6+3
3+6
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\(\frac{33-33:\frac{11}{6}}{\frac{6}{11}}\)
\(=\frac{33-33\cdot\frac{6}{11}}{\frac{6}{11}}\)
\(=\frac{33-33\cdot1}{1}\)
\(=33-33=0\)
Bài này chắc rút gọn
\(\sqrt{15-6\sqrt{6}}+\sqrt{33-12\sqrt{6}}\)
\(=\sqrt{3^2+2.3\sqrt{6}+\left(\sqrt{6}\right)^2}+\sqrt{3^2-2.3.2\sqrt{6}+\left(2\sqrt{6}\right)^2}\)
\(=\sqrt{\left(3-\sqrt{6}\right)^2}+\sqrt{\left(3-2\sqrt{6}\right) ^2}=3-\sqrt{6}+2\sqrt{6}-3\)
\(=\sqrt{6}\)
\(\sqrt{15-6\sqrt{6}}+\sqrt{33-12\sqrt{6}}\)
\(=\sqrt{9+6-2.3.\sqrt{6}}+\sqrt{9+24-2.3.2\sqrt{6}}\)
\(=\sqrt{\left(3-\sqrt{6}\right)^2}+\sqrt{\left(3-2\sqrt{6}\right)^2}\)
\(=3-\sqrt{6}-3+2\sqrt{6}=\sqrt{6}\)
\(\sqrt{15-6\sqrt{6}}+\sqrt{33-12\sqrt{6}}\)
\(=\sqrt{15-2.3\sqrt{6}}+\sqrt{33-2.6\sqrt{6}}\)
\(=\sqrt{15-2\sqrt{54}}+\sqrt{33-2\sqrt{216}}\)
\(=\sqrt{9-2\sqrt{6}\sqrt{9}+6}+\sqrt{24-2\sqrt{24}\sqrt{9}+\sqrt{9}}\)
\(=3-\sqrt{6}+\sqrt{24}-3\)
\(=\sqrt{24}-\sqrt{6}\)
\(=\sqrt{6}\)
\(\frac{\frac{6}{13}-\frac{6}{23}+\frac{6}{33}-\frac{6}{43}}{\frac{5}{13}-\frac{5}{23}+\frac{5}{33}-\frac{5}{43}}\)
= \(\frac{6.\left(\frac{1}{13}-\frac{1}{23}+\frac{1}{33}-\frac{1}{43}\right)}{5.\left(\frac{1}{13}-\frac{1}{23}+\frac{1}{33}-\frac{1}{43}\right)}\)
= \(\frac{6}{5}\)
k cho mình nhé
7 x 7 x 6 + 6 x 32 + 6 x 33 + 6 x 34
= 49 x 6 + 192 + 198 + 204
= 294 + 192 + 198 + 204
= 888
Mk đầu tiên nha
\(\sqrt{15-6\sqrt{6}}+\sqrt{33-12\sqrt{6}}\)
\(=\sqrt{\left(3-\sqrt{6}\right)^2}+\sqrt{\left(2\sqrt{6}-3\right)^2}\)
\(=3-\sqrt{6}+2\sqrt{6}-3=\sqrt{6}\)
Câu 5:
a: \(31\cdot\left(-18\right)+31\cdot\left(-81\right)-31\)
\(=31\left(-18-81-1\right)\)
\(=31\cdot\left(-100\right)=-3100\)
b: \(\left(-12\right)\cdot47+\left(-12\right)\cdot52+\left(-12\right)\)
\(=\left(-12\right)\left(47+52+1\right)\)
\(=-12\cdot100=-1200\)
c: \(13\cdot\left(23+22\right)-3\cdot\left(17+28\right)\)
\(=13\cdot45-3\cdot45\)
\(=45\cdot10=450\)
d: \(-48+48\left(-78\right)+48\left(-21\right)\)
\(=48\left(-1-78-21\right)\)
\(=48\left(-100\right)=-4800\)
Câu 4:
a: \(\left(-6-2\right)\left(-6+2\right)=\left(-8\right)\cdot\left(-4\right)=32\)
b: \(\dfrac{\left(7\cdot3-3\right)}{-6}=\dfrac{21-3}{-6}=\dfrac{18}{-6}=-3\)
c: \(\left(-5+9\right)\cdot\left(-4\right)=4\cdot\left(-4\right)=-16\)
d: \(\dfrac{72}{-6\cdot2+4}=\dfrac{72}{-12+4}=\dfrac{72}{-8}=-9\)
\(6+3=9\)
\(3+6=9\)
MK TRẢ LỜI ĐẦU TIÊN ĐÓA BẠN !
6+3=9
3+6=9