Tìm x:\(\frac{12}{3};x:\frac{14}{3}.\frac{4}{7}\)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{x}{12}=\frac{4}{3x-3}+\frac{1}{12}\)
\(\frac{x}{12}-\frac{1}{12}=\frac{4}{3\left(x-1\right)}\)
\(\frac{x-1}{12}=\frac{4}{3\left(x-1\right)}\)
=> ( x - 1 ) . 3 ( x - 1 ) = 48
=> ( x - 1 )2 . 3 = 48
=> ( x - 1 )2 = 16
Phần sau dễ bạn tự làm nốt nha
\(\frac{x}{2}+\frac{x}{3}+\frac{x}{6}=\frac{13}{12}\)
<=>\(\frac{3x}{6}+\frac{2x}{6}+\frac{x}{6}=\frac{13}{12}\)
<=>\(\frac{3x+2x+x}{6}=\frac{13}{12}\)
<=>\(\frac{6x}{6}=\frac{13}{12}\)
<=>x =\(\frac{13}{12}\).
Chúc bạn học tốt!
Có lẽ bạn viết đề sai.
Câu hỏi của Vũ Mai Linh - Toán lớp 7 - Học toán với OnlineMath
\(\frac{-11}{6}.x+\frac{3}{2}.x-1\frac{2}{3}=\frac{5}{12}\)
=> \(\left(-\frac{11}{6}+\frac{3}{2}\right).x=\frac{5}{12}+\frac{5}{3}\)
=> \(-\frac{1}{3}.x=\frac{25}{12}\)
=> \(x=\frac{25}{12}:\left(-\frac{1}{3}\right)\)
=> \(x=-\frac{25}{4}\)
\(\frac{-11}{6}x+\frac{3}{2}x-1\frac{2}{3}=\frac{5}{12}\)
\(\Rightarrow\left(-\frac{11}{6}+\frac{3}{2}\right)x-\frac{5}{3}=\frac{5}{12}\)
\(\Rightarrow\left(-\frac{11}{6}+\frac{9}{6}\right)x-\frac{5}{3}=\frac{5}{12}\)
\(\Rightarrow-\frac{1}{3}x-\frac{5}{3}=\frac{5}{12}\)
\(\Rightarrow-\frac{1}{3}x=\frac{5}{12}+\frac{5}{3}\)
\(\Rightarrow-\frac{1}{3}x=\frac{5}{12}+\frac{20}{12}\)
\(\Rightarrow-\frac{1}{3}x=\frac{25}{12}\)
\(\Rightarrow x=\frac{25}{12}:\left(-\frac{1}{3}\right)\)
\(\Rightarrow x=\frac{25}{12}.\left(-3\right)\)
\(\Rightarrow x=\frac{-75}{12}\)
\(\Rightarrow x=\frac{-25}{4}\)
\(\frac{x}{2}+\frac{x}{3}+\frac{x}{4}=-\frac{13}{12}\)
\(\Rightarrow x\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\right)=\frac{-13}{12}\)
\(\Rightarrow x.\frac{13}{12}=\frac{-13}{12}\)
\(\Rightarrow x=-1\)
\(\frac{x}{2}+\frac{x}{3}+\frac{x}{4}=-\frac{13}{12}\)
\(\Rightarrow\frac{6x}{12}+\frac{4x}{12}+\frac{3x}{12}=-\frac{13}{12}\)
\(\Leftrightarrow6x+4x+3x=-13\)
\(\Leftrightarrow13x=-13\)
\(\Leftrightarrow x=-1\)
\(-\frac{5}{9}-\left(-\frac{5}{12}\right)\)
\(=-\frac{5}{9}+\frac{5}{12}\)
\(=-\frac{5}{36}\)
*Tìm x
\(-\frac{5}{6}-x=\frac{7}{12}+\left(-\frac{1}{3}\right)\)
\(\Rightarrow-\frac{5}{6}-x=\frac{1}{4}\)
\(\Rightarrow x=-\frac{5}{6}-\frac{1}{4}\)
\(\Rightarrow x=-\frac{13}{12}\)
\(\frac{-5}{9}-\frac{-5}{12}\)
= \(\frac{-20}{36}-\frac{-15}{36}\)
= \(\frac{-5}{36}\)
Tìm x:
\(\frac{-5}{6}-x=\frac{7}{12}+\frac{-1}{3}\)
\(\frac{-5}{6}-x=\frac{7}{12}+\frac{-4}{12}\)
\(\frac{-5}{6}-x=\frac{1}{4}\)
\(x=\frac{-5}{6}-\frac{1}{4}\)
\(x=\frac{-10}{12}-\frac{3}{12}\)
\(x=\frac{-13}{12}\)
\(\frac{12}{5}\): x = \(\frac{8}{3}\)
x = \(\frac{8}{3}\): \(\frac{12}{5}\)
x = \(\frac{10}{9}\)
lộn đề