tìm X:
360:({6xX+4/20)+10}=6
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a) 32 : (3.x - 2) = 8
3x - 2 = 32 : 8
3x - 2 = 4
3x = 4 + 2
3x = 6
x = 6 : 3
x = 2
b) 75 : (x - 18) = 25
x - 18 = 75 : 25
x - 18 = 3
x = 3 + 18
x = 21
c) (15 - 6.x) . 243 = 729
15 - 6x = 729 : 243
15 - 6x = 3
6x = 15 - 3
6x = 12
x = 12 : 6
x = 2
d) 4.(x - 12) + 9 = 17
4(x - 12) = 17 - 9
4(x - 12) = 8
x - 12 = 8 : 4
x - 12 = 2
x = 2 + 12
x = 14
e) 20 - 2.(x + 4) = 4
2(x + 4) = 20 - 4
2(x + 4) = 16
x + 4 = 16 : 2
x + 4 = 8
x = 8 : 2
x = 4
`32: ( 3xx x -2)=8`
`3xx x-2=32:8`
`3xx x-2=4`
`3 xx x=4+2`
`3xx x=6`
`x=6:3`
`x=2`
__
`75 : (x-18) =25`
`x-18=75:25`
`x-18= 3`
`x=3+18`
`x=21`
__
`(15-6 xx x ) xx 243 =729`
`15-6 xx x = 729 : 243`
`15-6 xx x = 3`
`6 xx x=15-3`
`6 xx x=12`
`x=12:6`
`x=2`
__
`4 xx (x-12)+9=17`
`4 xx (x-12)=17-9`
`4 xx (x-12)= 8`
`x-12=8:4`
`x-12=2`
`x=2+12`
`x=14`
__
`20-2xx(x+4)=4`
`2xx(x+4)=20-4`
`2xx(x+4)=16`
`x+4=16:2`
`x+4=8`
`x=8-4`
`x=4`
Tìm số tự nhiên x, biết rằng 162 ⋮ x; 360 ⋮ x và 10 < x < 20 :
A. x = 6
B. x = 9
C. x = 18
D. x = 36
Đáp án là C
Vì 162 ⋮ x; 360 ⋮ x ⇒ x ∈ ƯC (162, 360)
Ta có:
162 = 2. 3 4
360 = 2 3 . 3 2 .5
Suy ra, ƯCLN ( 162, 360) = 2. 3 2 = 18
ƯC ( 162, 360) = Ư (18) = {1, 2, 3, 6, 9, 18} ⇒ x ∈ {1, 2, 3, 6, 9, 18}
Vì 10 < x < 20 ⇒ x = 18
112 - (x+4)=1339:13
112 - (x+4)=103
x+4= 112-103
x+4=9
x=9-4
x=5
_________
468+85xX=2508
85 x X = 2508 - 468
85 x X = 2040
X= 2040 : 85
X=24
____
Xx2,5=2,5x4
X x 2,5 = 10
X= 10:2,5
X=4
________
x-270:45=120
X - 6 = 120
X= 120+6
X=126
575-(6xX)+70=445
(6 x X) + 70 = 575 - 445
(6 x X) + 70= 130
6 x X = 130 - 70
6 x X = 60
X= 60:6
X=10
______
x-105:21=15
X - 5 = 15
X= 15+5
X=20
______
3200:(405-x)=8
405 - x = 3200 : 8
405 - x = 400
x= 405 - 400
x= 5
_______
43575-75xX=42450
75 x X = 43575 - 42450
75 x X = 1125
X= 1125:75
X= 15
______
8,75xX+1,25xX=20
(8,75 + 1,25) x X = 20
10 x X = 20
X=20:10
X=2
a)\(\frac{2}{3}\cdot x+\frac{1}{4}=\frac{5}{6}\)
\(\frac{2}{3}\cdot x=\frac{5}{6}-\frac{1}{4}=\frac{7}{12}\)
\(x=\frac{7}{12}:\frac{2}{3}=\frac{7}{8}\)
b) \(\frac{7}{12}-\frac{5}{6}\cdot x=\frac{1}{4}:\frac{2}{3}\)
\(\frac{7}{12}-\frac{5}{6}\cdot x=\frac{3}{8}\)
\(\frac{5}{6}\cdot x=\frac{7}{12}-\frac{3}{8}=\frac{5}{24}\)
\(x=\frac{5}{24}:\frac{5}{6}=\frac{1}{4}\)
c) \(2\frac{1}{3}-\left(x+1\right)=\frac{5}{9}\)
\(\frac{7}{3}-\left(x+1\right)=\frac{5}{9}\)
\(x+1=\frac{7}{3}-\frac{5}{9}=\frac{16}{9}\)
\(x=\frac{16}{9}-1=\frac{7}{9}\)
d) \(\frac{2\cdot x+1}{15}=\frac{3}{5}\)
\(\left(2\cdot x+1\right):15=\frac{3}{5}\)
\(2\cdot x+1=\frac{3}{5}\cdot15=9\)
\(2\cdot x=9-1=8\)
\(x=8:2=4\)
a, 2/3 . x +1/4=5/6
2/3 . x=5/6-1/4
2/3 . x=10/12 -3/12
2/3 . x=7/12
x= 7/12 : 2/3
x=7/8
Vậy x=7/8
(-360):x+20=-40
=>(-360):x=-40-20=-60
=>360:x=60
=>x=360/60=6