1 Tinh nhanh
1212/4343*868686/545454*27/12
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bài 2
a] = 3 x \(\frac{4343}{7171}\)= \(\frac{17372}{7171}\)= \(\frac{172}{71}\)
b] = \(\frac{1}{33}\)x \(\frac{44}{7}\)= \(\frac{1}{3}\)x \(\frac{4}{7}\)=\(\frac{4}{21}\)
bài 1
a] y là 9
b] <=> 64y + 36y = 700 - 75 - 225
<=> 100y = 400
<=> y = 4
trên lớp cô sửa rồi nên mình giải luôn:
1) Tìm y
a) y3 + 3y = 12 x 11
y3 + 3y = 132
y x 10 + 3 + 3 x 10 + y = 132
( y x 10 + y ) + ( 3 x 10 + 3 ) = 132
11 x y + 33 = 132
11 x y = 132 - 33
11 x y = 99
y = 99 : 11
y = 9
b) 64 x y + 225 = 700 - 75 - 36 x y
64 x y + 225 = 625 - 36 x y
64 x y + 36 x y = 625 -225
64 x y + 36 x y = 400
( 64 + 36 ) x y = 400
100 x y = 400
y = 400 : 100
y = 4
2) Tính
a) \(\frac{4343}{7171}+\frac{4343}{7171}+\frac{4343}{7171}+\frac{4343}{7171}\)
\(=\frac{4343}{7171}\times4\)
\(=\frac{43}{71}\times4\)
\(=\frac{172}{71}\)
b) A = \(\frac{1}{33}\times\left(\frac{33}{12}+\frac{3333}{2020}+\frac{333333}{303030}+\frac{33333333}{42424242}\right)\)
Ta có:
\(\frac{3333}{2020}=\frac{3333:101}{2020:101}=\frac{33}{20}\)
\(\frac{333333}{303030}=\frac{333333:10101}{303030:10101}=\frac{33}{30}\)
\(\frac{33333333}{42424242}=\frac{33333333:1010101}{42424242:1010101}=\frac{33}{42}\)
A = \(\frac{1}{33}\times\left(\frac{33}{12}+\frac{33}{20}+\frac{33}{30}+\frac{33}{42}\right)\)
A = \(\frac{1}{33}\times33\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)\)
A = 1 x \(\left(\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)\)
A = 1 x \(\left(\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}+\frac{1}{6x7}\right)\)
A = 1 x \(\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\right)\)
A = 1 x \(\left(\frac{1}{3}-\frac{1}{7}\right)\)
A = 1 x \(\left(\frac{7}{21}-\frac{3}{21}\right)\)
A = 1 x \(\frac{4}{21}\)
A = \(\frac{4}{21}\)
\(=\dfrac{12}{21}\cdot\dfrac{165}{143}\cdot\dfrac{1993}{1995}\)
\(=\dfrac{4}{7}\cdot\dfrac{15}{13}\cdot\dfrac{1993}{1995}=\dfrac{1993}{13}\cdot\dfrac{4}{931}=\dfrac{7972}{12103}\)
a, \(\dfrac{15\times14-1}{13\times15+14}\)
= \(\dfrac{15\times\left(13+1\right)-1}{13\times15+14}\)
= \(\dfrac{13\times15+15-1}{13\times15+14}\)
= \(\dfrac{13\times15+14}{13\times15+14}\)
= 1
c, \(\dfrac{1+2+3+4+5+6+7+8+9}{10}\)
= \(\dfrac{\left(9+1\right)\times\left\{\left(9-1\right):1+1\right\}:2}{10}\)
= \(\dfrac{10\times9:2}{10}\)
= \(\dfrac{9}{2}\)
câu 1 :chọn câu hỏi đúng nhất.
wasn't there any lettuce ? (negative)
was there any lettuce ? (negative )
were there any lettuce ? (negative)
weren't there any lettuce ? (negative )
câu 2 :chọn câu hỏi đúng nhất
was there any gas in the car ? (negative )
wasn't there any gas in the car ? (negative)
weren't there any gas in the car ? (negative)
were there any gas in the car ?
a) \(\frac{27.45+55.27}{2+4+6+8+...+16+18}=\frac{27.\left(45+55\right)}{\left(2+18\right)+\left(16+4\right)+\left(14+6\right)+\left(12+8\right)}\)
\(=\frac{27.100}{20+20+20+20}=\frac{2700}{20.4}=\frac{2700}{80}=\frac{135}{4}\)
b) Lười
Làm giống câu a nhé
Gọi số bị chia và số chia lần lượt là a, b
Ta có: a : b = 153
3a : b = 153. 3= 459
Vậy thương mới là 459
k dùm nha
a)48.45+55.48=(45+55).48=100.48=4800
b)57.37+57.23+57.40=57.(23+37+40)=57.100=5700
c)25.5.4.17.2=(25.4).(5.17.2)=100.170=17000
d)127.45+55.127-27.100=127.(45+55)-(27.100)=127.100-27.100=(127-27).100=100.100=10000
e)543+165+457+35=(543+457)+(165+35)=1000+200=1200
g)13.58.4+32.6.2+52.10=(52.58)+(52.32)+52.10=52.(58+32+10)=52.100=5200
h)25.5.4.17.2=(25.4).(17.2.5)=100.170=17000
k)(3737.43-4343.37):(2+4+6+...+100)=(37.101.43-43.101.37):(2+4+6+...+100)=0.(2+4+6+...+100)=0
i)1+5+9+...+29+33+37=(1+37)+(5+33)+...=190
a=4800
b=5700
c=17000
d=10000
e=1200
...
phần còn lại bạn tự làm nhé
\(\frac{1212}{4343}\cdot\frac{868686}{545454}\cdot\frac{27}{12}=\frac{12}{43}\cdot\frac{43}{27}\cdot\frac{9}{4}=\frac{12\cdot43\cdot9}{43\cdot27\cdot4}=\frac{3\cdot1}{3\cdot1}=1\)