X + 5/4 = 3/.6 x5
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\(\dfrac{22}{5}\times\dfrac{6}{121}\times\dfrac{11}{4}\times\dfrac{3}{5}\times\dfrac{1}{3}\times\dfrac{5}{4}\)
\(=\left(\dfrac{22}{5}\times\dfrac{5}{4}\right)\times\left(\dfrac{6}{121}\times\dfrac{11}{4}\right)\times\left(\dfrac{3}{5}\times\dfrac{1}{3}\right)\)
\(=\dfrac{11}{2}\times\dfrac{3}{22}\times\dfrac{1}{5}\)
\(=\dfrac{3}{20}\)
\(=\dfrac{22\times6\times11\times3\times1\times5}{5\times121\times4\times5\times3\times4}=\dfrac{11\times2\times6\times11\times1}{11\times11\times4\times5\times4}=\dfrac{2\times6\times1}{4\times5\times4}=\dfrac{18}{100}=\dfrac{9}{50}\)
1) = \(\frac{3}{5}\)
2) =\(\frac{6}{7}\)
3)\(\frac{9}{13}\)
4)\(\frac{4}{13}\)
b. Ta có:
A(x) + B(x) = x2 + 2x + 1 + x2 + 1 = 2x2 + 2x + 2 (0.5 điểm)
A(x) - B(x) = x2 + 2x + 1 - (x2 + 1) = 2x (0.5 điểm)
\(\left(\frac{3}{5}-x\right)+\frac{13}{20}=\frac{5}{6}\)
\(\frac{3}{5}-x=\frac{5}{6}-\frac{13}{20}\)
\(\frac{3}{5}-x=\frac{11}{60}\)
\(x=\frac{3}{5}-\frac{11}{60}\)
\(x=\frac{5}{12}\)
\(\left(x-\frac{1}{2}\right)\cdot\frac{5}{3}=\frac{7}{4}-\frac{1}{2}\)
\(\left(x-\frac{1}{2}\right)\cdot\frac{5}{3}=\frac{5}{4}\)
\(x-\frac{1}{2}=\frac{5}{4}:\frac{5}{3}\)
\(x-\frac{1}{2}=\frac{3}{4}\)
\(x=\frac{3}{4}+\frac{1}{2}\)
\(x=\frac{5}{4}\)
( 3/5 - x ) + 13/20 = 5/6
3/5 - x = 5/6 - 13/20
3/5 - x = 89/60
x = 3/5 - 89/60
x = 25/12
( x - 1/2 ) x 5/3 = 7/4 - 1/2
( x - 1/2 ) x 5/3 = 5/4
x - 1/2 = 5/4 : 5/3
x - 1/2 = 35/12
x = 35/12 + 1/2
x = 41/12
c: Ta có: \(\left|x+\dfrac{5}{6}\right|:\dfrac{4}{5}=\dfrac{3}{8}\)
\(\Leftrightarrow\left|x+\dfrac{5}{6}\right|=\dfrac{3}{8}\cdot\dfrac{4}{5}=\dfrac{3}{10}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{5}{6}=\dfrac{3}{10}\\x+\dfrac{5}{6}=-\dfrac{3}{10}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-8}{15}\\x=-\dfrac{17}{15}\end{matrix}\right.\)
x + \(\frac{5}{4}\)= \(\frac{3}{6}\)x 5
x + \(\frac{5}{4}\)= 2,5
x = 2,5 - \(\frac{5}{4}\)
x = 1,25
quát đè heo