{11}\)= 1+ \(\frac{4}{11}\).
Vì \(\frac{4}{15}\)< \(\frac{4}{11}\).
=> 1+ \(\frac{4}{15}\)< 1+ \(\frac{4}{11}\).
=> \(\frac{19}{15}\)< \(\frac{15}{11}\).
87 - (73 - \(x\)) = 20
87 - 73+ \(x\) = 20
14+ \(x\) = 20
\(x\) = 20 - 14
\(x\) = 6
\(\dfrac{x-13}{87}+\dfrac{x-27}{73}+\dfrac{x-67}{83}+\dfrac{x-73}{27}=4\)
<=>\(\dfrac{x-13}{87}-1+\dfrac{x-27}{73}-1+\dfrac{x-67}{83}-1+\dfrac{x-73}{27}-1=0\)
<=>\(\dfrac{x-100}{87}+\dfrac{x-100}{73}+\dfrac{x-100}{83}+\dfrac{x-100}{27}=0\)
<=>\(\left(x-100\right)\left(\dfrac{1}{87}+\dfrac{1}{73}+\dfrac{1}{83}+\dfrac{1}{27}\right)=0\)
Do \(\dfrac{1}{87}+\dfrac{1}{73}+\dfrac{1}{83}+\dfrac{1}{27}>0\)
=>x-100=0
<=>x=100
25 x 33 + 25 x 87 + 64 x 73 + 64 x 47
= 25 x ( 33 + 87 ) + 64 x ( 73 + 47 )
= 25 x 120 + 64 x 120
= 120 x ( 15 + 64 )
= 120 x 49
= 5580
25 x 33 + 25 x 87 + 64 x 73 + 64 x 47
= 25 x ( 33 + 87 ) + 64 x ( 73 +47 )
= 25 x 120 + 64 x 120
= 120 x ( 25 + 64 )
= 120 x 89
= 10680
A = 4 . 2 . 25 . 5 . 175
A = 22 . 2 . 52 . 5 . 52 . 7
A = 22+1 . 52+1+2 . 7
A = 23 . 55 .7
A = 175000
\(B=4^2-10^4:\left(50\cdot273-50\cdot73\right)\)
\(B=4^2-10^4:\left[50\cdot\left(273-73\right)\right]\)
\(B=4^2-10^4:\left(50\cdot200\right)\)
\(B=4^2-10^4:10^4=4^2-1=15\)
\(C=3\times53\times6+2\times9\times87-18\times40\)
\(C=18\times53+18\times87-18\times40\)
\(C=18\times\left(53+87-40\right)\)
\(C=18\times100=1800\)
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