(376 + 320 ) : (x × 3) = 8
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b: =2376-376+3425-42
=2000+3383
=5383
c: =3145-145+246+4246+2347-347
=3000+2000+4492
=9492
e: =(72-72):A=0
a) 612 : (x - 7) + 8 = 59
612 : (x - 7) = 51
x - 7 = 612 : 51 = 12
x = 12 + 7
x = 19
b) 2016 - ( 2+4+6+8....+x)= 376
2 + 4 + 6+ 8 + ... +x = 2016 - 376 = 1640
Áp dụng công thức tính dãy số ta có :
\(\frac{\left[\left(x-2\right):2+1\right].\left(x+2\right)}{2}=1640\)
\(\Rightarrow\left(\frac{x-2}{2}+1\right).\left(x+2\right)=3280\)
\(\Rightarrow\frac{x}{2}.\left(x+2\right)=3280\)
\(\Rightarrow\frac{x^2}{2}+x=3280\)
\(\Rightarrow\frac{x^2}{2}+\frac{2x}{2}=3280\)
\(\Rightarrow x^2+2x=6560\)
=> x . (x+2) = 6560
=> x = 80
376 x 29 + 70 x 376 + 376
= 376 x 29 + 70 x 376 + 376 x 1
= 376 x (29 + 70 + 1)
= 376 x 100
= 37600
Sửa đề:
376 × 29 + 70 × 376 + 376
= 376 × (29 + 70 + 1)
= 376 × 100
= 37600
dẫu . là dấu nhân nha mn.
mong mn giải giúp mình mình đang cần gấp
376 x 29 + 70 x 376 + 376
= 376 x 29 + 70 x 376 + 376 x 1
= 376 x (29 + 70 + 1)
= 376 x 100
= 37600
Sửa đề:
376 × 29 + 70 × 376 + 376
= 376 × (29 + 70 + 1)
= 376 × 100
= 37600
Bài 1:
a) \(\dfrac{9}{20}-\dfrac{8}{15}\times\dfrac{5}{12}\)
\(=\dfrac{9}{20}-\dfrac{2}{9}\)
\(=\dfrac{41}{180}\)
b) \(\dfrac{2}{3}\div\dfrac{4}{5}\div\dfrac{7}{12}\)
\(=\dfrac{2}{3}\times\dfrac{5}{4}\times\dfrac{12}{7}\)
\(=\dfrac{5}{6}\times\dfrac{12}{7}\)
\(=\dfrac{10}{7}\)
c) \(\dfrac{7}{9}\times\dfrac{1}{3}+\dfrac{7}{9}\times\dfrac{2}{3}\)
\(=\dfrac{7}{9}\times\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\)
\(=\dfrac{7}{9}\times1\)
\(=\dfrac{7}{9}\)
Bài 2:
a) \(2\times\left(x-1\right)=4026\)
\(\left(x-1\right)=4026\div2\)
\(x-1=2013\)
\(x=2014\)
Vậy: \(x=2014\)
b) \(x\times3,7+6,3\times x=320\)
\(x\times\left(3,7+6,3\right)=320\)
\(x\times10=320\)
\(x=320\div10\)
\(x=32\)
Vậy: \(x=32\)
c) \(0,25\times3< 3< 1,02\)
\(\Leftrightarrow0,75< 3< 1,02\) ( S )
=> \(0,75< 1,02< 3\)
1/3 x 46 +2/3x37 3,2x (95x10) +(8x4)x 187 -(32x 10) x 8,2
=(1/3+2/3) x (46+37) 32x95+32x 187- 32x 82
= 1x 100 32x( 95+187-82)
= 100 = 32 x200
= 6400
\(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x\left(x+3\right)}=\frac{125}{376}\)
=>\(3\left(\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{x\left(x+3\right)}\right)=3.\frac{125}{376}\)
=>\(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{x\left(x+3\right)}=\frac{375}{376}\)
=>\(\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{x}-\frac{1}{x+3}=\frac{375}{376}\)
=>\(1-\frac{1}{x+3}=\frac{375}{376}\)
=>\(\frac{1}{x+3}=1-\frac{375}{376}\)
=>\(\frac{1}{x+3}=\frac{1}{376}\)
=>x+3=376
=>x=376-3
=>x=373
Vậy x=373
( 376 + 320 ) : ( X x 3 ) = 8
696 : X x 3 = 8
X x 3 = 696 : 8
X x 3 = 87
X = 87 : 3
X = 29
qqqqqqq