1/3xX+1/6xX=48
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a)\(\frac{2}{3}\cdot x+\frac{1}{4}=\frac{5}{6}\)
\(\frac{2}{3}\cdot x=\frac{5}{6}-\frac{1}{4}=\frac{7}{12}\)
\(x=\frac{7}{12}:\frac{2}{3}=\frac{7}{8}\)
b) \(\frac{7}{12}-\frac{5}{6}\cdot x=\frac{1}{4}:\frac{2}{3}\)
\(\frac{7}{12}-\frac{5}{6}\cdot x=\frac{3}{8}\)
\(\frac{5}{6}\cdot x=\frac{7}{12}-\frac{3}{8}=\frac{5}{24}\)
\(x=\frac{5}{24}:\frac{5}{6}=\frac{1}{4}\)
c) \(2\frac{1}{3}-\left(x+1\right)=\frac{5}{9}\)
\(\frac{7}{3}-\left(x+1\right)=\frac{5}{9}\)
\(x+1=\frac{7}{3}-\frac{5}{9}=\frac{16}{9}\)
\(x=\frac{16}{9}-1=\frac{7}{9}\)
d) \(\frac{2\cdot x+1}{15}=\frac{3}{5}\)
\(\left(2\cdot x+1\right):15=\frac{3}{5}\)
\(2\cdot x+1=\frac{3}{5}\cdot15=9\)
\(2\cdot x=9-1=8\)
\(x=8:2=4\)
a, 2/3 . x +1/4=5/6
2/3 . x=5/6-1/4
2/3 . x=10/12 -3/12
2/3 . x=7/12
x= 7/12 : 2/3
x=7/8
Vậy x=7/8
a) 32 : (3.x - 2) = 8
3x - 2 = 32 : 8
3x - 2 = 4
3x = 4 + 2
3x = 6
x = 6 : 3
x = 2
b) 75 : (x - 18) = 25
x - 18 = 75 : 25
x - 18 = 3
x = 3 + 18
x = 21
c) (15 - 6.x) . 243 = 729
15 - 6x = 729 : 243
15 - 6x = 3
6x = 15 - 3
6x = 12
x = 12 : 6
x = 2
d) 4.(x - 12) + 9 = 17
4(x - 12) = 17 - 9
4(x - 12) = 8
x - 12 = 8 : 4
x - 12 = 2
x = 2 + 12
x = 14
e) 20 - 2.(x + 4) = 4
2(x + 4) = 20 - 4
2(x + 4) = 16
x + 4 = 16 : 2
x + 4 = 8
x = 8 : 2
x = 4
`32: ( 3xx x -2)=8`
`3xx x-2=32:8`
`3xx x-2=4`
`3 xx x=4+2`
`3xx x=6`
`x=6:3`
`x=2`
__
`75 : (x-18) =25`
`x-18=75:25`
`x-18= 3`
`x=3+18`
`x=21`
__
`(15-6 xx x ) xx 243 =729`
`15-6 xx x = 729 : 243`
`15-6 xx x = 3`
`6 xx x=15-3`
`6 xx x=12`
`x=12:6`
`x=2`
__
`4 xx (x-12)+9=17`
`4 xx (x-12)=17-9`
`4 xx (x-12)= 8`
`x-12=8:4`
`x-12=2`
`x=2+12`
`x=14`
__
`20-2xx(x+4)=4`
`2xx(x+4)=20-4`
`2xx(x+4)=16`
`x+4=16:2`
`x+4=8`
`x=8-4`
`x=4`
Với x > 0;x ≠ 1 ta có:
A = x + 3 x x + 1 - x - 3 x x - 1
= x + 3 x - 1 - x - 3 x + 1 x x - 1 x + 1 = x + 2 x - 3 - x - 2 x - 3 x x - 1 = 4 x x x - 1 = 4 x - 1
`@` `\text {Ans}`
`\downarrow`
\(\dfrac{2}{3}\times x-\dfrac{x}{2}-\dfrac{1}{2}=\dfrac{1}{4}?\)
`=>`\(\dfrac{2}{3}x-\dfrac{x}{2}-\dfrac{1}{2}=\dfrac{1}{4}\)
`=>`\(\dfrac{4x}{6}-\dfrac{3x}{6}-\dfrac{1}{2}=\dfrac{1}{4}\)
`=>`\(\dfrac{x}{6}-\dfrac{1}{2}=\dfrac{1}{4}\)
`=>`\(\dfrac{x}{6}=\dfrac{1}{4}+\dfrac{1}{2}\)
`=>`\(\dfrac{x}{6}=\dfrac{3}{4}\)
`=> 4x=3*6`
`=> 4x=18`
`=> x=`\(\dfrac{18}{4}=\dfrac{9}{2}=4,5\)
Vậy, `x=4,5.`
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