7+23
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\(=\dfrac{7}{23}\left(\dfrac{8}{11}-\dfrac{3}{11}\right)-\dfrac{16}{23}=\dfrac{7}{23}\cdot\dfrac{5}{11}-\dfrac{16}{23}=-\dfrac{141}{253}\)
=-85/23-2/7-7/23+9/7
=(-2/7+9/7)+(-85/23-7/23)
=1+(-92/23=-4)
=-3
=
\(-3-\dfrac{16}{23}-\dfrac{2}{7}-\dfrac{7}{23}+\dfrac{9}{7}\)
\(=-3-\left(\dfrac{16}{23}+\dfrac{7}{23}\right)-\left(\dfrac{2}{7}-\dfrac{9}{7}\right)\)
\(=-3-\dfrac{23}{23}-\dfrac{-7}{7}\)
\(=-3-1-\left(-1\right)\)
\(=-3-1+1\)
\(=-3\)
Ai rảnh mà làm hộ mày, ngu như con chó mới không biết làm
\(A=\frac{7}{3\times13}+\frac{7}{13\times23}+...+\frac{7}{53\times63}\)
\(A=\frac{7}{10}.\left[\left(\frac{1}{3}-\frac{1}{13}\right)+\left(\frac{1}{13}-\frac{1}{23}\right)+....+\left(\frac{1}{53}-\frac{1}{63}\right)\right]\)
\(A=\frac{7}{10}.\left(\frac{1}{3}-\frac{1}{13}+\frac{1}{13}-\frac{1}{23}+....+\frac{1}{53}-\frac{1}{63}\right)\)
\(A=\frac{7}{10}.\left(\frac{1}{3}-\frac{1}{63}\right)\)
\(A=\frac{7}{10}.\frac{20}{63}\)
\(A=\frac{2}{9}\)
7/23.5/29+7/29.18/23-7/29
=(7.5)/(23.29)+7/29.18/23-7/29
=7/29.5/23+7/29.18/23-7/29.1
=7/29.(5/23+18/23-1)
=7/29.(1-1)
=7/29.0
=0
\(\frac{7}{23}\cdot\frac{5}{29}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)
\(=\frac{7}{29}\cdot\frac{5}{23}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)
\(=\frac{7}{29}\cdot\left(\frac{5}{23}+\frac{18}{23}-1\right)\)
\(=\frac{7}{29}\cdot0\)
\(=0\)
Ta có: \(23\dfrac{1}{4}:\left(-\dfrac{3}{7}\right)-23\dfrac{1}{4}:\left(-\dfrac{5}{7}\right)\)
\(=\dfrac{93}{4}\cdot\dfrac{-7}{3}-\dfrac{93}{4}\cdot\dfrac{-7}{5}\)
\(=\dfrac{93}{4}\cdot\left(-\dfrac{7}{3}+\dfrac{7}{5}\right)\)
\(=\dfrac{93}{4}\cdot\dfrac{-14}{15}=-\dfrac{217}{10}\)
Bn hâm mộ lewandoski à? Ghi 41 bàn ở mùa giải 2020 - 2021 đó
=30 bạn ạ
\(7+23=30\)
k mk mk k lại cho bn