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\(a)\frac{9}{4}\times y=\left[\frac{5}{7}-\frac{3}{14}\right]\times\frac{4}{7}\)
\(\Rightarrow\frac{9}{4}\times y=\left[\frac{10}{14}-\frac{3}{14}\right]\times\frac{4}{7}\)
\(\Rightarrow\frac{9}{4}\times y=\frac{1}{2}\times\frac{4}{7}\)
\(\Rightarrow\frac{9}{4}\times y=\frac{2}{7}\)
\(\Rightarrow y=\frac{2}{7}:\frac{9}{4}=\frac{8}{63}\)
b, Tương tự câu a
8,3 . 7,9 + 8,3 . 2,1
= 8,3 . ( 7,9 + 2,1 )
= 8,3 . 10
= 83
2,5 . 14,5 - 2,5 . 4,5
= 2,5 . ( 14,5 - 4,5 )
= 2,5 . 10
= 25
#Louis
8,3 x 7,9 + 8,3 x 2,1
= 8,3 x ( 7,9 + 2,1 )
= 8,3 x 10
= 83
2,5 x 14,5 - 2,5 x 4,5
= 2,5 x ( 14,5 - 4,5 )
= 2,5 x 10
= 25
Study well ! >_<
a: \(\dfrac{x}{0.9}=\dfrac{5}{6}\)
\(\Leftrightarrow x=\dfrac{3}{4}\)
b: \(\dfrac{-6}{x}=\dfrac{9}{-15}\)
\(\Leftrightarrow x=10\)
c: \(\dfrac{\dfrac{14}{15}}{\dfrac{9}{10}}=\dfrac{x}{\dfrac{3}{7}}\)
\(\Leftrightarrow x=\dfrac{3}{7}\cdot\dfrac{14}{15}:\dfrac{9}{10}=\dfrac{2}{5}\cdot\dfrac{10}{9}=\dfrac{20}{45}=\dfrac{4}{9}\)
a 9/15 x y = (5/7 +3/14) x 4/7
9/15 x y = 13/14 x 4/7
9/15 x y = 26/49
y= 26/49 : 9/15
y= 130/147
b, y : 0,25 = (2,5-1,3) : 0,75
y : 1/4 = 8/5
y= 8/5 x 1/4 = 2/5
a/
9/14 x y = (5/7 + 3/14) x 4/7
9/14 x y = 13/14 x 4/7
9/14 x y = 26/49
y = 26/49 : 9/14
y = 52/63
b/
y : 0,25= (2,5 - 1,3) : 0,75
y : 0,25= 1,2 : 0,75
y : 0,25= 1,6
y = 1,6 x 0,25
y = 0,4
chúc học tốt nhé!!! học giỏi !!!
\(\frac{7}{8}x-\frac{1}{4}x=\frac{9}{16}\)
\(\Rightarrow\left(\frac{7}{8}-\frac{1}{4}\right)x=\frac{9}{16}\)
\(\Rightarrow\left(\frac{7}{8}-\frac{2}{8}\right)x=\frac{9}{16}\)
\(\Rightarrow\frac{5}{8}x=\frac{9}{16}\)
\(\Rightarrow x=\frac{9}{16}:\frac{5}{8}\)
\(\Rightarrow x=\frac{9}{16}.\frac{8}{5}\)
\(\Rightarrow x=\frac{9}{10}\)
\(x:\frac{14}{5}=-2,5\)
\(\Rightarrow x:\frac{14}{5}=-\frac{5}{2}\)
\(\Rightarrow x=-\frac{5}{2}.\frac{14}{5}\)
\(\Rightarrow x=-7\)
Chúc bạn học tốt !!!
a, \(-2,5\%-\left[1-\left(\frac{2}{3}\right)^2\right]+\left(1-\frac{4}{9}\right)\\ =\frac{-1}{40}-\left[1-\frac{4}{9}\right]+\left(1-\frac{4}{9}\right)\\ =\frac{-1}{40}+\left[\left(1-\frac{4}{9}\right)-\left(1-\frac{4}{9}\right)\right]\\ =\frac{-1}{40}+0\\ =\frac{-1}{40}\)
b, \(5\frac{1}{2}-14\frac{3}{7}:\frac{9}{13}-3\frac{4}{7}:\frac{9}{13}\\ =5\frac{1}{2}-\left(14\frac{3}{7}:\frac{9}{13}+3\frac{4}{7}:\frac{9}{13}\right)\\ =5\frac{1}{2}-\left[\left(14\frac{3}{7}+3\frac{4}{7}\right):\frac{9}{13}\right]\\ =5\frac{1}{2}-\left(18:\frac{9}{13}\right)\\ =5\frac{1}{2}-\left(18\cdot\frac{13}{9}\right)\\ =\frac{11}{2}-26\\ =\frac{-41}{2}\)
c, \(\left(1+2\frac{1}{4}-3\frac{1}{3}\right):\left(1+3\frac{1}{2}-4\frac{7}{12}\right)\\ =\left(3\frac{1}{4}-3\frac{1}{3}\right):\left(4\frac{1}{2}-4\frac{7}{12}\right)\\ =\frac{-1}{12}:\frac{-1}{12}\\ =1\)
\(a,\frac{9}{14}\cdot y=\left[\frac{5}{7}-\frac{3}{14}\right]\cdot\frac{4}{7}\)
\(\Rightarrow\frac{9}{14}\cdot y=\left[\frac{10}{14}-\frac{3}{14}\right]\cdot\frac{4}{7}\)
\(\Rightarrow\frac{9}{14}\cdot y=\frac{1}{2}\cdot\frac{4}{7}\)
\(\Rightarrow\frac{9}{14}\cdot y=\frac{2}{7}\)
\(\Rightarrow y=\frac{2}{7}:\frac{9}{14}=\frac{2}{7}\cdot\frac{14}{9}=\frac{2}{1}\cdot\frac{2}{9}=\frac{4}{9}\)
\(\Leftrightarrow y=\frac{4}{9}\)
b, tương tự
-2,5xX=9/14 : (-24/7)
-2,5xX=-3/16
x=-3/16:(-2,5)
x=3/40
`Answer:`
\(\left(-2,5-x\right)\left(-2\frac{4}{7}\right)=\frac{9}{14}\)
\(\Leftrightarrow\left(-2,5-x\right)\left(-\frac{18}{7}\right)=\frac{9}{14}\)
\(\Leftrightarrow-2,5-x=\frac{9}{14}:\left(-\frac{18}{7}\right)\)
\(\Leftrightarrow-2,5-x=-\frac{1}{4}\)
\(\Leftrightarrow x=-2,5-\left(-\frac{1}{4}\right)\)
\(\Leftrightarrow x=-\frac{9}{4}\)